我有一个循环,开头为for I,范围为(0,100)。正常情况下,它可以正常运行,但有时由于网络条件而出现故障。目前,我已经设置它,以便在失败时,它将继续在except子句中(继续到I的下一个数字)。
我是否可以将相同的数字重新分配给i,并再次运行失败的循环迭代?
我有一个循环,开头为for I,范围为(0,100)。正常情况下,它可以正常运行,但有时由于网络条件而出现故障。目前,我已经设置它,以便在失败时,它将继续在except子句中(继续到I的下一个数字)。
我是否可以将相同的数字重新分配给i,并再次运行失败的循环迭代?
当前回答
使用递归
for i in range(100):
def do():
try:
## Network related scripts
except SpecificException as ex:
do()
do() ## invoke do() whenever required inside this loop
其他回答
如果您正在寻找的是重新尝试x次失败的尝试,那么单个for else循环可能就是您想要的。考虑这个例子,尝试了3次:
attempts = 3
for attempt in range(1, attempts+1):
try:
if attempt < 4:
raise TypeError(f"Error raised on attempt: {attempt}")
else:
print(f'Attempt {attempt} finally worked.')
except (TypeError) as error:
print(f'Attempt {attempt} hit the exception.')
continue
else:
break
else:
print(f'Exit after final attempt: {attempt}')
print(f'\nGo on to execute other code ...')
给出输出:
Attempt 1 hit the exception.
Attempt 2 hit the exception.
Attempt 3 hit the exception.
Exit after final attempt: 3
Go on to execute other code ...
再试一次它就成功了
attempts = 4
给出输出:
Attempt 1 hit the exception.
Attempt 2 hit the exception.
Attempt 3 hit the exception.
Attempt 4 finally worked.
Go on to execute other code ...
我喜欢laurent-laporte的回答。下面是我的版本,它包装在一个类与静态方法和一些例子。我实现了重试计数作为另一种重试方式。还增加了kwargs。
from typing import List
import time
class Retry:
@staticmethod
def onerror_retry(exception, callback, retries: int = 0, timeout: float = 0, timedelta: float = 0,
errors: List = None, **kwargs):
"""
@param exception: The exception to trigger retry handling with.
@param callback: The function that will potentially fail with an exception
@param retries: Optional total number of retries, regardless of timing if this threshold is met, the call will
raise the exception.
@param timeout: Optional total amount of time to do retries after which the call will raise an exception
@param timedelta: Optional amount of time to sleep in between calls
@param errors: A list to receive all the exceptions that were caught.
@param kwargs: An optional key value parameters to pass to the function to retry.
"""
for retry in Retry.__onerror_retry(exception, callback, retries, timeout, timedelta, errors, **kwargs):
if retry: retry(**kwargs) # retry will be None when all retries fail.
@staticmethod
def __onerror_retry(exception, callback, retries: int = 0, timeout: float = 0, timedelta: float = 0,
errors: List = None, **kwargs):
end_time = time.time() + timeout
continues = 0
while True:
try:
yield callback(**kwargs)
break
except exception as ex:
print(ex)
if errors:
errors.append(ex)
continues += 1
if 0 < retries < continues:
print('ran out of retries')
raise
if timeout > 0 and time.time() > end_time:
print('ran out of time')
raise
elif timedelta > 0:
time.sleep(timedelta)
err = 0
#
# sample dumb fail function
def fail_many_times(**kwargs):
global err
err += 1
max_errors = kwargs.pop('max_errors', '') or 1
if err < max_errors:
raise ValueError("I made boo boo.")
print("Successfully did something.")
#
# Example calls
try:
#
# retries with a parameter that overrides retries... just because
Retry.onerror_retry(ValueError, fail_many_times, retries=5, max_errors=3)
err = 0
#
# retries that run out of time, with 1 second sleep between retries.
Retry.onerror_retry(ValueError, fail_many_times, timeout=5, timedelta=1, max_errors=30)
except Exception as err:
print(err)
我使用这个,它可以用于任何函数:
def run_with_retry(func: callable, max_retries: int = 3, wait_seconds: int = 2, **func_params):
num_retries = 1
while True:
try:
return func(*func_params.values())
except Exception as e:
if num_retries > max_retries:
print('we have reached maximum errors and raising the exception')
raise e
else:
print(f'{num_retries}/{max_retries}')
print("Retrying error:", e)
num_retries += 1
sleep(wait_seconds)
像这样调用:
def add(val1, val2):
return val1 + val2
run_with_retry(func=add, param1=10, param2=20)
这里有一个快速装饰器来处理这个问题。7行,没有依赖关系。
def retry(exception=Exception, retries=3, delay=0):
def wrap(func):
for i in range(retries):
try:
return func()
except exception as e:
print(f'Retrying {func.__name__}: {i}/{retries}')
time.sleep(delay)
raise e
return wrap
@retry()
def do_something():
...
@retry(HTTPError, retries=100, delay=3)
def download_something():
...
可以添加的一个功能是扩展异常以处理多个异常(splat一个列表)。
不使用那些丑陋的while循环的更“功能性”的方法:
def tryAgain(retries=0):
if retries > 10: return
try:
# Do stuff
except:
retries+=1
tryAgain(retries)
tryAgain()