像这样,

if(v1.HasValue)
   v2=v1.Value

到目前为止，其他答案都是正确的;我只是想再加一个稍微干净一点的:

v2 = v1 ?? default(int);

任何Nullable<T>都可以隐式转换为它的T，前提是被计算的整个表达式永远不会导致对ValueType的空赋值。那么，空合并操作符??只是三元运算符的语法糖:

v2 = v1 == null ? default(int) : v1.Value;

.．.这反过来是if/else的语法糖:

if(v1==null)
   v2 = default(int);
else
   v2 = v1.Value;

此外，在。net 4.0中，Nullable<T>有一个"GetValueOrDefault()"方法，这是一个空安全的getter，基本上执行如上所示的空合并，所以这也是有效的:

v2 = v1.GetValueOrDefault();

根据你的使用上下文，你可以使用c# 7的模式匹配特性:

int? v1 = 100;
if (v1 is int v2)
{
    Console.WriteLine($"I'm not nullable anymore: {v2}");
}

编辑:

由于有些人没有留下解释就投了反对票，我想添加一些细节来解释将此作为可行解决方案的基本原理。

C# 7's pattern matching now allows us check the type of a value and cast it implicitly. In the above snippet, the if-condition will only pass when the value stored in v1 is type-compatible to the type for v2, which in this case is int. It follows that when the value for v1 is null, the if-condition will fail since null cannot be assigned to an int. More properly, null is not an int. I'd like to highlight that the that this solution may not always be the optimal choice. As I suggest, I believe this will depend on the developer's exact usage context. If you already have an int? and want to conditionally operate on its value if-and-only-if the assigned value is not null (this is the only time it is safe to convert a nullable int to a regular int without losing information), then pattern matching is perhaps one of the most concise ways to do this.

正常的TypeConversion将抛出异常

Eg:

int y = 5;    
int? x = null;    
y = x.value; //It will throw "Nullable object must have a value"   
Console.WriteLine(y);

使用Convert.ToInt32()方法

int y = 5;    
int? x = null;    
y = x.Convert.ToInt32(x);    
Console.WriteLine(y);

这将返回0作为输出，因为y是整数。

你可以这样做

v2 = v1.HasValue ? v1.Value : v2;

如果v1为空，就不能这样做，但可以用运算符检查。

v2 = v1 ?? 0;