var listDate = [];
var startDate ='2017-02-01';
var endDate = '2017-02-10';
var dateMove = new Date(startDate);
var strDate = startDate;

while (strDate < endDate){
  var strDate = dateMove.toISOString().slice(0,10);
  listDate.push(strDate);
  dateMove.setDate(dateMove.getDate()+1);
};
console.log(listDate);

//["2017-02-01", "2017-02-02", "2017-02-03", "2017-02-04", "2017-02-05", "2017-02-06", "2017-02-07", "2017-02-08", "2017-02-09", "2017-02-10"]

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

我一直在使用@Mohammed Safeer的解决方案一段时间，我做了一些改进。在控制器中工作时，使用格式化日期是一种糟糕的做法。Moment ().format()应该仅用于视图中的显示目的。还要记住，moment().clone()确保与输入参数分离，这意味着输入日期不会改变。我强烈建议您在处理日期时使用moment.js。

用法:

提供moment.js日期作为startDate, endDate参数的值 间隔参数为可选参数，默认为“days”。使用.add()方法(moment.js)支持的间隔。详情请点击这里 Total参数在指定以分钟为单位的间隔时非常有用。缺省值为1。

调用:

var startDate = moment(),
    endDate = moment().add(1, 'days');

getDatesRangeArray(startDate, endDate, 'minutes', 30);

功能:

var getDatesRangeArray = function (startDate, endDate, interval, total) {
    var config = {
            interval: interval || 'days',
            total: total || 1
        },
        dateArray = [],
        currentDate = startDate.clone();

    while (currentDate < endDate) {
        dateArray.push(currentDate);
        currentDate = currentDate.clone().add(config.total, config.interval);
    }

    return dateArray;
};

这里有一个不需要任何库的代码行，以防你不想创建另一个函数。只需用变量或日期值替换startDate(在两个地方)和endDate(这是js的日期对象)。当然，如果你愿意，你可以把它包装在一个函数中

Array(Math.floor((endDate - startDate) / 86400000) + 1).fill().map((_, idx) => (new Date(startDate.getTime() + idx * 86400000)))

@softvar的解决方案，但随后包括工作日期选项

/**
 * Returns array of working days between two dates.
 *
 * @param {string} startDate
 *   The start date in yyyy-mm-dd format.
 * @param {string} endDate
 *   The end date in yyyy-mm-dd format.
 * @param {boolean} onlyWorkingDays
 *   If true only working days are returned. Default: false
 *
 * @return {array}
 *   Array of dates in yyyy-mm-dd string format.
 */
function getDates(startDate, stopDate, onlyWorkingDays) {
  let doWd = typeof onlyWorkingDays ==='undefined' ? false : onlyWorkingDays;

  let dateArray = [];  
  let dayNr;
  let runDateObj = moment(startDate);  
  let stopDateObj = moment(stopDate);

  while (runDateObj <= stopDateObj) {
    dayNr = runDateObj.day();
    if (!doWd || (dayNr>0 && dayNr<6)) {
     dateArray.push(moment(runDateObj).format('YYYY-MM-DD'));  
    }

    runDateObj = moment(runDateObj).add(1, 'days');
  }
  return dateArray;
}

我使用这个函数

function getDatesRange(startDate, stopDate) {
    const ONE_DAY = 24*3600*1000;
    var days= [];
    var currentDate = new Date(startDate);
    while (currentDate <= stopDate) {
        days.push(new Date (currentDate));
        currentDate = currentDate - 1 + 1 + ONE_DAY;
    }
    return days;
}