在2013-05-10,Guido同意将PEP 435纳入Python 3.4标准库。这意味着Python终于内置了对枚举的支持!

Python 3.3、3.2、3.1、2.7、2.6、2.5和2.4有一个可用的后端端口。它在Pypi上枚举34。

声明:

>>> from enum import Enum
>>> class Color(Enum):
...     red = 1
...     green = 2
...     blue = 3

表示:

>>> print(Color.red)
Color.red
>>> print(repr(Color.red))
<Color.red: 1>

迭代:

>>> for color in Color:
...   print(color)
...
Color.red
Color.green
Color.blue

编程访问:

>>> Color(1)
Color.red
>>> Color['blue']
Color.blue

有关更多信息，请参阅提案。官方文件可能很快就会发布。

在PEP 435之前，Python没有等效的，但你可以实现自己的。

就我个人而言，我喜欢保持简单(我在网上看到过一些非常复杂的例子)，就像这样……

class Animal:
    DOG = 1
    CAT = 2

x = Animal.DOG

在Python 3.4 (PEP 435)中，可以将Enum作为基类。这为您提供了一些额外的功能，详见PEP。例如，enum成员不同于整数，它们由名称和值组成。

from enum import Enum

class Animal(Enum):
    DOG = 1
    CAT = 2

print(Animal.DOG)
# <Animal.DOG: 1>

print(Animal.DOG.value)
# 1

print(Animal.DOG.name)
# "DOG"

如果您不想键入值，请使用以下快捷方式:

class Animal(Enum):
    DOG, CAT = range(2)

枚举实现可以转换为列表，并且是可迭代的。其成员的顺序是声明顺序，与它们的值无关。例如:

class Animal(Enum):
    DOG = 1
    CAT = 2
    COW = 0

list(Animal)
# [<Animal.DOG: 1>, <Animal.CAT: 2>, <Animal.COW: 0>]

[animal.value for animal in Animal]
# [1, 2, 0]

Animal.CAT in Animal
# True

另一个非常简单的Python枚举实现，使用namedtuple:

from collections import namedtuple

def enum(*keys):
    return namedtuple('Enum', keys)(*keys)

MyEnum = enum('FOO', 'BAR', 'BAZ')

,或者

# With sequential number values
def enum(*keys):
    return namedtuple('Enum', keys)(*range(len(keys)))

# From a dict / keyword args
def enum(**kwargs):
    return namedtuple('Enum', kwargs.keys())(*kwargs.values())




# Example for dictionary param:
values = {"Salad": 20, "Carrot": 99, "Tomato": "No i'm not"} 
Vegetables= enum(**values)

# >>> print(Vegetables.Tomato)        'No i'm not'


# Example for keyworded params: 
Fruits = enum(Apple="Steve Jobs", Peach=1, Banana=2)

# >>> print(Fruits.Apple)             'Steve Jobs'

就像上面子类设置的方法一样，这允许:

'FOO' in MyEnum
other = MyEnum.FOO
assert other == MyEnum.FOO

但是具有更大的灵活性，因为它可以有不同的键和值。这允许

MyEnum.FOO < MyEnum.BAR

如果使用填充连续数字值的版本，则按预期操作。

这是我见过的最好的一个:“Python中的First Class Enums”

http://code.activestate.com/recipes/413486/

It gives you a class, and the class contains all the enums. The enums can be compared to each other, but don't have any particular value; you can't use them as an integer value. (I resisted this at first because I am used to C enums, which are integer values. But if you can't use it as an integer, you can't use it as an integer by mistake so overall I think it is a win.) Each enum is a unique value. You can print enums, you can iterate over them, you can test that an enum value is "in" the enum. It's pretty complete and slick.

编辑(cfi):上面的链接不兼容Python 3。下面是我将枚举.py移植到Python 3的端口:

def cmp(a,b):
   if a < b: return -1
   if b < a: return 1
   return 0


def Enum(*names):
   ##assert names, "Empty enums are not supported" # <- Don't like empty enums? Uncomment!

   class EnumClass(object):
      __slots__ = names
      def __iter__(self):        return iter(constants)
      def __len__(self):         return len(constants)
      def __getitem__(self, i):  return constants[i]
      def __repr__(self):        return 'Enum' + str(names)
      def __str__(self):         return 'enum ' + str(constants)

   class EnumValue(object):
      __slots__ = ('__value')
      def __init__(self, value): self.__value = value
      Value = property(lambda self: self.__value)
      EnumType = property(lambda self: EnumType)
      def __hash__(self):        return hash(self.__value)
      def __cmp__(self, other):
         # C fans might want to remove the following assertion
         # to make all enums comparable by ordinal value {;))
         assert self.EnumType is other.EnumType, "Only values from the same enum are comparable"
         return cmp(self.__value, other.__value)
      def __lt__(self, other):   return self.__cmp__(other) < 0
      def __eq__(self, other):   return self.__cmp__(other) == 0
      def __invert__(self):      return constants[maximum - self.__value]
      def __nonzero__(self):     return bool(self.__value)
      def __repr__(self):        return str(names[self.__value])

   maximum = len(names) - 1
   constants = [None] * len(names)
   for i, each in enumerate(names):
      val = EnumValue(i)
      setattr(EnumClass, each, val)
      constants[i] = val
   constants = tuple(constants)
   EnumType = EnumClass()
   return EnumType


if __name__ == '__main__':
   print( '\n*** Enum Demo ***')
   print( '--- Days of week ---')
   Days = Enum('Mo', 'Tu', 'We', 'Th', 'Fr', 'Sa', 'Su')
   print( Days)
   print( Days.Mo)
   print( Days.Fr)
   print( Days.Mo < Days.Fr)
   print( list(Days))
   for each in Days:
      print( 'Day:', each)
   print( '--- Yes/No ---')
   Confirmation = Enum('No', 'Yes')
   answer = Confirmation.No
   print( 'Your answer is not', ~answer)

在2013-05-10,Guido同意将PEP 435纳入Python 3.4标准库。这意味着Python终于内置了对枚举的支持!

Python 3.3、3.2、3.1、2.7、2.6、2.5和2.4有一个可用的后端端口。它在Pypi上枚举34。

声明:

>>> from enum import Enum
>>> class Color(Enum):
...     red = 1
...     green = 2
...     blue = 3

表示:

>>> print(Color.red)
Color.red
>>> print(repr(Color.red))
<Color.red: 1>

迭代:

>>> for color in Color:
...   print(color)
...
Color.red
Color.green
Color.blue

编程访问:

>>> Color(1)
Color.red
>>> Color['blue']
Color.blue

有关更多信息，请参阅提案。官方文件可能很快就会发布。

这个解决方案是获取定义为列表的枚举类的简单方法(没有更多烦人的整数赋值):

enumeration.py:

import new

def create(class_name, names):
    return new.classobj(
        class_name, (object,), dict((y, x) for x, y in enumerate(names))
    )

example.py:

import enumeration

Colors = enumeration.create('Colors', (
    'red',
    'orange',
    'yellow',
    'green',
    'blue',
    'violet',
))