D3js提供了很多方便的函数，包括d3。是时候简单地处理日期了

https://github.com/d3/d3-time

针对您的具体要求:

Utc

var range = d3.utcDay.range(new Date(), d3.utcDay.offset(new Date(), 7));

或当地时间

var range = d3.timeDay.range(new Date(), d3.timeDay.offset(new Date(), 7));

Range将是一个日期对象数组，它位于每一天的第一个可能值上

您可以将timeDay更改为timeHour, timmonth等，在不同的间隔上获得相同的结果

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

试试这个，记得加上moment js，

function getDates(startDate, stopDate) {
    var dateArray = [];
    var currentDate = moment(startDate);
    var stopDate = moment(stopDate);
    while (currentDate <= stopDate) {
        dateArray.push( moment(currentDate).format('YYYY-MM-DD') )
        currentDate = moment(currentDate).add(1, 'days');
    }
    return dateArray;
}

@softvar的解决方案，但随后包括工作日期选项

/**
 * Returns array of working days between two dates.
 *
 * @param {string} startDate
 *   The start date in yyyy-mm-dd format.
 * @param {string} endDate
 *   The end date in yyyy-mm-dd format.
 * @param {boolean} onlyWorkingDays
 *   If true only working days are returned. Default: false
 *
 * @return {array}
 *   Array of dates in yyyy-mm-dd string format.
 */
function getDates(startDate, stopDate, onlyWorkingDays) {
  let doWd = typeof onlyWorkingDays ==='undefined' ? false : onlyWorkingDays;

  let dateArray = [];  
  let dayNr;
  let runDateObj = moment(startDate);  
  let stopDateObj = moment(stopDate);

  while (runDateObj <= stopDateObj) {
    dayNr = runDateObj.day();
    if (!doWd || (dayNr>0 && dayNr<6)) {
     dateArray.push(moment(runDateObj).format('YYYY-MM-DD'));  
    }

    runDateObj = moment(runDateObj).add(1, 'days');
  }
  return dateArray;
}

Date.prototype.addDays = function(days) {
    var date = new Date(this.valueOf());
    date.setDate(date.getDate() + days);
    return date;
}

function getDates(startDate, stopDate) {
    var dateArray = new Array();
    var currentDate = startDate;
    while (currentDate <= stopDate) {
        dateArray.push(new Date (currentDate));
        currentDate = currentDate.addDays(1);
    }
    return dateArray;
}

这里是一个功能演示http://jsfiddle.net/jfhartsock/cM3ZU/

Generate an array of years: const DAYS = () => { const days = [] const dateStart = moment() const dateEnd = moment().add(30, ‘days') while (dateEnd.diff(dateStart, ‘days') >= 0) { days.push(dateStart.format(‘D')) dateStart.add(1, ‘days') } return days } console.log(DAYS()) Generate an arrays for month: const MONTHS = () => { const months = [] const dateStart = moment() const dateEnd = moment().add(12, ‘month') while (dateEnd.diff(dateStart, ‘months') >= 0) { months.push(dateStart.format(‘M')) dateStart.add(1, ‘month') } return months } console.log(MONTHS()) Generate an arrays for days: const DAYS = () => { const days = [] const dateStart = moment() const dateEnd = moment().add(30, ‘days') while (dateEnd.diff(dateStart, ‘days') >= 0) { days.push(dateStart.format(‘D')) dateStart.add(1, ‘days') } return days } console.log(DAYS())