我希望提供一个结构化的配置文件,它对于非技术用户来说尽可能容易编辑(不幸的是它必须是一个文件),所以我想使用YAML。然而,我找不到任何方法从Unix shell脚本解析这个。
当前回答
以下是Stefan Farestam回答的扩展版本:
function parse_yaml {
local prefix=$2
local s='[[:space:]]*' w='[a-zA-Z0-9_]*' fs=$(echo @|tr @ '\034')
sed -ne "s|,$s\]$s\$|]|" \
-e ":1;s|^\($s\)\($w\)$s:$s\[$s\(.*\)$s,$s\(.*\)$s\]|\1\2: [\3]\n\1 - \4|;t1" \
-e "s|^\($s\)\($w\)$s:$s\[$s\(.*\)$s\]|\1\2:\n\1 - \3|;p" $1 | \
sed -ne "s|,$s}$s\$|}|" \
-e ":1;s|^\($s\)-$s{$s\(.*\)$s,$s\($w\)$s:$s\(.*\)$s}|\1- {\2}\n\1 \3: \4|;t1" \
-e "s|^\($s\)-$s{$s\(.*\)$s}|\1-\n\1 \2|;p" | \
sed -ne "s|^\($s\):|\1|" \
-e "s|^\($s\)-$s[\"']\(.*\)[\"']$s\$|\1$fs$fs\2|p" \
-e "s|^\($s\)-$s\(.*\)$s\$|\1$fs$fs\2|p" \
-e "s|^\($s\)\($w\)$s:$s[\"']\(.*\)[\"']$s\$|\1$fs\2$fs\3|p" \
-e "s|^\($s\)\($w\)$s:$s\(.*\)$s\$|\1$fs\2$fs\3|p" | \
awk -F$fs '{
indent = length($1)/2;
vname[indent] = $2;
for (i in vname) {if (i > indent) {delete vname[i]; idx[i]=0}}
if(length($2)== 0){ vname[indent]= ++idx[indent] };
if (length($3) > 0) {
vn=""; for (i=0; i<indent; i++) { vn=(vn)(vname[i])("_")}
printf("%s%s%s=\"%s\"\n", "'$prefix'",vn, vname[indent], $3);
}
}'
}
该版本支持字典和列表的-符号和短符号。以下输入:
global:
input:
- "main.c"
- "main.h"
flags: [ "-O3", "-fpic" ]
sample_input:
- { property1: value, property2: "value2" }
- { property1: "value3", property2: 'value 4' }
产生如下输出:
global_input_1="main.c"
global_input_2="main.h"
global_flags_1="-O3"
global_flags_2="-fpic"
global_sample_input_1_property1="value"
global_sample_input_1_property2="value2"
global_sample_input_2_property1="value3"
global_sample_input_2_property2="value 4"
as you can see the - items automatically get numbered in order to obtain different variable names for each item. In bash there are no multidimensional arrays, so this is one way to work around. Multiple levels are supported. To work around the problem with trailing white spaces mentioned by @briceburg one should enclose the values in single or double quotes. However, there are still some limitations: Expansion of the dictionaries and lists can produce wrong results when values contain commas. Also, more complex structures like values spanning multiple lines (like ssh-keys) are not (yet) supported.
A few words about the code: The first sed command expands the short form of dictionaries { key: value, ...} to regular and converts them to more simple yaml style. The second sed call does the same for the short notation of lists and converts [ entry, ... ] to an itemized list with the - notation. The third sed call is the original one that handled normal dictionaries, now with the addition to handle lists with - and indentations. The awk part introduces an index for each indentation level and increases it when the variable name is empty (i.e. when processing a list). The current value of the counters are used instead of the empty vname. When going up one level, the counters are zeroed.
编辑:我已经为此创建了一个github存储库。
其他回答
如果你有python 2和PyYAML,你可以使用我写的这个解析器parse_yaml.py。它做的一些更整洁的事情是让您选择一个前缀(以防您有多个具有类似变量的文件),并从yaml文件中选择一个值。
例如,如果你有这些yaml文件:
staging.yaml:
db:
type: sqllite
host: 127.0.0.1
user: dev
password: password123
prod.yaml:
db:
type: postgres
host: 10.0.50.100
user: postgres
password: password123
您可以加载两者而不会产生冲突。
$ eval $(python parse_yaml.py prod.yaml --prefix prod --cap)
$ eval $(python parse_yaml.py staging.yaml --prefix stg --cap)
$ echo $PROD_DB_HOST
10.0.50.100
$ echo $STG_DB_HOST
127.0.0.1
甚至可以选择你想要的值。
$ prod_user=$(python parse_yaml.py prod.yaml --get db_user)
$ prod_port=$(python parse_yaml.py prod.yaml --get db_port --default 5432)
$ echo prod_user
postgres
$ echo prod_port
5432
perl -ne 'chomp; printf qq/%s="%s"\n/, split(/\s*:\s*/,$_,2)' file.yml > file.sh
现在做这件事的一个快速方法(以前的方法对我没用):
sudo wget https://github.com/mikefarah/yq/releases/download/v4.4.1/yq_linux_amd64 -O /usr/bin/yq &&\
sudo chmod +x /usr/bin/yq
示例asd.yaml:
a_list:
- key1: value1
key2: value2
key3: value3
解析:根
user@vm:~$ yq e '.' asd.yaml
a_list:
- key1: value1
key2: value2
key3: value3
解析key3:
user@vm:~$ yq e '.a_list[0].key3' asd.yaml
value3
我的用例可能与这篇原始文章所要求的完全相同,也可能不完全相同,但它肯定是相似的。
我需要拉一些YAML作为bash变量。YAML的深度永远不会超过一层。
YAML看起来是这样的:
KEY: value
ANOTHER_KEY: another_value
OH_MY_SO_MANY_KEYS: yet_another_value
LAST_KEY: last_value
输出如下:
KEY="value"
ANOTHER_KEY="another_value"
OH_MY_SO_MANY_KEYS="yet_another_value"
LAST_KEY="last_value"
我用这一行实现了输出:
sed -e 's/:[^:\/\/]/="/g;s/$/"/g;s/ *=/=/g' file.yaml > file.sh
s/:[^:\/\/]/="/g查找:并将其替换为=",同时忽略://(对于url) S /$/"/g将"附加到每一行的末尾 S / *=/=/g删除=前面的所有空格
我曾经使用python将yaml转换为json,并在jq中进行处理。
python -c "import yaml; import json; from pathlib import Path; print(json.dumps(yaml.safe_load(Path('file.yml').read_text())))" | jq '.'