我继承了一个c#类。我已经成功地“构建”了对象。但是我需要将对象序列化为XML。有什么简单的方法吗?
看起来类已经为序列化设置了,但我不确定如何获得XML表示。我的类定义是这样的:
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.domain.com/test")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.domain.com/test", IsNullable = false)]
public partial class MyObject
{
...
}
以下是我认为我能做的,但它不起作用:
MyObject o = new MyObject();
// Set o properties
string xml = o.ToString();
如何获得该对象的XML表示形式?
我的工作代码。返回utf8 xml启用空命名空间。
// override StringWriter
public class Utf8StringWriter : StringWriter
{
public override Encoding Encoding => Encoding.UTF8;
}
private string GenerateXmlResponse(Object obj)
{
Type t = obj.GetType();
var xml = "";
using (StringWriter sww = new Utf8StringWriter())
{
using (XmlWriter writer = XmlWriter.Create(sww))
{
var ns = new XmlSerializerNamespaces();
// add empty namespace
ns.Add("", "");
XmlSerializer xsSubmit = new XmlSerializer(t);
xsSubmit.Serialize(writer, obj, ns);
xml = sww.ToString(); // Your XML
}
}
return xml;
}
示例返回响应Yandex api支付Aviso url:
<?xml version="1.0" encoding="utf-8"?><paymentAvisoResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" performedDatetime="2017-09-01T16:22:08.9747654+07:00" code="0" shopId="54321" invoiceId="12345" orderSumAmount="10643" />
现在可能太晚了,但是只有用户定义的命名空间是序列化的:
public static string XmlSerialize<T>(this T obj) where T : class
{
Type serialType = typeof(T);
var xsSubmit = new XmlSerializer(serialType);
XmlWriterSettings xws = new XmlWriterSettings() { OmitXmlDeclaration = true, Indent = true };
var Namespaces = new XmlSerializerNamespaces(new XmlQualifiedName[] {
new XmlQualifiedName(string.Empty, GetXmlNameSpace(serialType) ?? string.Empty )
});
private static string GetXmlNameSpace(Type target)
{
XmlRootAttribute attribute = (XmlRootAttribute)Attribute.GetCustomAttribute(target, typeof(XmlRootAttribute));
return attribute == null ? null : attribute.Namespace;
}
并在自定义类中定义命名空间
[XmlRoot("IdentityTerminal",Namespace = "http://my-name-space/XMLSchema")]
public class IdentityTerminal
{
}
这段代码允许只使用用户定义的名称空间,而忽略默认的名称空间。