试试这段代码

static bool IsSubclassOfRawGeneric(Type generic, Type toCheck) {
    while (toCheck != null && toCheck != typeof(object)) {
        var cur = toCheck.IsGenericType ? toCheck.GetGenericTypeDefinition() : toCheck;
        if (generic == cur) {
            return true;
        }
        toCheck = toCheck.BaseType;
    }
    return false;
}

添加到@jaredpar的答案中，下面是我用来检查接口的方法:

public static bool IsImplementerOfRawGeneric(this Type type, Type toCheck)
{
    if (toCheck.GetTypeInfo().IsClass)
    {
        return false;
    }

    return type.GetInterfaces().Any(interfaceType =>
    {
        var current = interfaceType.GetTypeInfo().IsGenericType ?
                    interfaceType.GetGenericTypeDefinition() : interfaceType;
        return current == toCheck;
    });
}

public static bool IsSubTypeOfRawGeneric(this Type type, Type toCheck)
{
    return type.IsInterface ?
          IsImplementerOfRawGeneric(type, toCheck)
        : IsSubclassOfRawGeneric(type, toCheck);
}

Ex:

Console.WriteLine(typeof(IList<>).IsSubTypeOfRawGeneric(typeof(IList<int>))); // true

试试这段代码

static bool IsSubclassOfRawGeneric(Type generic, Type toCheck) {
    while (toCheck != null && toCheck != typeof(object)) {
        var cur = toCheck.IsGenericType ? toCheck.GetGenericTypeDefinition() : toCheck;
        if (generic == cur) {
            return true;
        }
        toCheck = toCheck.BaseType;
    }
    return false;
}

JaredPar的代码可以工作，但只适用于一个继承级别。要获得无限级别的继承，请使用以下代码

public bool IsTypeDerivedFromGenericType(Type typeToCheck, Type genericType)
{
    if (typeToCheck == typeof(object))
    {
        return false;
    }
    else if (typeToCheck == null)
    {
        return false;
    }
    else if (typeToCheck.IsGenericType && typeToCheck.GetGenericTypeDefinition() == genericType)
    {
        return true;
    }
    else
    {
        return IsTypeDerivedFromGenericType(typeToCheck.BaseType, genericType);
    }
}

简单的解决方案:只需创建并添加第二个非泛型接口到泛型类:

public interface IGenericClass
{
}

public class GenericClass<T> : GenericInterface<T>, IGenericClass
{
}

然后用is as IsAssignableFrom等任何你喜欢的方式检查。

if (thing is IGenericClass)
{
    // Do work
{

显然，只有当您能够编辑泛型类(OP似乎具有这种能力)时才有可能，但它比使用神秘的扩展方法更优雅、更可读。

这个游戏已经晚了…我对JarodPar的答案也有另一种排列。

下面是Type. issubclassof (Type)，由reflector提供:

    public virtual bool IsSubclassOf(Type c)
    {
        Type baseType = this;
        if (!(baseType == c))
        {
            while (baseType != null)
            {
                if (baseType == c)
                {
                    return true;
                }
                baseType = baseType.BaseType;
            }
            return false;
        }
        return false;
    }

由此，我们看到它并没有做任何过于疯狂的事情，并且类似于JaredPar的迭代方法。到目前为止，一切顺利。这是我的版本(免责声明:没有彻底测试，所以如果你发现问题，请告诉我)

    public static bool IsExtension(this Type thisType, Type potentialSuperType)
    {
        //
        // protect ya neck
        //
        if (thisType == null || potentialSuperType == null || thisType == potentialSuperType) return false;

        //
        // don't need to traverse inheritance for interface extension, so check/do these first
        //
        if (potentialSuperType.IsInterface)
        {
            foreach (var interfaceType in thisType.GetInterfaces())
            {
                var tempType = interfaceType.IsGenericType ? interfaceType.GetGenericTypeDefinition() : interfaceType;

                if (tempType == potentialSuperType)
                {
                    return true;
                }
            }
        }

        //
        // do the concrete type checks, iterating up the inheritance chain, as in orignal
        //
        while (thisType != null && thisType != typeof(object))
        {
            var cur = thisType.IsGenericType ? thisType.GetGenericTypeDefinition() : thisType;

            if (potentialSuperType == cur)
            {
                return true;
            }

            thisType = thisType.BaseType;
        }
        return false;
    }

基本上这只是System的一个扩展方法。类型-我这样做是为了故意将“thisType”类型限制为具体类型，因为我的直接用法是对类型对象的LINQ查询“where”谓词。我相信所有聪明的人都可以把它归结为一个有效的，通用的静态方法，如果你需要:)代码做了一些事情，答案的代码没有

open's it up to to general "extension" - i'm considering inheritance (think classes) as well as implementation (interfaces); method and parameter names are changed to better reflect this input null-validation (meah) input of same type (a class cannot extend itself) short-circuit execution if Type in question is an interface; because GetInterfaces() returns all implemented interfaces (even ones implemented in super-classes), you can simply loop through that collection not having to climb the inheritance tree

其余部分基本上与JaredPar的代码相同