var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
当前回答
D3js提供了很多方便的函数,包括d3。是时候简单地处理日期了
https://github.com/d3/d3-time
针对您的具体要求:
Utc
var range = d3.utcDay.range(new Date(), d3.utcDay.offset(new Date(), 7));
或当地时间
var range = d3.timeDay.range(new Date(), d3.timeDay.offset(new Date(), 7));
Range将是一个日期对象数组,它位于每一天的第一个可能值上
您可以将timeDay更改为timeHour, timmonth等,在不同的间隔上获得相同的结果
其他回答
var boxingDay = new Date("12/26/2010");
var nextWeek = boxingDay*1 + 7*24*3600*1000;
function getDates( d1, d2 ){
var oneDay = 24*3600*1000;
for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
d.push( new Date(ms) );
}
return d;
}
getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)
试试这个,记得加上moment js,
function getDates(startDate, stopDate) {
var dateArray = [];
var currentDate = moment(startDate);
var stopDate = moment(stopDate);
while (currentDate <= stopDate) {
dateArray.push( moment(currentDate).format('YYYY-MM-DD') )
currentDate = moment(currentDate).add(1, 'days');
}
return dateArray;
}
@softvar的解决方案,但随后包括工作日期选项
/**
* Returns array of working days between two dates.
*
* @param {string} startDate
* The start date in yyyy-mm-dd format.
* @param {string} endDate
* The end date in yyyy-mm-dd format.
* @param {boolean} onlyWorkingDays
* If true only working days are returned. Default: false
*
* @return {array}
* Array of dates in yyyy-mm-dd string format.
*/
function getDates(startDate, stopDate, onlyWorkingDays) {
let doWd = typeof onlyWorkingDays ==='undefined' ? false : onlyWorkingDays;
let dateArray = [];
let dayNr;
let runDateObj = moment(startDate);
let stopDateObj = moment(stopDate);
while (runDateObj <= stopDateObj) {
dayNr = runDateObj.day();
if (!doWd || (dayNr>0 && dayNr<6)) {
dateArray.push(moment(runDateObj).format('YYYY-MM-DD'));
}
runDateObj = moment(runDateObj).add(1, 'days');
}
return dateArray;
}
Date.prototype.addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
}
function getDates(startDate, stopDate) {
var dateArray = new Array();
var currentDate = startDate;
while (currentDate <= stopDate) {
dateArray.push(new Date (currentDate));
currentDate = currentDate.addDays(1);
}
return dateArray;
}
这里是一个功能演示http://jsfiddle.net/jfhartsock/cM3ZU/
Generate an array of years: const DAYS = () => { const days = [] const dateStart = moment() const dateEnd = moment().add(30, ‘days') while (dateEnd.diff(dateStart, ‘days') >= 0) { days.push(dateStart.format(‘D')) dateStart.add(1, ‘days') } return days } console.log(DAYS()) Generate an arrays for month: const MONTHS = () => { const months = [] const dateStart = moment() const dateEnd = moment().add(12, ‘month') while (dateEnd.diff(dateStart, ‘months') >= 0) { months.push(dateStart.format(‘M')) dateStart.add(1, ‘month') } return months } console.log(MONTHS()) Generate an arrays for days: const DAYS = () => { const days = [] const dateStart = moment() const dateEnd = moment().add(30, ‘days') while (dateEnd.diff(dateStart, ‘days') >= 0) { days.push(dateStart.format(‘D')) dateStart.add(1, ‘days') } return days } console.log(DAYS())