var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
当前回答
D3js提供了很多方便的函数,包括d3。是时候简单地处理日期了
https://github.com/d3/d3-time
针对您的具体要求:
Utc
var range = d3.utcDay.range(new Date(), d3.utcDay.offset(new Date(), 7));
或当地时间
var range = d3.timeDay.range(new Date(), d3.timeDay.offset(new Date(), 7));
Range将是一个日期对象数组,它位于每一天的第一个可能值上
您可以将timeDay更改为timeHour, timmonth等,在不同的间隔上获得相同的结果
其他回答
这可能会帮助到一些人,
您可以从中获得行输出,并根据需要格式化row_date对象。
var from_date = '2016-01-01';
var to_date = '2016-02-20';
var dates = getDates(from_date, to_date);
console.log(dates);
function getDates(from_date, to_date) {
var current_date = new Date(from_date);
var end_date = new Date(to_date);
var getTimeDiff = Math.abs(current_date.getTime() - end_date.getTime());
var date_range = Math.ceil(getTimeDiff / (1000 * 3600 * 24)) + 1 ;
var weekday = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
var dates = new Array();
for (var i = 0; i <= date_range; i++) {
var getDate, getMonth = '';
if(current_date.getDate() < 10) { getDate = ('0'+ current_date.getDate());}
else{getDate = current_date.getDate();}
if(current_date.getMonth() < 9) { getMonth = ('0'+ (current_date.getMonth()+1));}
else{getMonth = current_date.getMonth();}
var row_date = {day: getDate, month: getMonth, year: current_date.getFullYear()};
var fmt_date = {weekDay: weekday[current_date.getDay()], date: getDate, month: months[current_date.getMonth()]};
var is_weekend = false;
if (current_date.getDay() == 0 || current_date.getDay() == 6) {
is_weekend = true;
}
dates.push({row_date: row_date, fmt_date: fmt_date, is_weekend: is_weekend});
current_date.setDate(current_date.getDate() + 1);
}
return dates;
}
https://gist.github.com/pranid/3c78f36253cbbc6a41a859c5d718f362.js
var boxingDay = new Date("12/26/2010");
var nextWeek = boxingDay*1 + 7*24*3600*1000;
function getDates( d1, d2 ){
var oneDay = 24*3600*1000;
for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
d.push( new Date(ms) );
}
return d;
}
getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)
功能:
var dates = [],
currentDate = startDate,
addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
};
while (currentDate <= endDate) {
dates.push(currentDate);
currentDate = addDays.call(currentDate, 1);
}
return dates;
};
用法:
var dates = getDatesRange(new Date(2019,01,01), new Date(2019,01,25));
dates.forEach(function(date) {
console.log(date);
});
希望对你有所帮助
Date.prototype.addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
}
function getDates(startDate, stopDate) {
var dateArray = new Array();
var currentDate = startDate;
while (currentDate <= stopDate) {
dateArray.push(new Date (currentDate));
currentDate = currentDate.addDays(1);
}
return dateArray;
}
这里是一个功能演示http://jsfiddle.net/jfhartsock/cM3ZU/
我看了上面所有的。最后我自己开始写作。你不需要花时间。原生的for循环就足够了,而且最有意义,因为for循环的存在是为了计算一个范围内的值。
一个衬套:
var getDaysArray = function(s,e) {for(var a=[],d=new Date(s);d<=new Date(e);d.setDate(d.getDate()+1)){ a.push(new Date(d));}return a;};
长版本
var getDaysArray = function(start, end) {
for(var arr=[],dt=new Date(start); dt<=new Date(end); dt.setDate(dt.getDate()+1)){
arr.push(new Date(dt));
}
return arr;
};
列出中间的日期:
var daylist = getDaysArray(new Date("2018-05-01"),new Date("2018-07-01"));
daylist.map((v)=>v.toISOString().slice(0,10)).join("")
/*
Output:
"2018-05-01
2018-05-02
2018-05-03
...
2018-06-30
2018-07-01"
*/
从过去日期到现在的日子:
var daylist = getDaysArray(new Date("2018-05-01"),new Date());
daylist.map((v)=>v.toISOString().slice(0,10)).join("")