不是最短的，而是简单的，不可变的，没有依赖关系

function datesArray(start, end) {
    let result = [], current = new Date(start);
    while (current <= end)
        result.push(current) && (current = new Date(current)) && current.setDate(current.getDate() + 1);
    return result;
}

使用

函数datesArray(start, end) { let result = []， current = new Date(start); While (current <= end) result.push(current) && (current = new Date(current)) && current. setdate (current. getdate () + 1); 返回结果; } / /使用 const test = datesArray( 新的日期(“2020-02-26”), 新日期(“2020-03-05”) ）; 对于(设I = 0;I < test.length;I ++) { console.log ( 测试[我].toISOString () .slice (0, 10) ）; }

var boxingDay = new Date("12/26/2010");
var nextWeek  = boxingDay*1 + 7*24*3600*1000;

function getDates( d1, d2 ){
  var oneDay = 24*3600*1000;
  for (var d=[],ms=d1*1,last=d2*1;ms<last;ms+=oneDay){
    d.push( new Date(ms) );
  }
  return d;
}

getDates( boxingDay, nextWeek ).join("\n");
// Sun Dec 26 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Mon Dec 27 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Tue Dec 28 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Wed Dec 29 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Thu Dec 30 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Fri Dec 31 2010 00:00:00 GMT-0700 (Mountain Standard Time)
// Sat Jan 01 2011 00:00:00 GMT-0700 (Mountain Standard Time)

getDates = (from, to) => {
    const cFrom = new Date(from);
    const cTo = new Date(to);

    let daysArr = [new Date(cFrom)];
    let tempDate = cFrom;

    while (tempDate < cTo) {
        tempDate.setUTCDate(tempDate.getUTCDate() + 1);
        daysArr.push(new Date(tempDate));
    }

    return daysArr;
}

不是最短的，而是简单的，不可变的，没有依赖关系

function datesArray(start, end) {
    let result = [], current = new Date(start);
    while (current <= end)
        result.push(current) && (current = new Date(current)) && current.setDate(current.getDate() + 1);
    return result;
}

使用

函数datesArray(start, end) { let result = []， current = new Date(start); While (current <= end) result.push(current) && (current = new Date(current)) && current. setdate (current. getdate () + 1); 返回结果; } / /使用 const test = datesArray( 新的日期(“2020-02-26”), 新日期(“2020-03-05”) ）; 对于(设I = 0;I < test.length;I ++) { console.log ( 测试[我].toISOString () .slice (0, 10) ）; }

我喜欢这样做

// hours * minutes * seconds * milliseconds
const DAY_IN_MS = 24 * 60 * 60 * 1000

/**
 * Get range of dates 
 * @param {Date} startDate 
 * @param {Number} numOfDays 
 * @returns {array}
 */
const dateRange = (startDate, numOfDays) => {
    const startDateMs = startDate.getTime()

    // get array of days and map it to Date object
    return [...Array(numOfDays).keys()].map(i => new Date(startDateMs + i * DAY_IN_MS))
}

我使用moment.js和Twix.js，它们为日期和时间操作提供了非常好的支持

var itr = moment.twix(new Date('2012-01-15'),new Date('2012-01-20')).iterate("days");
var range=[];
while(itr.hasNext()){
    range.push(itr.next().toDate())
}
console.log(range);

我在http://jsfiddle.net/Lkzg1bxb/上运行这个程序