你可以有一个专门的函数使用返回短路结果。比如这样:

def my_function_with_retries(..., max_retries=100):
    for attempt in range(max_retries):
        try:
            return my_function(...)
        except SomeSpecificException as error:
            logging.warning(f"Retrying after failed execution: {error}")

    raise SomeOtherException()

你可以有一个专门的函数使用返回短路结果。比如这样:

def my_function_with_retries(..., max_retries=100):
    for attempt in range(max_retries):
        try:
            return my_function(...)
        except SomeSpecificException as error:
            logging.warning(f"Retrying after failed execution: {error}")

    raise SomeOtherException()

我使用这个，它可以用于任何函数:

def run_with_retry(func: callable, max_retries: int = 3, wait_seconds: int = 2, **func_params):
num_retries = 1
while True:
    try:
        return func(*func_params.values())
    except Exception as e:
        if num_retries > max_retries:
            print('we have reached maximum errors and raising the exception')
            raise e
        else:
            print(f'{num_retries}/{max_retries}')
            print("Retrying error:", e)
            num_retries += 1
            sleep(wait_seconds)

像这样调用:

    def add(val1, val2):
        return val1 + val2

    run_with_retry(func=add, param1=10, param2=20)

带超时的通用解决方案:

import time

def onerror_retry(exception, callback, timeout=2, timedelta=.1):
    end_time = time.time() + timeout
    while True:
        try:
            yield callback()
            break
        except exception:
            if time.time() > end_time:
                raise
            elif timedelta > 0:
                time.sleep(timedelta)

用法:

for retry in onerror_retry(SomeSpecificException, do_stuff):
    retry()

更新2021-12-01:

自2016年6月起，不再维护重试包。 考虑使用活动的fork github.com/jd/tenacity，或者github.com/litl/backoff。

重试包是在失败时重试代码块的好方法。

例如:

@retry(wait_random_min=1000, wait_random_max=2000)
def wait_random_1_to_2_s():
    print("Randomly wait 1 to 2 seconds between retries")

这里有一个与其他解决方案类似的解决方案，但是如果在规定的次数或重试次数内没有成功，它将引发异常。

tries = 3
for i in range(tries):
    try:
        do_the_thing()
    except KeyError as e:
        if i < tries - 1: # i is zero indexed
            continue
        else:
            raise
    break