var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
var range = getDates(new Date(), new Date().addDays(7));
我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。
诀窍在于它还应该处理月份和年份的边界。
当前回答
这可能会帮助到一些人,
您可以从中获得行输出,并根据需要格式化row_date对象。
var from_date = '2016-01-01';
var to_date = '2016-02-20';
var dates = getDates(from_date, to_date);
console.log(dates);
function getDates(from_date, to_date) {
var current_date = new Date(from_date);
var end_date = new Date(to_date);
var getTimeDiff = Math.abs(current_date.getTime() - end_date.getTime());
var date_range = Math.ceil(getTimeDiff / (1000 * 3600 * 24)) + 1 ;
var weekday = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
var dates = new Array();
for (var i = 0; i <= date_range; i++) {
var getDate, getMonth = '';
if(current_date.getDate() < 10) { getDate = ('0'+ current_date.getDate());}
else{getDate = current_date.getDate();}
if(current_date.getMonth() < 9) { getMonth = ('0'+ (current_date.getMonth()+1));}
else{getMonth = current_date.getMonth();}
var row_date = {day: getDate, month: getMonth, year: current_date.getFullYear()};
var fmt_date = {weekDay: weekday[current_date.getDay()], date: getDate, month: months[current_date.getMonth()]};
var is_weekend = false;
if (current_date.getDay() == 0 || current_date.getDay() == 6) {
is_weekend = true;
}
dates.push({row_date: row_date, fmt_date: fmt_date, is_weekend: is_weekend});
current_date.setDate(current_date.getDate() + 1);
}
return dates;
}
https://gist.github.com/pranid/3c78f36253cbbc6a41a859c5d718f362.js
其他回答
这是另外几行使用date-fns库的解决方案:
const {format, differenceInDays, addDays} = dateFns; const getRangeDates = (startDate, endDate) => { const days = differenceInDays(endDate, startDate); console.log([…数组(天+ 1). keys ()] . map ((i) = >格式(addDays (startDate可以,我),YYYY-MM-DD))); }; getRangeDates (' 2021-06-01 ', ' 2021-06-05 '); < script src = " https://cdnjs.cloudflare.com/ajax/libs/date-fns/1.30.1/date_fns.js " > < /脚本>
刚遇到这个问题,最简单的方法就是用moment:
你需要先安装moment和moment-range:
const Moment = require('moment');
const MomentRange = require('moment-range');
const moment = MomentRange.extendMoment(Moment);
const start = moment()
const end = moment().add(2, 'months')
const range = moment.range(start, end)
const arrayOfDates = Array.from(range.by('days'))
console.log(arrayOfDates)
我最近在用moment.js工作,下面做了一个戏法。
function getDateRange(startDate, endDate, dateFormat) {
var dates = [],
end = moment(endDate),
diff = endDate.diff(startDate, 'days');
if(!startDate.isValid() || !endDate.isValid() || diff <= 0) {
return;
}
for(var i = 0; i < diff; i++) {
dates.push(end.subtract(1,'d').format(dateFormat));
}
return dates;
};
console.log(getDateRange(startDate, endDate, dateFormat));
结果将是:
["09/03/2015", "10/03/2015", "11/03/2015", "12/03/2015", "13/03/2015", "14/03/2015", "15/03/2015", "16/03/2015", "17/03/2015", "18/03/2015"]
这是一个罐装方法,它将接受Moment日期或字符串或混合作为输入,并生成一个日期数组作为Moment日期。如果不希望将Moment日期作为输出,则更改map()方法返回的内容。
const moment = require('moment');
// ...
/**
* @param {string|import('moment').Moment} start
* @param {string|import('moment').Moment} end
* @returns {import('moment').Moment[]}
*/
const getDateRange = (start, end) => {
const s = moment.isMoment(start) ? start : moment(start);
const e = moment.isMoment(end) ? end : moment(end);
return [...Array(1 + e.diff(s, 'days')).keys()].map(n => moment(s).add(n, 'days'));
};
我使用moment.js和Twix.js,它们为日期和时间操作提供了非常好的支持
var itr = moment.twix(new Date('2012-01-15'),new Date('2012-01-20')).iterate("days");
var range=[];
while(itr.hasNext()){
range.push(itr.next().toDate())
}
console.log(range);
我在http://jsfiddle.net/Lkzg1bxb/上运行这个程序