var range = getDates(new Date(), new Date().addDays(7));

我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。

诀窍在于它还应该处理月份和年份的边界。


当前回答

这可能会帮助到一些人,

您可以从中获得行输出,并根据需要格式化row_date对象。

var from_date = '2016-01-01';
var to_date = '2016-02-20';

var dates = getDates(from_date, to_date);

console.log(dates);

function getDates(from_date, to_date) {
  var current_date = new Date(from_date);
  var end_date     = new Date(to_date);

  var getTimeDiff = Math.abs(current_date.getTime() - end_date.getTime());
  var date_range = Math.ceil(getTimeDiff / (1000 * 3600 * 24)) + 1 ;

  var weekday = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
  var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
  var dates = new Array();

  for (var i = 0; i <= date_range; i++) {
     var getDate, getMonth = '';

     if(current_date.getDate() < 10) { getDate = ('0'+ current_date.getDate());}
     else{getDate = current_date.getDate();}

    if(current_date.getMonth() < 9) { getMonth = ('0'+ (current_date.getMonth()+1));}
    else{getMonth = current_date.getMonth();}

    var row_date = {day: getDate, month: getMonth, year: current_date.getFullYear()};
    var fmt_date = {weekDay: weekday[current_date.getDay()], date: getDate, month: months[current_date.getMonth()]};
    var is_weekend = false;
    if (current_date.getDay() == 0 || current_date.getDay() == 6) {
        is_weekend = true;
    }
    dates.push({row_date: row_date, fmt_date: fmt_date, is_weekend: is_weekend});
    current_date.setDate(current_date.getDate() + 1);
 }
 return dates;
}

https://gist.github.com/pranid/3c78f36253cbbc6a41a859c5d718f362.js

其他回答

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

@softvar的解决方案,但随后包括工作日期选项

/**
 * Returns array of working days between two dates.
 *
 * @param {string} startDate
 *   The start date in yyyy-mm-dd format.
 * @param {string} endDate
 *   The end date in yyyy-mm-dd format.
 * @param {boolean} onlyWorkingDays
 *   If true only working days are returned. Default: false
 *
 * @return {array}
 *   Array of dates in yyyy-mm-dd string format.
 */
function getDates(startDate, stopDate, onlyWorkingDays) {
  let doWd = typeof onlyWorkingDays ==='undefined' ? false : onlyWorkingDays;

  let dateArray = [];  
  let dayNr;
  let runDateObj = moment(startDate);  
  let stopDateObj = moment(stopDate);

  while (runDateObj <= stopDateObj) {
    dayNr = runDateObj.day();
    if (!doWd || (dayNr>0 && dayNr<6)) {
     dateArray.push(moment(runDateObj).format('YYYY-MM-DD'));  
    }

    runDateObj = moment(runDateObj).add(1, 'days');
  }
  return dateArray;
}

我看了上面所有的。最后我自己开始写作。你不需要花时间。原生的for循环就足够了,而且最有意义,因为for循环的存在是为了计算一个范围内的值。

一个衬套:

var getDaysArray = function(s,e) {for(var a=[],d=new Date(s);d<=new Date(e);d.setDate(d.getDate()+1)){ a.push(new Date(d));}return a;};

长版本

var getDaysArray = function(start, end) {
    for(var arr=[],dt=new Date(start); dt<=new Date(end); dt.setDate(dt.getDate()+1)){
        arr.push(new Date(dt));
    }
    return arr;
};

列出中间的日期:

var daylist = getDaysArray(new Date("2018-05-01"),new Date("2018-07-01"));
daylist.map((v)=>v.toISOString().slice(0,10)).join("")
/*
Output: 
    "2018-05-01
    2018-05-02
    2018-05-03
    ...
    2018-06-30
    2018-07-01"
*/

从过去日期到现在的日子:

var daylist = getDaysArray(new Date("2018-05-01"),new Date());
daylist.map((v)=>v.toISOString().slice(0,10)).join("")

功能:

  var dates = [],
      currentDate = startDate,
      addDays = function(days) {
        var date = new Date(this.valueOf());
        date.setDate(date.getDate() + days);
        return date;
      };
  while (currentDate <= endDate) {
    dates.push(currentDate);
    currentDate = addDays.call(currentDate, 1);
  }
  return dates;
};

用法:

var dates = getDatesRange(new Date(2019,01,01), new Date(2019,01,25));                                                                                                           
dates.forEach(function(date) {
  console.log(date);
});

希望对你有所帮助

这是一个罐装方法,它将接受Moment日期或字符串或混合作为输入,并生成一个日期数组作为Moment日期。如果不希望将Moment日期作为输出,则更改map()方法返回的内容。

const moment = require('moment');

// ...

/**
 * @param {string|import('moment').Moment} start
 * @param {string|import('moment').Moment} end
 * @returns {import('moment').Moment[]}
 */
const getDateRange = (start, end) => {
  const s = moment.isMoment(start) ? start : moment(start);
  const e = moment.isMoment(end) ? end : moment(end);
  return [...Array(1 + e.diff(s, 'days')).keys()].map(n => moment(s).add(n, 'days'));
};