我使用了这种方法，可能更容易掌握。获取一个根元素，然后连接到具有相同ID但不是“正式”名称的选项

  Declare @IdxList as Table(id int, choices varchar(max),AisName varchar(255))
  Insert into @IdxLIst(id,choices,AisName)
  Select IdxId,''''+Max(Title)+'''',Max(Title) From [dbo].[dta_Alias] 
 where IdxId is not null group by IdxId
  Update @IdxLIst
    set choices=choices +','''+Title+''''
    From @IdxLIst JOIN [dta_Alias] ON id=IdxId And Title <> AisName
    where IdxId is not null
    Select * from @IdxList where choices like '%,%'

当我尝试将Kevin Fairchild的建议转换为使用包含空格和编码的特殊XML字符(&，<，>)的字符串时，遇到了几个问题。

我的代码的最终版本(它没有回答最初的问题，但可能对某些人有用)看起来像这样:

CREATE TABLE #YourTable ([ID] INT, [Name] VARCHAR(MAX), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'Oranges & Lemons',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'1 < 2',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

SELECT  [ID],
  STUFF((
    SELECT ', ' + CAST([Name] AS VARCHAR(MAX))
    FROM #YourTable WHERE (ID = Results.ID) 
    FOR XML PATH(''),TYPE 
     /* Use .value to uncomment XML entities e.g. &gt; &lt; etc*/
    ).value('.','VARCHAR(MAX)') 
  ,1,2,'') as NameValues
FROM    #YourTable Results
GROUP BY ID

DROP TABLE #YourTable

它没有使用空格作为分隔符并将所有空格替换为逗号，而是在每个值前附加一个逗号和空格，然后使用STUFF删除前两个字符。

XML编码由TYPE指令自动处理。

这只是Kevin Fairchild的文章的补充(顺便说一句，非常聪明)。我本来会把它作为一个评论，但我还没有足够的分数:)

我将这个想法用于我正在工作的视图，然而我正在连接的项目包含空间。因此，我稍微修改了代码，不再使用空格作为分隔符。

再次感谢你酷炫的解决办法，凯文!

CREATE TABLE #YourTable ( [ID] INT, [Name] CHAR(1), [Value] INT ) 

INSERT INTO #YourTable ([ID], [Name], [Value]) VALUES (1, 'A', 4) 
INSERT INTO #YourTable ([ID], [Name], [Value]) VALUES (1, 'B', 8) 
INSERT INTO #YourTable ([ID], [Name], [Value]) VALUES (2, 'C', 9) 

SELECT [ID], 
       REPLACE(REPLACE(REPLACE(
                          (SELECT [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) as A 
                           FROM   #YourTable 
                           WHERE  ( ID = Results.ID ) 
                           FOR XML PATH (''))
                        , '</A><A>', ', ')
                ,'<A>','')
        ,'</A>','') AS NameValues 
FROM   #YourTable Results 
GROUP  BY ID 

DROP TABLE #YourTable 

这类问题在这里经常被问到，解决方案将在很大程度上取决于潜在的需求:

https://stackoverflow.com/search?q=sql+pivot

and

https://stackoverflow.com/search?q=sql+concatenate

通常，如果没有动态sql、用户定义函数或游标，就没有仅使用sql的方法来完成此任务。

让我们变得非常简单:

SELECT stuff(
    (
    select ', ' + x from (SELECT 'xxx' x union select 'yyyy') tb 
    FOR XML PATH('')
    )
, 1, 2, '')

替换这一行:

select ', ' + x from (SELECT 'xxx' x union select 'yyyy') tb

你的疑问。

使用Stuff和for xml路径操作符将行连接到字符串:Group By两列——>

CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',5)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

-- retrieve each unique id and name columns and concatonate the values into one column
SELECT 
  [ID], 
  STUFF((
    SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES EACH APPLICATION : VALUE SET      
    FROM #YourTable 
    WHERE (ID = Results.ID and Name = results.[name] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID


SELECT 
  [ID],[Name] , --these are acting as the group by clause
  STUFF((
    SELECT ', '+  CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES THE VALUES FOR EACH ID NAME COMBINATION 
    FROM #YourTable 
    WHERE (ID = Results.ID and Name = results.[name] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS  NameValues
FROM #YourTable Results
GROUP BY ID, name

DROP TABLE #YourTable