我继承了一个c#类。我已经成功地“构建”了对象。但是我需要将对象序列化为XML。有什么简单的方法吗?

看起来类已经为序列化设置了,但我不确定如何获得XML表示。我的类定义是这样的:

[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.domain.com/test")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.domain.com/test", IsNullable = false)]
public partial class MyObject
{
  ...
}

以下是我认为我能做的,但它不起作用:

MyObject o = new MyObject();
// Set o properties
string xml = o.ToString();

如何获得该对象的XML表示形式?


当前回答

我将从本·格里普卡的回答开始:

public void Save(string FileName)
{
    using (var writer = new System.IO.StreamWriter(FileName))
    {
        var serializer = new XmlSerializer(this.GetType());
        serializer.Serialize(writer, this);
        writer.Flush();
    }
}

I used this code earlier. But reality showed that this solution is a bit problematic. Usually most of programmers just serialize setting on save and deserialize settings on load. This is an optimistic scenario. Once the serialization failed, because of some reason, the file is partly written, XML file is not complete and it is invalid. In consequence XML deserialization does not work and your application may crash on start. If the file is not huge, I suggest first serialize object to MemoryStream then write the stream to the File. This case is especially important if there is some complicated custom serialization. You can never test all cases.

public void Save(string fileName)
{
    //first serialize the object to memory stream,
    //in case of exception, the original file is not corrupted
    using (MemoryStream ms = new MemoryStream())
    {
        var writer = new System.IO.StreamWriter(ms);    
        var serializer = new XmlSerializer(this.GetType());
        serializer.Serialize(writer, this);
        writer.Flush();

        //if the serialization succeed, rewrite the file.
        File.WriteAllBytes(fileName, ms.ToArray());
    }
}

现实场景中的反序列化应该与损坏的序列化文件算在一起,它有时会发生。负载函数由Ben Gripka提供。

public static [ObjectType] Load(string fileName)
{
    using (var stream = System.IO.File.OpenRead(fileName))
    {
        var serializer = new XmlSerializer(typeof([ObjectType]));
        return serializer.Deserialize(stream) as [ObjectType];        
    }    
}

它可能会被一些复苏场景所包裹。它适用于设置文件或其他文件,可以删除的情况下出现问题。

public static [ObjectType] LoadWithRecovery(string fileName)
{
    try
    {
        return Load(fileName);
    }
    catch(Excetion)
    {
        File.Delete(fileName); //delete corrupted settings file
        return GetFactorySettings();
    }
}

其他回答

要序列化一个对象,请执行:

 using (StreamWriter myWriter = new StreamWriter(path, false))
 {
     XmlSerializer mySerializer = new XmlSerializer(typeof(your_object_type));
     mySerializer.Serialize(myWriter, objectToSerialize);
 }

还要记住,要使XmlSerializer工作,需要一个无参数构造函数。

我有一个简单的方法来序列化一个对象到XML使用c#,它的工作很棒,它是高度可重用的。我知道这是一个较老的帖子,但我想发布这个帖子,因为有人可能会发现这对他们有帮助。

下面是我如何调用该方法:

var objectToSerialize = new MyObject();
var xmlString = objectToSerialize.ToXmlString();

下面是完成这项工作的类:

注意:由于这些是扩展方法,它们需要在静态类中。

using System.IO;
using System.Xml.Serialization;

public static class XmlTools
{
    public static string ToXmlString<T>(this T input)
    {
        using (var writer = new StringWriter())
        {
            input.ToXml(writer);
            return writer.ToString();
        }
    }

    private static void ToXml<T>(this T objectToSerialize, StringWriter writer)
    {
        new XmlSerializer(typeof(T)).Serialize(writer, objectToSerialize);
    }
}
public string ObjectToXML(object input)
{
    try
    {
        var stringwriter = new System.IO.StringWriter();
        var serializer = new XmlSerializer(input.GetType());
        serializer.Serialize(stringwriter, input);
        return stringwriter.ToString();
    }
    catch (Exception ex)
    {
        if (ex.InnerException != null)
            ex = ex.InnerException;

        return "Could not convert: " + ex.Message;
    }
}

//Usage
var res = ObjectToXML(obj)

您需要使用以下类:

using System.IO;
using System.Xml;
using System.Xml.Serialization;

必须使用XmlSerializer进行XML序列化。下面是一个示例代码片段。

 XmlSerializer xsSubmit = new XmlSerializer(typeof(MyObject));
 var subReq = new MyObject();
 var xml = "";

 using(var sww = new StringWriter())
 {
     using(XmlWriter writer = XmlWriter.Create(sww))
     {
         xsSubmit.Serialize(writer, subReq);
         xml = sww.ToString(); // Your XML
     }
 }

根据泛型类的@kiquenet请求:

public class MySerializer<T> where T : class
{
    public static string Serialize(T obj)
    {
        XmlSerializer xsSubmit = new XmlSerializer(typeof(T));
        using (var sww = new StringWriter())
        {
            using (XmlTextWriter writer = new XmlTextWriter(sww) { Formatting = Formatting.Indented })
            {
                xsSubmit.Serialize(writer, obj);
                return sww.ToString();
            }
        }
    }
}

用法:

string xmlMessage = MySerializer<MyClass>.Serialize(myObj);

基于上述解决方案,这里有一个扩展类,您可以使用它序列化和反序列化任何对象。任何其他XML属性都由您决定。

就像这样使用它:

        string s = new MyObject().Serialize(); // to serialize into a string
        MyObject b = s.Deserialize<MyObject>();// deserialize from a string



internal static class Extensions
{
    public static T Deserialize<T>(this string value)
    {
        var xmlSerializer = new XmlSerializer(typeof(T));

        return (T)xmlSerializer.Deserialize(new StringReader(value));
    }

    public static string Serialize<T>(this T value)
    {
        if (value == null)
            return string.Empty;

        var xmlSerializer = new XmlSerializer(typeof(T));

        using (var stringWriter = new StringWriter())
        {
            using (var xmlWriter = XmlWriter.Create(stringWriter, new XmlWriterSettings { Indent = true }))
            {
                xmlSerializer.Serialize(xmlWriter, value);
                return stringWriter.ToString();
            }
        }
    }
}