var range = getDates(new Date(), new Date().addDays(7));

我想“范围”是一个日期对象的数组,一个为两个日期之间的每一天。

诀窍在于它还应该处理月份和年份的边界。


当前回答

Generate an array of years: const DAYS = () => { const days = [] const dateStart = moment() const dateEnd = moment().add(30, ‘days') while (dateEnd.diff(dateStart, ‘days') >= 0) { days.push(dateStart.format(‘D')) dateStart.add(1, ‘days') } return days } console.log(DAYS()) Generate an arrays for month: const MONTHS = () => { const months = [] const dateStart = moment() const dateEnd = moment().add(12, ‘month') while (dateEnd.diff(dateStart, ‘months') >= 0) { months.push(dateStart.format(‘M')) dateStart.add(1, ‘month') } return months } console.log(MONTHS()) Generate an arrays for days: const DAYS = () => { const days = [] const dateStart = moment() const dateEnd = moment().add(30, ‘days') while (dateEnd.diff(dateStart, ‘days') >= 0) { days.push(dateStart.format(‘D')) dateStart.add(1, ‘days') } return days } console.log(DAYS())

其他回答

我最近在用moment.js工作,下面做了一个戏法。

function getDateRange(startDate, endDate, dateFormat) {
        var dates = [],
            end = moment(endDate),
            diff = endDate.diff(startDate, 'days');

        if(!startDate.isValid() || !endDate.isValid() || diff <= 0) {
            return;
        }

        for(var i = 0; i < diff; i++) {
            dates.push(end.subtract(1,'d').format(dateFormat));
        }

        return dates;
    };
    console.log(getDateRange(startDate, endDate, dateFormat));

结果将是:

["09/03/2015", "10/03/2015", "11/03/2015", "12/03/2015", "13/03/2015", "14/03/2015", "15/03/2015", "16/03/2015", "17/03/2015", "18/03/2015"]

我使用这个函数

function getDatesRange(startDate, stopDate) {
    const ONE_DAY = 24*3600*1000;
    var days= [];
    var currentDate = new Date(startDate);
    while (currentDate <= stopDate) {
        days.push(new Date (currentDate));
        currentDate = currentDate - 1 + 1 + ONE_DAY;
    }
    return days;
}
Array(7).fill().map((_,i) => dayjs().subtract(i, "day").format("YYYY-MM-DD"));

我在使用上面的答案时遇到了麻烦。由于当地夏令时(DST)导致时区偏移,日期范围丢失了一天。我实现了一个使用UTC日期的版本,解决了这个问题:

函数daterrange (startDate, endDate, steps = 1) { const dateArray = []; let currentDate = new Date(startDate); while (currentDate <=新日期(endDate)) { dateArray。推动(新日期(currentDate)); //使用UTC日期防止时区和夏令时出现问题 currentDate.setUTCDate() + steps); } 返回dateArray; } const dates = dateRange('2020-09-27', '2020-10-28'); console.log(日期);

注意:是否应用了某个时区或DST,完全取决于您的地区。忽略这一点通常不是一个好主意。使用UTC日期可以缓解大多数与时间相关的问题。

好处:您可以使用可选的steps参数设置要创建时间戳的时间间隔。如果你想要每周的时间表,将步骤设置为7。

这可能会帮助到一些人,

您可以从中获得行输出,并根据需要格式化row_date对象。

var from_date = '2016-01-01';
var to_date = '2016-02-20';

var dates = getDates(from_date, to_date);

console.log(dates);

function getDates(from_date, to_date) {
  var current_date = new Date(from_date);
  var end_date     = new Date(to_date);

  var getTimeDiff = Math.abs(current_date.getTime() - end_date.getTime());
  var date_range = Math.ceil(getTimeDiff / (1000 * 3600 * 24)) + 1 ;

  var weekday = ["SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"];
  var months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
  var dates = new Array();

  for (var i = 0; i <= date_range; i++) {
     var getDate, getMonth = '';

     if(current_date.getDate() < 10) { getDate = ('0'+ current_date.getDate());}
     else{getDate = current_date.getDate();}

    if(current_date.getMonth() < 9) { getMonth = ('0'+ (current_date.getMonth()+1));}
    else{getMonth = current_date.getMonth();}

    var row_date = {day: getDate, month: getMonth, year: current_date.getFullYear()};
    var fmt_date = {weekDay: weekday[current_date.getDay()], date: getDate, month: months[current_date.getMonth()]};
    var is_weekend = false;
    if (current_date.getDay() == 0 || current_date.getDay() == 6) {
        is_weekend = true;
    }
    dates.push({row_date: row_date, fmt_date: fmt_date, is_weekend: is_weekend});
    current_date.setDate(current_date.getDate() + 1);
 }
 return dates;
}

https://gist.github.com/pranid/3c78f36253cbbc6a41a859c5d718f362.js