我知道这是个老问题，但是@jmoerdyk 在你的问题中:

如何在配置文件中的链式creatatemap()表达式中使用它?

你可以像这样在Profile中使用这个答案

this.IgnoreUnmapped();
CreateMap<TSource, Tdestination>(MemberList.Destination)
.ForMember(dest => dest.SomeProp, opt => opt.MapFrom(src => src.OtherProp));

您可以使用ForAllMembers，而不是只覆盖所需 像这样

public static IMappingExpression<TSource, TDest> IgnoreAll<TSource, TDest>(this IMappingExpression<TSource, TDest> expression)
        {
            expression.ForAllMembers(opt => opt.Ignore());
            return expression;
        }

小心，它将忽略所有，如果你不添加自定义映射，它们已经被忽略，将无法工作

我还想说，如果你有AutoMapper的单元测试。你测试了所有的模型，所有的属性映射正确，你不应该使用这种扩展方法

你应该显式地写ignore

这个问题已经问了几年了，但是这个扩展方法对我来说似乎更干净，使用当前版本的AutoMapper (3.2.1):

public static IMappingExpression<TSource, TDestination> IgnoreUnmappedProperties<TSource, TDestination>(this IMappingExpression<TSource, TDestination> expression)
{
    var typeMap = Mapper.FindTypeMapFor<TSource, TDestination>();
    if (typeMap != null)
    {
        foreach (var unmappedPropertyName in typeMap.GetUnmappedPropertyNames())
        {
            expression.ForMember(unmappedPropertyName, opt => opt.Ignore());
        }
    }

    return expression;
}

版本12 这是一个非常糟糕的代码，但它解决了紧急工作。

      CreateMap<RepairPutRequest, Repair>(MemberList.None) 
                .ForAbdusselamMember(x => x.ClosedLostTimeId, y => y.MapFrom(z => z.ClosedLostTimeId))
                .ForAbdusselamMember(x => x.Explanation, y => y.MapFrom(z => z.Explanation)).IgnoreUnmapped()
                ; 

  public static class MappingExtensions
    {
        public static Dictionary<string, List<string>> list = new Dictionary<string, List<string>>();
        public static IMappingExpression<TSource, TDestination> IgnoreUnmapped<TSource, TDestination>(this IMappingExpression<TSource, TDestination> expression)
        {
             var sourceType = typeof(TSource);
            var destinationType = typeof(TDestination);
            var key =$"{sourceType.FullName}__||__{destinationType.FullName}"   ;
            var t = list[key];
            foreach (var item in destinationType.GetProperties())
            {
                if (!t.Contains(item.Name)) {
                    expression.ForMember(item.Name, x => x.Ignore());
                    }
            }
            return expression;
        }
        public static IMappingExpression<TSource, TDestination> ForAbdusselamMember<TSource, TDestination, TMember>(this IMappingExpression<TSource, TDestination> expression,
            Expression<Func<TDestination, TMember>> destinationMember, Action<IMemberConfigurationExpression<TSource, TDestination, TMember>> memberOptions )
        {
            var sourceType = typeof(TSource);
            var destinationType = typeof(TDestination);
            var key = $"{sourceType.FullName}__||__{destinationType.FullName}";
            if (!list.ContainsKey(key))
            {
                list[key]=new List<string>();
            }
            expression.ForMember(destinationMember, memberOptions);
            var memberInfo = ReflectionHelper.FindProperty(destinationMember);

            list[key].Add(memberInfo.Name);
            return expression;
        }
          
    }

我更新了Robert Schroeder对AutoMapper 4.2的答案。对于非静态映射器配置，我们不能使用mapper . getalltypemaps()，但表达式有一个对所需的TypeMap的引用:

public static IMappingExpression<TSource, TDestination> 
    IgnoreAllNonExisting<TSource, TDestination>(this IMappingExpression<TSource, TDestination> expression)
{
    foreach (var property in expression.TypeMap.GetUnmappedPropertyNames())
    {
        expression.ForMember(property, opt => opt.Ignore());
    }
    return expression;
}

我已经能够做到这一点的方式如下:

Mapper.CreateMap<SourceType, DestinationType>().ForAllMembers(opt => opt.Ignore());
Mapper.CreateMap<SourceType, DestinationType>().ForMember(/*Do explicit mapping 1 here*/);
Mapper.CreateMap<SourceType, DestinationType>().ForMember(/*Do explicit mapping 2 here*/);
...

注意:我使用的是AutoMapper v.2.0。