使用Replace函数和FOR JSON PATH

SELECT T3.DEPT, REPLACE(REPLACE(T3.ENAME,'{"ENAME":"',''),'"}','') AS ENAME_LIST
FROM (
 SELECT DEPT, (SELECT ENAME AS [ENAME]
        FROM EMPLOYEE T2
        WHERE T2.DEPT=T1.DEPT
        FOR JSON PATH,WITHOUT_ARRAY_WRAPPER) ENAME
    FROM EMPLOYEE T1
    GROUP BY DEPT) T3

有关示例数据和更多方法，请点击这里

一个例子是

在Oracle中可以使用LISTAGG聚合函数。

原始记录

name   type
------------
name1  type1
name2  type2
name2  type3

Sql

SELECT name, LISTAGG(type, '; ') WITHIN GROUP(ORDER BY name)
FROM table
GROUP BY name

导致

name   type
------------
name1  type1
name2  type2; type3

这类问题在这里经常被问到，解决方案将在很大程度上取决于潜在的需求:

https://stackoverflow.com/search?q=sql+pivot

and

https://stackoverflow.com/search?q=sql+concatenate

通常，如果没有动态sql、用户定义函数或游标，就没有仅使用sql的方法来完成此任务。

另一个不带垃圾的例子:"，TYPE).value('(./text())[1]'，'VARCHAR(MAX)')"

WITH t AS (
    SELECT 1 n, 1 g, 1 v
    UNION ALL 
    SELECT 2 n, 1 g, 2 v
    UNION ALL 
    SELECT 3 n, 2 g, 3 v
)
SELECT g
        , STUFF (
                (
                    SELECT ', ' + CAST(v AS VARCHAR(MAX))
                    FROM t sub_t
                    WHERE sub_t.g = main_t.g
                    FOR XML PATH('')
                )
                , 1, 2, ''
        ) cg
FROM t main_t
GROUP BY g

输入-输出是

*************************   ->  *********************
*   n   *   g   *   v   *       *   g   *   cg      *
*   -   *   -   *   -   *       *   -   *   -       *
*   1   *   1   *   1   *       *   1   *   1, 2    *
*   2   *   1   *   2   *       *   2   *   3       *
*   3   *   2   *   3   *       *********************
*************************   

八年后……Microsoft SQL Server vNext数据库引擎最终增强了Transact-SQL，以直接支持分组字符串连接。社区技术预览版本1.0添加了STRING_AGG函数，CTP 1.1为STRING_AGG函数添加了WITHIN GROUP子句。

参考:https://msdn.microsoft.com/en-us/library/mt775028.aspx

使用Stuff和for xml路径操作符将行连接到字符串:Group By两列——>

CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',5)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

-- retrieve each unique id and name columns and concatonate the values into one column
SELECT 
  [ID], 
  STUFF((
    SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES EACH APPLICATION : VALUE SET      
    FROM #YourTable 
    WHERE (ID = Results.ID and Name = results.[name] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID


SELECT 
  [ID],[Name] , --these are acting as the group by clause
  STUFF((
    SELECT ', '+  CAST([Value] AS VARCHAR(MAX)) -- CONCATONATES THE VALUES FOR EACH ID NAME COMBINATION 
    FROM #YourTable 
    WHERE (ID = Results.ID and Name = results.[name] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS  NameValues
FROM #YourTable Results
GROUP BY ID, name

DROP TABLE #YourTable