谢谢你的帮助，但我发现了一个可选的解决方案

 public class getsetclass implements Serializable {
        private int dt = 10;
    //pass any object, drwabale 
        public int getDt() {
            return dt;
        }

        public void setDt(int dt) {
            this.dt = dt;
        }
    }

活动一

getsetclass d = new getsetclass ();
                d.setDt(50);
                LinkedHashMap<String, Object> obj = new LinkedHashMap<String, Object>();
                obj.put("hashmapkey", d);
            Intent inew = new Intent(SgParceLableSampelActivity.this,
                    ActivityNext.class);
            Bundle b = new Bundle();
            b.putSerializable("bundleobj", obj);
            inew.putExtras(b);
            startActivity(inew);

在活动2中获取数据

 try {  setContentView(R.layout.main);
            Bundle bn = new Bundle();
            bn = getIntent().getExtras();
            HashMap<String, Object> getobj = new HashMap<String, Object>();
            getobj = (HashMap<String, Object>) bn.getSerializable("bundleobj");
            getsetclass  d = (getsetclass) getobj.get("hashmapkey");
        } catch (Exception e) {
            Log.e("Err", e.getMessage());
        }

如果你只是传递对象，那么Parcelable就是为这个设计的。使用它需要比使用Java的本机序列化多一点努力，但它要快得多(我的意思是快得多)。

从文档中，一个简单的例子是如何实现的:

// simple class that just has one member property as an example
public class MyParcelable implements Parcelable {
    private int mData;

    /* everything below here is for implementing Parcelable */

    // 99.9% of the time you can just ignore this
    @Override
    public int describeContents() {
        return 0;
    }

    // write your object's data to the passed-in Parcel
    @Override
    public void writeToParcel(Parcel out, int flags) {
        out.writeInt(mData);
    }

    // this is used to regenerate your object. All Parcelables must have a CREATOR that implements these two methods
    public static final Parcelable.Creator<MyParcelable> CREATOR = new Parcelable.Creator<MyParcelable>() {
        public MyParcelable createFromParcel(Parcel in) {
            return new MyParcelable(in);
        }

        public MyParcelable[] newArray(int size) {
            return new MyParcelable[size];
        }
    };

    // example constructor that takes a Parcel and gives you an object populated with it's values
    private MyParcelable(Parcel in) {
        mData = in.readInt();
    }
}

请注意，如果要从给定的Parcel中检索多个字段，则必须按照放入它们的相同顺序(即采用FIFO方法)执行此操作。

一旦你有你的对象实现Parcelable，这只是一个问题，把他们放入你的意图与putExtra():

Intent i = new Intent();
i.putExtra("name_of_extra", myParcelableObject);

然后你可以用getParcelableExtra()把它们拉回来:

Intent i = getIntent();
MyParcelable myParcelableObject = (MyParcelable) i.getParcelableExtra("name_of_extra");

如果你的对象类实现了Parcelable和Serializable，那么请确保转换为以下类型之一:

i.putExtra("parcelable_extra", (Parcelable) myParcelableObject);
i.putExtra("serializable_extra", (Serializable) myParcelableObject);

另一种方法是使用Application对象(android.app.Application)。在AndroidManifest.xml文件中定义如下:

<application
    android:name=".MyApplication"
    ...

然后，您可以从任何活动调用它，并将对象保存到Application类。

在FirstActivity中:

MyObject myObject = new MyObject();
MyApplication app = (MyApplication) getApplication();
app.setMyObject(myObject);

在SecondActivity中，执行以下操作:

MyApplication app = (MyApplication) getApplication();
MyObject retrievedObject = app.getMyObject(myObject);

如果你的对象具有应用程序级别的作用域，即它们必须在整个应用程序中使用，这是很方便的。如果您希望显式控制对象范围，或者对象范围是有限的，那么Parcelable方法仍然更好。

不过，这完全避免了intent的使用。我不知道是否适合你。我使用它的另一种方式是让对象的int标识符通过intent发送，并在Application对象中检索我在Maps中拥有的对象。

你的类应该实现Serializable或Parcelable。

public class MY_CLASS implements Serializable

一旦完成，你可以在putExtra上发送一个对象

intent.putExtra("KEY", MY_CLASS_instance);

startActivity(intent);

要得到额外的，你只需要做

Intent intent = getIntent();
MY_CLASS class = (MY_CLASS) intent.getExtras().getSerializable("KEY");

如果您的类实现了Parcelable，请使用下一个

MY_CLASS class = (MY_CLASS) intent.getExtras().getParcelable("KEY");

我希望它能帮到你

对于你知道要在应用程序中传递数据的情况，使用“全局变量”(比如静态类)

以下是Dianne Hackborn (hackbod -谷歌安卓软件工程师)对此事的看法:

For situations where you know the activities are running in the same process, you can just share data through globals. For example, you could have a global HashMap<String, WeakReference<MyInterpreterState>> and when you make a new MyInterpreterState come up with a unique name for it and put it in the hash map; to send that state to another activity, simply put the unique name into the hash map and when the second activity is started it can retrieve the MyInterpreterState from the hash map with the name it receives.

如果你有一个单例类(fx Service)作为你的模型层的网关，它可以通过在该类中有一个带有getter和setter的变量来解决。

活动一:

Intent intent = new Intent(getApplicationContext(), Activity2.class);
service.setSavedOrder(order);
startActivity(intent);

活动二:

private Service service;
private Order order;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_quality);

    service = Service.getInstance();
    order = service.getSavedOrder();
    service.setSavedOrder(null) //If you don't want to save it for the entire session of the app.
}

在服务:

private static Service instance;

private Service()
{
    //Constructor content
}

public static Service getInstance()
{
    if(instance == null)
    {
        instance = new Service();
    }
    return instance;
}
private Order savedOrder;

public Order getSavedOrder()
{
    return savedOrder;
}

public void setSavedOrder(Order order)
{
    this.savedOrder = order;
}

此解决方案不需要对相关对象进行任何序列化或其他“打包”。但是，只有在使用这种架构时才会有好处。