将对象序列化为XML

我继承了一个c#类。我已经成功地“构建”了对象。但是我需要将对象序列化为XML。有什么简单的方法吗?

看起来类已经为序列化设置了，但我不确定如何获得XML表示。我的类定义是这样的:

[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.domain.com/test")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.domain.com/test", IsNullable = false)]
public partial class MyObject
{
  ...
}

以下是我认为我能做的，但它不起作用:

MyObject o = new MyObject();
// Set o properties
string xml = o.ToString();

如何获得该对象的XML表示形式?

当前回答

这里有一个关于如何做到这一点的很好的教程

基本上应该使用System.Xml.Serialization.XmlSerializer类来做到这一点。

2010-11-08 12:03:29

其他回答

扩展类:

using System.IO;
using System.Xml;
using System.Xml.Serialization;

namespace MyProj.Extensions
{
    public static class XmlExtension
    {
        public static string Serialize<T>(this T value)
        {
            if (value == null) return string.Empty;

            var xmlSerializer = new XmlSerializer(typeof(T));

            using (var stringWriter = new StringWriter())
            {
                using (var xmlWriter = XmlWriter.Create(stringWriter,new XmlWriterSettings{Indent = true}))
                {
                    xmlSerializer.Serialize(xmlWriter, value);
                    return stringWriter.ToString();
                }    
            }
        }
    }
}

用法:

Foo foo = new Foo{MyProperty="I have been serialized"};

string xml = foo.Serialize();

只是引用名称空间持有您的扩展方法在文件中，你想使用它，它将工作(在我的例子中，它将是:使用myproject . extensions;)

请注意，如果您想使扩展方法只特定于一个特定的类(例如。， Foo)，你可以在扩展方法中替换T参数。

序列化(这个Foo值){…}

2014-11-27 15:30:26

我修改了我的返回一个字符串，而不是像下面这样使用一个ref变量。

public static string Serialize<T>(this T value)
{
    if (value == null)
    {
        return string.Empty;
    }
    try
    {
        var xmlserializer = new XmlSerializer(typeof(T));
        var stringWriter = new StringWriter();
        using (var writer = XmlWriter.Create(stringWriter))
        {
            xmlserializer.Serialize(writer, value);
            return stringWriter.ToString();
        }
    }
    catch (Exception ex)
    {
        throw new Exception("An error occurred", ex);
    }
}

它的用法是这样的:

var xmlString = obj.Serialize();

2013-05-31 08:43:22

我的工作代码。返回utf8 xml启用空命名空间。

// override StringWriter
public class Utf8StringWriter : StringWriter
{
    public override Encoding Encoding => Encoding.UTF8;
}

private string GenerateXmlResponse(Object obj)
{    
    Type t = obj.GetType();

    var xml = "";

    using (StringWriter sww = new Utf8StringWriter())
    {
        using (XmlWriter writer = XmlWriter.Create(sww))
        {
            var ns = new XmlSerializerNamespaces();
            // add empty namespace
            ns.Add("", "");
            XmlSerializer xsSubmit = new XmlSerializer(t);
            xsSubmit.Serialize(writer, obj, ns);
            xml = sww.ToString(); // Your XML
        }
    }
    return xml;
}

示例返回响应Yandex api支付Aviso url:

<?xml version="1.0" encoding="utf-8"?><paymentAvisoResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" performedDatetime="2017-09-01T16:22:08.9747654+07:00" code="0" shopId="54321" invoiceId="12345" orderSumAmount="10643" />

2017-09-01 09:33:20

这比调用类的ToString方法要复杂一些，但也不是很复杂。

下面是一个简单的下拉函数，可以用来序列化任何类型的对象。它返回一个包含序列化XML内容的字符串:

public string SerializeObject(object obj)
{
    System.Xml.XmlDocument xmlDoc = new System.Xml.XmlDocument();
    System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(obj.GetType());
    using (System.IO.MemoryStream ms = new System.IO.MemoryStream()) {
        serializer.Serialize(ms, obj);
        ms.Position = 0;
        xmlDoc.Load(ms);
        return xmlDoc.InnerXml;
    }
}

2010-11-08 12:13:49

必须使用XmlSerializer进行XML序列化。下面是一个示例代码片段。

 XmlSerializer xsSubmit = new XmlSerializer(typeof(MyObject));
 var subReq = new MyObject();
 var xml = "";

 using(var sww = new StringWriter())
 {
     using(XmlWriter writer = XmlWriter.Create(sww))
     {
         xsSubmit.Serialize(writer, subReq);
         xml = sww.ToString(); // Your XML
     }
 }

根据泛型类的@kiquenet请求:

public class MySerializer<T> where T : class
{
    public static string Serialize(T obj)
    {
        XmlSerializer xsSubmit = new XmlSerializer(typeof(T));
        using (var sww = new StringWriter())
        {
            using (XmlTextWriter writer = new XmlTextWriter(sww) { Formatting = Formatting.Indented })
            {
                xsSubmit.Serialize(writer, obj);
                return sww.ToString();
            }
        }
    }
}

用法:

string xmlMessage = MySerializer<MyClass>.Serialize(myObj);

2010-11-08 12:05:08

将对象序列化为XML

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