首先在类中实现Parcelable。然后像这样传递object。

SendActivity.java

ObjectA obj = new ObjectA();

// Set values etc.

Intent i = new Intent(this, MyActivity.class);
i.putExtra("com.package.ObjectA", obj);

startActivity(i);

ReceiveActivity.java

Bundle b = getIntent().getExtras();
ObjectA obj = b.getParcelable("com.package.ObjectA");

包字符串不是必须的，只是在两个活动中字符串需要相同

参考

对于你知道要在应用程序中传递数据的情况，使用“全局变量”(比如静态类)

以下是Dianne Hackborn (hackbod -谷歌安卓软件工程师)对此事的看法:

For situations where you know the activities are running in the same process, you can just share data through globals. For example, you could have a global HashMap<String, WeakReference<MyInterpreterState>> and when you make a new MyInterpreterState come up with a unique name for it and put it in the hash map; to send that state to another activity, simply put the unique name into the hash map and when the second activity is started it can retrieve the MyInterpreterState from the hash map with the name it receives.

你可以使用android BUNDLE来做到这一点。

从你的类中创建一个Bundle，像这样:

public Bundle toBundle() {
    Bundle b = new Bundle();
    b.putString("SomeKey", "SomeValue");

    return b;
}

然后用INTENT传递这个bundle。 现在你可以通过传递bundle来重新创建你的类对象

public CustomClass(Context _context, Bundle b) {
    context = _context;
    classMember = b.getString("SomeKey");
}

在自定义类中声明并使用。

在类中实现serializable

public class Place implements Serializable{
        private int id;
        private String name;

        public void setId(int id) {
           this.id = id;
        }
        public int getId() {
           return id;
        }
        public String getName() {
           return name;
        }

        public void setName(String name) {
           this.name = name;
        }
}

然后你可以意图传递这个对象

     Intent intent = new Intent(this, SecondAct.class);
     intent.putExtra("PLACE", Place);
     startActivity(intent);

在第二个活动中，你可以得到这样的数据

     Place place= (Place) getIntent().getSerializableExtra("PLACE");

但是当数据量变大时，这种方法会变慢。

你可以使用putExtra(Serializable..)和getSerializableExtra()方法来传递和检索你的类类型的对象;你必须将你的类标记为Serializable，并确保你所有的成员变量也是Serializable…

你可以通过intent发送可序列化对象

// send where details is object
ClassName details = new ClassName();
Intent i = new Intent(context, EditActivity.class);
i.putExtra("Editing", details);
startActivity(i);


//receive
ClassName model = (ClassName) getIntent().getSerializableExtra("Editing");

And 

Class ClassName implements Serializable {
}