我有以下DataFrame(df):

import numpy as np
import pandas as pd

df = pd.DataFrame(np.random.rand(10, 5))

我通过分配添加更多列:

df['mean'] = df.mean(1)

如何将列的意思移到前面,即将其设置为第一列,而其他列的顺序保持不变?


当前回答

我认为这个函数更简单。您只需在开始或结束处或同时指定列的子集:

def reorder_df_columns(df, start=None, end=None):
    """
        This function reorder columns of a DataFrame.
        It takes columns given in the list `start` and move them to the left.
        Its also takes columns in `end` and move them to the right.
    """
    if start is None:
        start = []
    if end is None:
        end = []
    assert isinstance(start, list) and isinstance(end, list)
    cols = list(df.columns)
    for c in start:
        if c not in cols:
            start.remove(c)
    for c in end:
        if c not in cols or c in start:
            end.remove(c)
    for c in start + end:
        cols.remove(c)
    cols = start + cols + end
    return df[cols]

其他回答

这里有一个函数可以对任意数量的列执行此操作。

def mean_first(df):
    ncols = df.shape[1]        # Get the number of columns
    index = list(range(ncols)) # Create an index to reorder the columns
    index.insert(0,ncols)      # This puts the last column at the front
    return(df.assign(mean=df.mean(1)).iloc[:,index]) # new df with last column (mean) first

只需按所需顺序分配列名:

In [39]: df
Out[39]: 
          0         1         2         3         4  mean
0  0.172742  0.915661  0.043387  0.712833  0.190717     1
1  0.128186  0.424771  0.590779  0.771080  0.617472     1
2  0.125709  0.085894  0.989798  0.829491  0.155563     1
3  0.742578  0.104061  0.299708  0.616751  0.951802     1
4  0.721118  0.528156  0.421360  0.105886  0.322311     1
5  0.900878  0.082047  0.224656  0.195162  0.736652     1
6  0.897832  0.558108  0.318016  0.586563  0.507564     1
7  0.027178  0.375183  0.930248  0.921786  0.337060     1
8  0.763028  0.182905  0.931756  0.110675  0.423398     1
9  0.848996  0.310562  0.140873  0.304561  0.417808     1

In [40]: df = df[['mean', 4,3,2,1]]

现在,“mean”列出现在前面:

In [41]: df
Out[41]: 
   mean         4         3         2         1
0     1  0.190717  0.712833  0.043387  0.915661
1     1  0.617472  0.771080  0.590779  0.424771
2     1  0.155563  0.829491  0.989798  0.085894
3     1  0.951802  0.616751  0.299708  0.104061
4     1  0.322311  0.105886  0.421360  0.528156
5     1  0.736652  0.195162  0.224656  0.082047
6     1  0.507564  0.586563  0.318016  0.558108
7     1  0.337060  0.921786  0.930248  0.375183
8     1  0.423398  0.110675  0.931756  0.182905
9     1  0.417808  0.304561  0.140873  0.310562

我相信,如果你知道另一列的位置,@Aman的答案是最好的。

如果您不知道mean的位置,但只有它的名称,则不能直接使用cols=cols[-1:]+cols[:-1]。以下是我接下来能想到的最好的东西:

meanDf = pd.DataFrame(df.pop('mean'))
# now df doesn't contain "mean" anymore. Order of join will move it to left or right:
meanDf.join(df) # has mean as first column
df.join(meanDf) # has mean as last column
import numpy as np
import pandas as pd
df = pd.DataFrame()
column_names = ['x','y','z','mean']
for col in column_names: 
    df[col] = np.random.randint(0,100, size=10000)

您可以尝试以下解决方案:

解决方案1:

df = df[ ['mean'] + [ col for col in df.columns if col != 'mean' ] ]

解决方案2:


df = df[['mean', 'x', 'y', 'z']]

解决方案3:

col = df.pop("mean")
df = df.insert(0, col.name, col)

解决方案4:

df.set_index(df.columns[-1], inplace=True)
df.reset_index(inplace=True)

解决方案5:

cols = list(df)
cols = [cols[-1]] + cols[:-1]
df = df[cols]

解决方案6:

order = [1,2,3,0] # setting column's order
df = df[[df.columns[i] for i in order]]

时间比较:

解决方案1:

CPU时间:用户1.05 ms,sys:35µs,总计:1.08 ms壁时间:995µs

解决方案2:

CPU时间:用户933µs,系统:0 ns,总计:933µ壁时间:800µs

解决方案3:

CPU时间:用户0 ns,sys:1.35 ms,总计:1.35 ms壁时间:1.08 ms

解决方案4:

CPU时间:用户1.23毫秒,系统:45µs,总计:1.27毫秒壁时间:986µs

解决方案5:

CPU时间:用户1.09 ms,系统:19µs,总计:1.11 ms壁时间:949µs

解决方案6:

CPU时间:用户955µs,系统:34µs,总计:989µs壁时间:859µs

使用T怎么样?

df = df.T.reindex(['mean', 0, 1, 2, 3, 4]).T