当我需要一个简单的switchcase来调用一堆方法而不仅仅是打印一些文本时，下面的方法适用于我的情况。在玩了lambda和globals之后，我觉得这是迄今为止最简单的选择。也许它也会帮助某人：

def start():
    print("Start")

def stop():
    print("Stop")

def print_help():
    print("Help")

def choose_action(arg):
    return {
        "start": start,
        "stop": stop,
        "help": print_help,
    }.get(arg, print_help)

argument = sys.argv[1].strip()
choose_action(argument)()  # calling a method from the given string

我一直喜欢这样做

result = {
  'a': lambda x: x * 5,
  'b': lambda x: x + 7,
  'c': lambda x: x - 2
}[value](x)

从这里开始

如果你有一个复杂的大小写块，你可以考虑使用函数字典查找表。。。

如果您以前没有这样做过，那么最好进入调试器并查看字典如何查找每个函数。

注意：不要在大小写/字典查找中使用“（）”，否则将在创建字典/大小写块时调用每个函数。记住这一点，因为您只想使用哈希样式查找调用每个函数一次。

def first_case():
    print "first"

def second_case():
    print "second"

def third_case():
    print "third"

mycase = {
'first': first_case, #do not use ()
'second': second_case, #do not use ()
'third': third_case #do not use ()
}
myfunc = mycase['first']
myfunc()

运行函数的解决方案：

result = {
    'case1':     foo1, 
    'case2':     foo2,
    'case3':     foo3,
}.get(option)(parameters_optional)

其中foo1（）、foo2（）和foo3（）是函数

示例1（带参数）：

option = number['type']
result = {
    'number':     value_of_int,  # result = value_of_int(number['value'])
    'text':       value_of_text, # result = value_of_text(number['value'])
    'binary':     value_of_bin,  # result = value_of_bin(number['value'])
}.get(option)(value['value'])

示例2（无参数）：

option = number['type']
result = {
    'number':     func_for_number, # result = func_for_number()
    'text':       func_for_text,   # result = func_for_text()
    'binary':     func_for_bin,    # result = func_for_bin()
}.get(option)()

示例4（仅限值）：

option = number['type']
result = {
    'number':    lambda: 10,       # result = 10
    'text':      lambda: 'ten',    # result = 'ten'
    'binary':    lambda: 0b101111, # result = 47
}.get(option)()

我使用的解决方案：

这里发布的两个解决方案的组合，相对容易阅读，并支持默认值。

result = {
  'a': lambda x: x * 5,
  'b': lambda x: x + 7,
  'c': lambda x: x - 2
}.get(whatToUse, lambda x: x - 22)(value)

哪里

.get('c', lambda x: x - 22)(23)

在dict中查找“lambda x:x-2”，并在x=23时使用它

.get('xxx', lambda x: x - 22)(44)

在dict中找不到它，使用默认的“lambda x:x-22”，x=44。

我在谷歌搜索上找不到简单的答案。但我还是想通了。这真的很简单。决定把它贴出来，也许可以防止别人的头上少刮几下。关键是简单的“in”和元组。下面是带有直通的switch语句行为，包括RANDOM直通。

l = ['Dog', 'Cat', 'Bird', 'Bigfoot',
     'Dragonfly', 'Snake', 'Bat', 'Loch Ness Monster']

for x in l:
    if x in ('Dog', 'Cat'):
        x += " has four legs"
    elif x in ('Bat', 'Bird', 'Dragonfly'):
        x += " has wings."
    elif x in ('Snake',):
        x += " has a forked tongue."
    else:
        x += " is a big mystery by default."
    print(x)

print()

for x in range(10):
    if x in (0, 1):
        x = "Values 0 and 1 caught here."
    elif x in (2,):
        x = "Value 2 caught here."
    elif x in (3, 7, 8):
        x = "Values 3, 7, 8 caught here."
    elif x in (4, 6):
        x = "Values 4 and 6 caught here"
    else:
        x = "Values 5 and 9 caught in default."
    print(x)

提供：

Dog has four legs
Cat has four legs
Bird has wings.
Bigfoot is a big mystery by default.
Dragonfly has wings.
Snake has a forked tongue.
Bat has wings.
Loch Ness Monster is a big mystery by default.

Values 0 and 1 caught here.
Values 0 and 1 caught here.
Value 2 caught here.
Values 3, 7, 8 caught here.
Values 4 and 6 caught here
Values 5 and 9 caught in default.
Values 4 and 6 caught here
Values 3, 7, 8 caught here.
Values 3, 7, 8 caught here.
Values 5 and 9 caught in default.