我使用这个函数

function getDatesRange(startDate, stopDate) {
    const ONE_DAY = 24*3600*1000;
    var days= [];
    var currentDate = new Date(startDate);
    while (currentDate <= stopDate) {
        days.push(new Date (currentDate));
        currentDate = currentDate - 1 + 1 + ONE_DAY;
    }
    return days;
}

@softvar的解决方案，但随后包括工作日期选项

/**
 * Returns array of working days between two dates.
 *
 * @param {string} startDate
 *   The start date in yyyy-mm-dd format.
 * @param {string} endDate
 *   The end date in yyyy-mm-dd format.
 * @param {boolean} onlyWorkingDays
 *   If true only working days are returned. Default: false
 *
 * @return {array}
 *   Array of dates in yyyy-mm-dd string format.
 */
function getDates(startDate, stopDate, onlyWorkingDays) {
  let doWd = typeof onlyWorkingDays ==='undefined' ? false : onlyWorkingDays;

  let dateArray = [];  
  let dayNr;
  let runDateObj = moment(startDate);  
  let stopDateObj = moment(stopDate);

  while (runDateObj <= stopDateObj) {
    dayNr = runDateObj.day();
    if (!doWd || (dayNr>0 && dayNr<6)) {
     dateArray.push(moment(runDateObj).format('YYYY-MM-DD'));  
    }

    runDateObj = moment(runDateObj).add(1, 'days');
  }
  return dateArray;
}

这是另外几行使用date-fns库的解决方案:

const {format, differenceInDays, addDays} = dateFns; const getRangeDates = (startDate, endDate) => { const days = differenceInDays(endDate, startDate); console.log([…数组(天+ 1). keys ()] . map ((i) = >格式(addDays (startDate可以,我),YYYY-MM-DD))); }; getRangeDates (' 2021-06-01 ', ' 2021-06-05 '); < script src = " https://cdnjs.cloudflare.com/ajax/libs/date-fns/1.30.1/date_fns.js " > < /脚本>

功能:

  var dates = [],
      currentDate = startDate,
      addDays = function(days) {
        var date = new Date(this.valueOf());
        date.setDate(date.getDate() + days);
        return date;
      };
  while (currentDate <= endDate) {
    dates.push(currentDate);
    currentDate = addDays.call(currentDate, 1);
  }
  return dates;
};

用法:

var dates = getDatesRange(new Date(2019,01,01), new Date(2019,01,25));                                                                                                           
dates.forEach(function(date) {
  console.log(date);
});

希望对你有所帮助

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

我最近在用moment.js工作，下面做了一个戏法。

function getDateRange(startDate, endDate, dateFormat) {
        var dates = [],
            end = moment(endDate),
            diff = endDate.diff(startDate, 'days');

        if(!startDate.isValid() || !endDate.isValid() || diff <= 0) {
            return;
        }

        for(var i = 0; i < diff; i++) {
            dates.push(end.subtract(1,'d').format(dateFormat));
        }

        return dates;
    };
    console.log(getDateRange(startDate, endDate, dateFormat));

结果将是:

["09/03/2015", "10/03/2015", "11/03/2015", "12/03/2015", "13/03/2015", "14/03/2015", "15/03/2015", "16/03/2015", "17/03/2015", "18/03/2015"]