在编写多线程应用程序时,遇到的最常见的问题之一是竞争条件。
我对社区的问题是:
竞态条件是什么? 你如何发现它们? 你是如何处理的? 最后,你如何防止它们的发生?
在编写多线程应用程序时,遇到的最常见的问题之一是竞争条件。
我对社区的问题是:
竞态条件是什么? 你如何发现它们? 你是如何处理的? 最后,你如何防止它们的发生?
当前回答
Race conditions occur in multi-threaded applications or multi-process systems. A race condition, at its most basic, is anything that makes the assumption that two things not in the same thread or process will happen in a particular order, without taking steps to ensure that they do. This happens commonly when two threads are passing messages by setting and checking member variables of a class both can access. There's almost always a race condition when one thread calls sleep to give another thread time to finish a task (unless that sleep is in a loop, with some checking mechanism).
防止竞争条件的工具依赖于语言和操作系统,但一些常见的工具是互斥锁、临界区和信号。互斥锁在你想确保你是唯一一个在做某事的时候很有用。当你想确保别人已经完成某件事时,信号是很好的。最小化共享资源还有助于防止意外行为
Detecting race conditions can be difficult, but there are a couple signs. Code which relies heavily on sleeps is prone to race conditions, so first check for calls to sleep in the affected code. Adding particularly long sleeps can also be used for debugging to try and force a particular order of events. This can be useful for reproducing the behavior, seeing if you can make it disappear by changing the timing of things, and for testing solutions put in place. The sleeps should be removed after debugging.
但是,如果某个问题只在某些机器上断断续续地发生,则是存在竞争条件的标志性标志。常见的错误是崩溃和死锁。使用日志记录,您应该能够找到受影响的区域并从那里返回。
其他回答
下面是一个经典的银行账户余额示例,它将帮助新手轻松理解Java中的线程w.r.t.竞争条件:
public class BankAccount {
/**
* @param args
*/
int accountNumber;
double accountBalance;
public synchronized boolean Deposit(double amount){
double newAccountBalance=0;
if(amount<=0){
return false;
}
else {
newAccountBalance = accountBalance+amount;
accountBalance=newAccountBalance;
return true;
}
}
public synchronized boolean Withdraw(double amount){
double newAccountBalance=0;
if(amount>accountBalance){
return false;
}
else{
newAccountBalance = accountBalance-amount;
accountBalance=newAccountBalance;
return true;
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
BankAccount b = new BankAccount();
b.accountBalance=2000;
System.out.println(b.Withdraw(3000));
}
微软实际上已经发布了一篇关于竞态条件和死锁的非常详细的文章。最概括的摘要是标题段:
A race condition occurs when two threads access a shared variable at the same time. The first thread reads the variable, and the second thread reads the same value from the variable. Then the first thread and second thread perform their operations on the value, and they race to see which thread can write the value last to the shared variable. The value of the thread that writes its value last is preserved, because the thread is writing over the value that the previous thread wrote.
当两个或多个线程可以访问共享数据,并且它们试图同时更改数据时,就会发生竞态条件。因为线程调度算法可以在任何时候在线程之间交换,所以您不知道线程将尝试访问共享数据的顺序。因此,数据更改的结果依赖于线程调度算法,即两个线程都在“竞相”访问/更改数据。
当一个线程执行“检查-然后-行动”时,问题经常发生。“check”如果值是X,那么“act”做一些取决于值是X的事情),另一个线程在“check”和“act”之间对值做一些事情。例句:
if (x == 5) // The "Check"
{
y = x * 2; // The "Act"
// If another thread changed x in between "if (x == 5)" and "y = x * 2" above,
// y will not be equal to 10.
}
这一点是,y可以是10,也可以是任何值,这取决于在检查和执行之间是否有另一个线程改变了x。你根本不知道。
为了防止竞争条件的发生,您通常会在共享数据周围放置一个锁,以确保一次只有一个线程可以访问数据。这意味着:
// Obtain lock for x
if (x == 5)
{
y = x * 2; // Now, nothing can change x until the lock is released.
// Therefore y = 10
}
// release lock for x
考虑一个操作,该操作必须在计数增加时立即显示计数。ie。,只要CounterThread增加值,DisplayThread就需要显示最近更新的值。
int i = 0;
输出
CounterThread -> i = 1
DisplayThread -> i = 1
CounterThread -> i = 2
CounterThread -> i = 3
CounterThread -> i = 4
DisplayThread -> i = 4
在这里,CounterThread频繁地获取锁,并在DisplayThread显示它之前更新值。这里存在一个竞态条件。竞争条件可以通过使用同步来解决
我做了一个视频来解释这个。
从本质上讲,它是当你有一个跨多个线程共享的状态,在一个给定状态的第一次执行完成之前,另一个执行开始,一个给定操作的新线程的初始状态是错误的,因为前一次执行还没有完成。
由于第二次执行的初始状态是错误的,因此计算结果也是错误的。因为最终第二次执行会用错误的结果更新最终状态。
你可以在这里查看。 https://youtu.be/RWRicNoWKOY