var listDate = [];
var startDate ='2017-02-01';
var endDate = '2017-02-10';
var dateMove = new Date(startDate);
var strDate = startDate;

while (strDate < endDate){
  var strDate = dateMove.toISOString().slice(0,10);
  listDate.push(strDate);
  dateMove.setDate(dateMove.getDate()+1);
};
console.log(listDate);

//["2017-02-01", "2017-02-02", "2017-02-03", "2017-02-04", "2017-02-05", "2017-02-06", "2017-02-07", "2017-02-08", "2017-02-09", "2017-02-10"]

刚遇到这个问题，最简单的方法就是用moment:

你需要先安装moment和moment-range:

const Moment = require('moment');
const MomentRange = require('moment-range');
const moment = MomentRange.extendMoment(Moment);

const start = moment()
const end = moment().add(2, 'months')
const range = moment.range(start, end)
const arrayOfDates = Array.from(range.by('days'))
console.log(arrayOfDates)

使用JavaScript

const getDatesBetween = (startDate, endDate, includeEndDate) => {
    const dates = [];
    const currentDate = startDate;
    while (currentDate < endDate) {
        dates.push(new Date(currentDate));
        currentDate.setDate(currentDate.getDate() + 1);
    }
    if (includeEndDate) dates.push(endDate);
    return dates;
};

使用打印稿

const getDatesBetween = (
  startDate: Date,
  endDate: Date,
  includeEndDate?: boolean
) => {
  const dates = [];
  const currentDate = startDate;
  while (currentDate < endDate) {
    dates.push(new Date(currentDate));
    currentDate.setDate(currentDate.getDate() + 1);
  }
  if (includeEndDate) dates.push(endDate);
  return dates;
};

例子

console.log(getDatesBetween(new Date(2020, 0, 1), new Date(2020, 0, 3)));
console.log(getDatesBetween(new Date(2020, 0, 1), new Date(2020, 0, 3), true));

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

我看了上面所有的。最后我自己开始写作。你不需要花时间。原生的for循环就足够了，而且最有意义，因为for循环的存在是为了计算一个范围内的值。

一个衬套:

var getDaysArray = function(s,e) {for(var a=[],d=new Date(s);d<=new Date(e);d.setDate(d.getDate()+1)){ a.push(new Date(d));}return a;};

长版本

var getDaysArray = function(start, end) {
    for(var arr=[],dt=new Date(start); dt<=new Date(end); dt.setDate(dt.getDate()+1)){
        arr.push(new Date(dt));
    }
    return arr;
};

列出中间的日期:

var daylist = getDaysArray(new Date("2018-05-01"),new Date("2018-07-01"));
daylist.map((v)=>v.toISOString().slice(0,10)).join("")
/*
Output: 
    "2018-05-01
    2018-05-02
    2018-05-03
    ...
    2018-06-30
    2018-07-01"
*/

从过去日期到现在的日子:

var daylist = getDaysArray(new Date("2018-05-01"),new Date());
daylist.map((v)=>v.toISOString().slice(0,10)).join("")

使用ES6，你有Array.from意味着你可以写一个非常优雅的函数，它允许动态间隔(小时，天，月)。

function getDates(startDate, endDate, interval) { const duration = endDate - startDate; const steps = duration / interval; return Array.from({length: steps+1}, (v,i) => new Date(startDate.valueOf() + (interval * i))); } const startDate = new Date(2017,12,30); const endDate = new Date(2018,1,3); const dayInterval = 1000 * 60 * 60 * 24; // 1 day const halfDayInterval = 1000 * 60 * 60 * 12; // 1/2 day console.log("Days", getDates(startDate, endDate, dayInterval)); console.log("Half Days", getDates(startDate, endDate, halfDayInterval));