我已经将记录插入到SQL Server数据库表中。该表定义了一个主键,并且自动递增标识种子被设置为“Yes”。这样做主要是因为在SQL Azure中,每个表都必须定义一个主键和标识。

但是由于我必须从表中删除一些记录,这些表的标识种子将受到干扰,索引列(自动生成的增量为1)也将受到干扰。

如何在删除记录后重置标识列,使该列具有升序数字顺序?

标识列在数据库中的任何地方都不能用作外键。


当前回答

DBCC CHECKIDENT ('TestTable', RESEED, 0)
GO

其中0是标识起始值

其他回答

发出2号命令就可以做到这一点

DBCC CHECKIDENT ('[TestTable]', RESEED,0)
DBCC CHECKIDENT ('[TestTable]', RESEED)

第一个将标识重置为零,下一个将其设置为下一个可用值 ——雅各

需要注意的是,如果所有的数据都是通过DELETE从表中删除的(即没有WHERE子句),那么只要a)权限允许,b)没有fk引用表(这里似乎就是这种情况),使用TRUNCATE table将是首选,因为它可以更有效地DELETE并同时重置IDENTITY种子。以下细节取自TRUNCATE TABLE的MSDN页面:

Compared to the DELETE statement, TRUNCATE TABLE has the following advantages: Less transaction log space is used. The DELETE statement removes rows one at a time and records an entry in the transaction log for each deleted row. TRUNCATE TABLE removes the data by deallocating the data pages used to store the table data and records only the page deallocations in the transaction log. Fewer locks are typically used. When the DELETE statement is executed using a row lock, each row in the table is locked for deletion. TRUNCATE TABLE always locks the table (including a schema (SCH-M) lock) and page but not each row. Without exception, zero pages are left in the table. After a DELETE statement is executed, the table can still contain empty pages. For example, empty pages in a heap cannot be deallocated without at least an exclusive (LCK_M_X) table lock. If the delete operation does not use a table lock, the table (heap) will contain many empty pages. For indexes, the delete operation can leave empty pages behind, although these pages will be deallocated quickly by a background cleanup process. If the table contains an identity column, the counter for that column is reset to the seed value defined for the column. If no seed was defined, the default value 1 is used. To retain the identity counter, use DELETE instead.

下面是:

DELETE FROM [MyTable];
DBCC CHECKIDENT ('[MyTable]', RESEED, 0);

变成:

TRUNCATE TABLE [MyTable];

请参阅TRUNCATE TABLE文档(上面有链接)以获得有关限制等的其他信息。

我尝试了@anil shahs的答案,它重置了身份。但是当插入新的行时,它得到了恒等式= 2。所以我把语法改为:

DELETE FROM [TestTable]

DBCC CHECKIDENT ('[TestTable]', RESEED, 0)
GO

那么第一行将得到恒等式= 1。

虽然大多数答案都建议RESEED到0,但很多时候我们只需要重新播种到下一个可用的Id

declare @max int
select @max=max([Id]) from [TestTable]
if @max IS NULL   --check when max is returned as null
  SET @max = 0
DBCC CHECKIDENT ('[TestTable]', RESEED, @max)

这将检查表并重置到下一个ID。

使用这个存储过程:

IF (object_id('[dbo].[pResetIdentityField]') IS NULL)
  BEGIN
    EXEC('CREATE PROCEDURE [dbo].[pResetIdentityField] AS SELECT 1 FROM DUMMY');
  END
GO

SET  ANSI_NULLS ON
GO
SET  QUOTED_IDENTIFIER ON
GO

ALTER PROCEDURE [dbo].[pResetIdentityField]
  @pSchemaName NVARCHAR(1000)
, @pTableName NVARCHAR(1000) AS
DECLARE @max   INT;
DECLARE @fullTableName   NVARCHAR(2000) = @pSchemaName + '.' + @pTableName;

DECLARE @identityColumn   NVARCHAR(1000);

SELECT @identityColumn = c.[name]
FROM sys.tables t
     INNER JOIN sys.schemas s ON t.[schema_id] = s.[schema_id]
     INNER JOIN sys.columns c ON c.[object_id] = t.[object_id]
WHERE     c.is_identity = 1
      AND t.name = @pTableName
      AND s.[name] = @pSchemaName

IF @identityColumn IS NULL
  BEGIN
    RAISERROR(
      'One of the following is true: 1. the table you specified doesn''t have an identity field, 2. you specified an invalid schema, 3. you specified an invalid table'
    , 16
    , 1);
    RETURN;
  END;

DECLARE @sqlString   NVARCHAR(MAX) = N'SELECT @maxOut = max(' + @identityColumn + ') FROM ' + @fullTableName;

EXECUTE sp_executesql @stmt = @sqlString, @params = N'@maxOut int OUTPUT', @maxOut = @max OUTPUT

IF @max IS NULL
  SET @max = 0

print(@max)

DBCC CHECKIDENT (@fullTableName, RESEED, @max)
go

--exec pResetIdentityField 'dbo', 'Table'

回顾一下我的答案。我在sql server 2008 r2中遇到了一个奇怪的行为,你应该知道。

drop table test01

create table test01 (Id int identity(1,1), descr nvarchar(10))

execute pResetIdentityField 'dbo', 'test01'

insert into test01 (descr) values('Item 1')

select * from test01

delete from test01

execute pResetIdentityField 'dbo', 'test01'

insert into test01 (descr) values('Item 1')

select * from test01

第一个选择生成0,Item 1。

第二个生成1,项目1。如果在表创建后立即执行重置,则下一个值为0。老实说,我并不惊讶微软不能把这些东西做好。我发现它是因为我有一个填充引用表的脚本文件,有时在重新创建表后运行,有时在已经创建表时运行。