首先，您必须设置EditText监听按键

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main); 

    // Set the EditText listens to key press
    EditText edittextproductnumber = (EditText) findViewById(R.id.editTextproductnumber);
    edittextproductnumber.setOnKeyListener(this);

}

其次，定义按键时的事件，例如，设置TextView的文本的event:

@Override
public boolean onKey(View v, int keyCode, KeyEvent event) {
    // TODO Auto-generated method stub

 // Listen to "Enter" key press
 if ((event.getAction() == KeyEvent.ACTION_DOWN) && (keyCode == KeyEvent.KEYCODE_ENTER))
 {
     TextView textviewmessage = (TextView) findViewById(R.id.textViewmessage);
     textviewmessage.setText("You hit 'Enter' key");
     return true;
 }

return false;   

}

最后，不要忘记在顶部导入EditText,TextView,OnKeyListener,KeyEvent:

import android.view.KeyEvent;
import android.view.View.OnKeyListener;
import android.widget.EditText;
import android.widget.TextView;

A dependable way to respond to an <enter> in an EditText is with a TextWatcher, a LocalBroadcastManager, and a BroadcastReceiver. You need to add the v4 support library to use the LocalBroadcastManager. I use the tutorial at vogella.com: 7.3 "Local broadcast events with LocalBroadcastManager" because of its complete concise code Example. In onTextChanged before is the index of the end of the change before the change>;minus start. When in the TextWatcher the UI thread is busy updating editText's editable, so we send an Intent to wake up the BroadcastReceiver when the UI thread is done updating editText.

import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.text.Editable;
//in onCreate:
editText.addTextChangedListener(new TextWatcher() {
  public void onTextChanged
  (CharSequence s, int start, int before, int count) {
    //check if exactly one char was added and it was an <enter>
    if (before==0 && count==1 && s.charAt(start)=='\n') {
    Intent intent=new Intent("enter")
    Integer startInteger=new Integer(start);
    intent.putExtra("Start", startInteger.toString()); // Add data
    mySendBroadcast(intent);
//in the BroadcastReceiver's onReceive:
int start=Integer.parseInt(intent.getStringExtra("Start"));
editText.getText().replace(start, start+1,""); //remove the <enter>
//respond to the <enter> here

Kotlin解决方案的反应进入按使用Lambda表达式:

        editText.setOnKeyListener { _, keyCode, event ->
            if(keyCode == KeyEvent.KEYCODE_ENTER && event.action==KeyEvent.ACTION_DOWN){
            //react to enter press here
            }
            true
        }

不做额外的检查类型的事件将导致这个监听器被调用两次时按一次(一次为ACTION_DOWN，一次为ACTION_UP)

这应该可以

input.addTextChangedListener(new TextWatcher() {

           @Override
           public void afterTextChanged(Editable s) {}

           @Override    
           public void beforeTextChanged(CharSequence s, int start,
             int count, int after) {
           }

           @Override    
           public void onTextChanged(CharSequence s, int start,
             int before, int count) {
               if( -1 != input.getText().toString().indexOf( "\n" ) ){
                   input.setText("Enter was pressed!");
                    }
           }
          });

final EditText edittext = (EditText) findViewById(R.id.edittext);
edittext.setOnKeyListener(new OnKeyListener() {
    public boolean onKey(View v, int keyCode, KeyEvent event) {
        // If the event is a key-down event on the "enter" button
        if ((event.getAction() == KeyEvent.ACTION_DOWN) &&
            (keyCode == KeyEvent.KEYCODE_ENTER)) {
          // Perform action on key press
          Toast.makeText(HelloFormStuff.this, edittext.getText(), Toast.LENGTH_SHORT).show();
          return true;
        }
        return false;
    }
});

     password.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            if(event != null && event.getKeyCode() == KeyEvent.KEYCODE_ENTER && event.getAction() == KeyEvent.ACTION_DOWN) {
                InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
                imm.toggleSoftInput(InputMethodManager.SHOW_IMPLICIT, 0);
                submit.performClick();
                return true;
            }
            return false;
        }
    });

对我来说很好 另外隐藏键盘