是否有办法在bash上比较这些字符串,例如:2.4.5和2.8和2.4.5.1?


当前回答

这里有一个支持修订的纯Bash解决方案(例如。“1.0-r1”),答案是基于丹尼斯·威廉姆森(Dennis Williamson)发布的答案。可以很容易地修改它以支持'-RC1'之类的东西,或者通过更改正则表达式从更复杂的字符串中提取版本。

有关实现的详细信息,请参考代码内注释和/或启用包含的调试代码:

#!/bin/bash

# Compare two version strings [$1: version string 1 (v1), $2: version string 2 (v2)]
# Return values:
#   0: v1 == v2
#   1: v1 > v2
#   2: v1 < v2
# Based on: https://stackoverflow.com/a/4025065 by Dennis Williamson
function compare_versions() {

    # Trivial v1 == v2 test based on string comparison
    [[ "$1" == "$2" ]] && return 0

    # Local variables
    local regex="^(.*)-r([0-9]*)$" va1=() vr1=0 va2=() vr2=0 len i IFS="."

    # Split version strings into arrays, extract trailing revisions
    if [[ "$1" =~ ${regex} ]]; then
        va1=(${BASH_REMATCH[1]})
        [[ -n "${BASH_REMATCH[2]}" ]] && vr1=${BASH_REMATCH[2]}
    else
        va1=($1)
    fi
    if [[ "$2" =~ ${regex} ]]; then
        va2=(${BASH_REMATCH[1]})
        [[ -n "${BASH_REMATCH[2]}" ]] && vr2=${BASH_REMATCH[2]}
    else
        va2=($2)
    fi

    # Bring va1 and va2 to same length by filling empty fields with zeros
    (( ${#va1[@]} > ${#va2[@]} )) && len=${#va1[@]} || len=${#va2[@]}
    for ((i=0; i < len; ++i)); do
        [[ -z "${va1[i]}" ]] && va1[i]="0"
        [[ -z "${va2[i]}" ]] && va2[i]="0"
    done

    # Append revisions, increment length
    va1+=($vr1)
    va2+=($vr2)
    len=$((len+1))

    # *** DEBUG ***
    #echo "TEST: '${va1[@]} (?) ${va2[@]}'"

    # Compare version elements, check if v1 > v2 or v1 < v2
    for ((i=0; i < len; ++i)); do
        if (( 10#${va1[i]} > 10#${va2[i]} )); then
            return 1
        elif (( 10#${va1[i]} < 10#${va2[i]} )); then
            return 2
        fi
    done

    # All elements are equal, thus v1 == v2
    return 0
}


# ---------- everything below this line is just for testing ----------


# Test compare_versions [$1: version string 1, $2: version string 2, $3: expected result]
function test_compare_versions() {
    local op
    compare_versions "$1" "$2"
    case $? in
        0) op="==" ;;
        1) op=">" ;;
        2) op="<" ;;
    esac
    if [[ "$op" == "$3" ]]; then
        echo -e "\e[1;32mPASS: '$1 $op $2'\e[0m"
    else
        echo -e "\e[1;31mFAIL: '$1 $3 $2' (result: '$1 $op $2')\e[0m"
    fi
}

echo -e "\nThe following tests should pass:"
while read -r test; do
    test_compare_versions $test
done << EOF
1            1            ==
2.1          2.2          <
3.0.4.10     3.0.4.2      >
4.08         4.08.01      <
3.2.1.9.8144 3.2          >
3.2          3.2.1.9.8144 <
1.2          2.1          <
2.1          1.2          >
5.6.7        5.6.7        ==
1.01.1       1.1.1        ==
1.1.1        1.01.1       ==
1            1.0          ==
1.0          1            ==
1.0.2.0      1.0.2        ==
1..0         1.0          ==
1.0          1..0         ==
1.0-r1       1.0-r3       <
1.0-r9       2.0          <
3.0-r15      3.0-r9       >
...-r1       ...-r2       <
2.0-r1       1.9.8.21-r2  >
1.0          3.8.9.32-r   <
-r           -r3          <
-r3          -r           >
-r3          -r3          ==
-r           -r           ==
0.0-r2       0.0.0.0-r2   ==
1.0.0.0-r2   1.0-r2       ==
0.0.0.1-r7   -r9          >
0.0-r0       0            ==
1.002.0-r6   1.2.0-r7     <
001.001-r2   1.1-r2       ==
5.6.1-r0     5.6.1        ==
EOF

echo -e "\nThe following tests should fail:"
while read -r test; do
    test_compare_versions $test
done << EOF
1            1            >
3.0.5-r5     3..5-r5      >
4.9.21-r3    4.8.22-r9    <
1.0-r        1.0-r1       ==
-r           1.0-r        >
-r1          0.0-r1       <
-r2          0-r2         <
EOF

其他回答

下面是另一个纯bash版本,比公认的答案要小得多。它只检查版本是否小于或等于“最小版本”,并且它将按字典顺序检查字母数字序列,这通常会给出错误的结果(举个常见的例子,“snapshot”不晚于“release”)。它将工作的主要/次要。

is_number() {
    case "$BASH_VERSION" in
        3.1.*)
            PATTERN='\^\[0-9\]+\$'
            ;;
        *)
            PATTERN='^[0-9]+$'
            ;;
    esac

    [[ "$1" =~ $PATTERN ]]
}

min_version() {
    if [[ $# != 2 ]]
    then
        echo "Usage: min_version current minimum"
        return
    fi

    A="${1%%.*}"
    B="${2%%.*}"

    if [[ "$A" != "$1" && "$B" != "$2" && "$A" == "$B" ]]
    then
        min_version "${1#*.}" "${2#*.}"
    else
        if is_number "$A" && is_number "$B"
        then
            [[ "$A" -ge "$B" ]]
        else
            [[ ! "$A" < "$B" ]]
        fi
    fi
}

这里是另一个没有任何外部调用的纯bash解决方案:

#!/bin/bash

function version_compare {

IFS='.' read -ra ver1 <<< "$1"
IFS='.' read -ra ver2 <<< "$2"

[[ ${#ver1[@]} -gt ${#ver2[@]} ]] && till=${#ver1[@]} || till=${#ver2[@]}

for ((i=0; i<${till}; i++)); do

    local num1; local num2;

    [[ -z ${ver1[i]} ]] && num1=0 || num1=${ver1[i]}
    [[ -z ${ver2[i]} ]] && num2=0 || num2=${ver2[i]}

    if [[ $num1 -gt $num2 ]]; then
        echo ">"; return 0
    elif
       [[ $num1 -lt $num2 ]]; then
        echo "<"; return 0
    fi
done

echo "="; return 0
}

echo "${1} $(version_compare "${1}" "${2}") ${2}"

还有更简单的解决方案,如果你确定所讨论的版本在第一个点后不包含前导零:

#!/bin/bash

function version_compare {

local ver1=${1//.}
local ver2=${2//.}


    if [[ $ver1 -gt $ver2 ]]; then
        echo ">"; return 0
    elif    
       [[ $ver1 -lt $ver2 ]]; then
        echo "<"; return 0
    fi 

echo "="; return 0
}

echo "${1} $(version_compare "${1}" "${2}") ${2}"

这适用于像1.2.3 vs 1.3.1 vs 0.9.7这样的版本,但不适用于其他版本 1.2.3 vs 1.2.3.0或1.01.1 vs 1.1.1

我遇到并解决了这个问题,添加了一个额外的(更短更简单的)答案…

首先注意,扩展shell比较失败了,你可能已经知道了…

    if [[ 1.2.0 < 1.12.12 ]]; then echo true; else echo false; fi
    false

使用sort -t'。'-g(或者kanaka提到的sort -V)来排序版本和简单的bash字符串比较,我找到了一个解决方案。输入文件包含列3和列4中的版本,我想对它们进行比较。这将遍历列表,确定匹配项或其中一个大于另一个。希望这仍然可以帮助那些希望使用bash尽可能简单地做到这一点的人。

while read l
do
    #Field 3 contains version on left to compare (change -f3 to required column).
    kf=$(echo $l | cut -d ' ' -f3)
    #Field 4 contains version on right to compare (change -f4 to required column).
    mp=$(echo $l | cut -d ' ' -f4)

    echo 'kf = '$kf
    echo 'mp = '$mp

    #To compare versions m.m.m the two can be listed and sorted with a . separator and the greater version found.
    gv=$(echo -e $kf'\n'$mp | sort -t'.' -g | tail -n 1)

    if [ $kf = $mp ]; then 
        echo 'Match Found: '$l
    elif [ $kf = $gv ]; then
        echo 'Karaf feature file version is greater '$l
    elif [ $mp = $gv ]; then
        echo 'Maven pom file version is greater '$l
   else
       echo 'Comparison error '$l
   fi
done < features_and_pom_versions.tmp.txt

感谢Barry的博客给出了排序的想法…… 裁判:http://bkhome.org/blog/?viewDetailed=02199

这里一个有用的技巧是字符串索引。

$ echo "${BASH_VERSION}"
4.4.23(1)-release

$ echo "${BASH_VERSION:0:1}"
4

下面是一个不使用外部命令的简单Bash函数。它适用于包含最多三个数字部分的版本字符串-小于3也是可以的。它可以很容易地扩展为更多。它实现了=、<、<=、>、>=和!=条件。

#!/bin/bash
vercmp() {
    version1=$1 version2=$2 condition=$3

    IFS=. v1_array=($version1) v2_array=($version2)
    v1=$((v1_array[0] * 100 + v1_array[1] * 10 + v1_array[2]))
    v2=$((v2_array[0] * 100 + v2_array[1] * 10 + v2_array[2]))
    diff=$((v2 - v1))
    [[ $condition = '='  ]] && ((diff == 0)) && return 0
    [[ $condition = '!=' ]] && ((diff != 0)) && return 0
    [[ $condition = '<'  ]] && ((diff >  0)) && return 0
    [[ $condition = '<=' ]] && ((diff >= 0)) && return 0
    [[ $condition = '>'  ]] && ((diff <  0)) && return 0
    [[ $condition = '>=' ]] && ((diff <= 0)) && return 0
    return 1
}

下面是测试:

for tv1 in '*' 1.1.1 2.5.3 7.3.0 0.5.7 10.3.9 8.55.32 0.0.1; do
    for tv2 in 3.1.1 1.5.3 4.3.0 0.0.7 0.3.9 11.55.32 10.0.0 '*'; do
      for c in '=' '>' '<' '>=' '<=' '!='; do
        vercmp "$tv1" "$tv2" "$c" && printf '%s\n' "$tv1 $c $tv2 is true" || printf '%s\n' "$tv1 $c $tv2 is false"
      done
    done
done

测试输出的子集:

<snip>

* >= * is true
* <= * is true
* != * is true
1.1.1 = 3.1.1 is false
1.1.1 > 3.1.1 is false
1.1.1 < 3.1.1 is true
1.1.1 >= 3.1.1 is false
1.1.1 <= 3.1.1 is true
1.1.1 != 3.1.1 is true
1.1.1 = 1.5.3 is false
1.1.1 > 1.5.3 is false
1.1.1 < 1.5.3 is true
1.1.1 >= 1.5.3 is false
1.1.1 <= 1.5.3 is true
1.1.1 != 1.5.3 is true
1.1.1 = 4.3.0 is false
1.1.1 > 4.3.0 is false

<snip>