我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。

还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。


当前回答

我通过扩展新的MaterialAlertDialogBuilder创建了一个辅助类

使用

new InputPopupBuilder(context)
        .setInput(R.string.send, 
                R.string.enter_your_message, 
                text -> sendFeedback(text, activity))
        .setTitle(R.string.contact_us)
        .show();

Code

public class InputPopupBuilder extends MaterialAlertDialogBuilder {

    private final Context context;
    private final AppCompatEditText input;

    public InputPopupBuilder(Context context) {
        super(context);
        this.context = context;
        input = new AppCompatEditText(context);
        input.setInputType(InputType.TYPE_CLASS_TEXT);
        setView(input);
    }

    public InputPopupBuilder setInput(int actionLabel, int hint, Callback callback) {
        input.setHint(hint);
        input.setImeActionLabel(context.getString(actionLabel), KeyEvent.KEYCODE_ENTER);
        input.setOnEditorActionListener((TextView.OnEditorActionListener) (v, actionId, event) -> {
            if (actionId == EditorInfo.IME_NULL
                    && event.getAction() == KeyEvent.ACTION_DOWN) {
                Editable text = input.getText();
                if (text != null) {
                    callback.onClick(text.toString());
                    return true;
                }
            }
            return false;
        });

        setPositiveButton(actionLabel, (dialog, which) -> {
            Editable text = input.getText();
            if (text != null) {
                callback.onClick(text.toString());
            }
        });

        return this;
    }

    public InputPopupBuilder setText(String text){
        input.setText(text);
        return this;
    }

    public InputPopupBuilder setInputType(int inputType){
        input.setInputType(inputType);
        return this;
    }

    public interface Callback {
        void onClick(String text);
    }
}

需要

implementation 'com.google.android.material:material:1.3.0-alpha04'

其他回答

你可以用这种方法

editText.setOnEditorActionListener((v, actionId, event) -> {
       if (actionId == EditorInfo.IME_ACTION_DONE) {
          // Do some things      
          return true;
       }
       return false;
});

你可以在那里看到行动清单。

例如:

IME_ACTION_GO

IME_ACTION_SEARCH

IME_ACTION_SEND

作为Chad响应的补充(对我来说几乎完美),我发现我需要在KeyEvent操作类型上添加一个检查,以防止代码执行两次(一次在key-up事件上执行,一次在key-down事件上执行)。

if (actionId == EditorInfo.IME_NULL && event.getAction() == KeyEvent.ACTION_DOWN)
{
    // your code here
}

有关重复动作事件(按住enter键)的信息,请参见http://developer.android.com/reference/android/view/KeyEvent.html。

完美的工作

public class MainActivity extends AppCompatActivity {  
TextView t;
Button b;
EditText e;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    b = (Button) findViewById(R.id.b);
    e = (EditText) findViewById(R.id.e);

    e.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

            if (before == 0 && count == 1 && s.charAt(start) == '\n') {

                b.performClick();
                e.getText().replace(start, start + 1, ""); //remove the <enter>
            }

        }
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {}
        @Override
        public void afterTextChanged(Editable s) {}
    });

    b.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            b.setText("ok");

        }
    });
}

}

完美的工作

本页详细描述了如何做到这一点。

https://developer.android.com/training/keyboard-input/style.html

设置android:imeOptions,然后检查onEditorAction中的actionId。因此,如果你设置imeOptions为“actionDone”,那么你会检查“actionId == EditorInfo”。onEditorAction中的IME_ACTION_DONE `。另外,确保设置android:inputType。

如果使用材质设计,将代码放在TextInputEditText中。

下面是上面链接的例子中的EditText:

<EditText
    android:id="@+id/search"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:hint="@string/search_hint"
    android:inputType="text"
    android:imeOptions="actionSend" />

您还可以使用setImeOptions(int)函数以编程方式设置此选项。下面是上面链接的例子中的OnEditorActionListener:

EditText editText = (EditText) findViewById(R.id.search);
editText.setOnEditorActionListener(new OnEditorActionListener() {
    @Override
    public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
        boolean handled = false;
        if (actionId == EditorInfo.IME_ACTION_SEND) {
            sendMessage();
            handled = true;
        }
        return handled;
    }
});

A dependable way to respond to an <enter> in an EditText is with a TextWatcher, a LocalBroadcastManager, and a BroadcastReceiver. You need to add the v4 support library to use the LocalBroadcastManager. I use the tutorial at vogella.com: 7.3 "Local broadcast events with LocalBroadcastManager" because of its complete concise code Example. In onTextChanged before is the index of the end of the change before the change>;minus start. When in the TextWatcher the UI thread is busy updating editText's editable, so we send an Intent to wake up the BroadcastReceiver when the UI thread is done updating editText.

import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.text.Editable;
//in onCreate:
editText.addTextChangedListener(new TextWatcher() {
  public void onTextChanged
  (CharSequence s, int start, int before, int count) {
    //check if exactly one char was added and it was an <enter>
    if (before==0 && count==1 && s.charAt(start)=='\n') {
    Intent intent=new Intent("enter")
    Integer startInteger=new Integer(start);
    intent.putExtra("Start", startInteger.toString()); // Add data
    mySendBroadcast(intent);
//in the BroadcastReceiver's onReceive:
int start=Integer.parseInt(intent.getStringExtra("Start"));
editText.getText().replace(start, start+1,""); //remove the <enter>
//respond to the <enter> here