最近Stack Overflow上有一群讨厌perl的人，所以我想我应该把我的“关于你最喜欢的语言你讨厌的五件事”的问题带到Stack Overflow上。拿你最喜欢的语言来说，告诉我你讨厌它的五件事。这些可能只是让你烦恼的事情，承认的设计缺陷，公认的性能问题，或任何其他类别。你只需要讨厌它，它必须是你最喜欢的语言。
不要拿它和其他语言比较，也不要谈论你已经讨厌的语言。不要用你最喜欢的语言谈论你喜欢的事情。我只是想听到你讨厌但能容忍的东西，这样你就可以使用所有其他的东西，我想听到你希望别人使用的语言。
每当有人试图把他们最喜欢的语言强加给我时，我就会问这个问题，有时是面试问题。如果有人找不出他最喜欢的工具的5个缺点，那他对它还不够了解，不能提倡它，也不能利用它赚大钱。他还没有在足够多的不同情况下使用它来充分探索它。他把它作为一种文化或宗教来倡导，这意味着如果我不选择他最喜欢的技术，我就错了。
我不在乎你用什么语言。不想使用特定的语言?那就不要。你通过尽职调查做出了明智的选择，但仍然没有使用它?好吧。有时正确的答案是“你有一个强大的编程团队，有良好的实践和丰富的Bar经验。改成Foo是愚蠢的。”
This is a good question for code reviews too. People who really know a codebase will have all sorts of suggestions for it, and those who don't know it so well have non-specific complaints. I ask things like "If you could start over on this project, what would you do differently?" In this fantasy land, users and programmers get to complain about anything and everything they don't like. "I want a better interface", "I want to separate the model from the view", "I'd use this module instead of this other one", "I'd rename this set of methods", or whatever they really don't like about the current situation. That's how I get a handle on how much a particular developer knows about the codebase. It's also a clue about how much of the programmer's ego is tied up in what he's telling me.
憎恨并不是衡量人们了解多少的唯一尺度，但我发现它是一个相当不错的尺度。他们讨厌的事情也让我知道他们对这个话题的思考有多好。
C++
Strings.
They are not interoperable with platform strings, so you end up using std::vector half of the time. The copy policy (copy on write or deep copy) is not defined, so performance guarantees can not be given for straightforward syntax. Sometimes they rely on STL algorithms that are not very intuitive to use. Too many libraries roll their own which are unfortunately much more comfortable to use. Unless you have to combine them.
Variety of string representations
Now, this is a little bit of a platform problem - but I still hope it would have been better when a less obstinate standard string class would have been available earlier. The following string representations I use frequently:
generic LPCTSTR,
LPC(W)STR allocated by CoTaskMemAlloc,
BSTR, _bstr _t
(w)string,
CString,
std::vector
a roll-my-own class (sigh) that adds range checking and basic operations to a (w)char * buffer of known length
Build model.
I am sick to death of all the time spent muddling around with who-includes-what, forward declarations, optimizing precompiled headers and includes to keep at least incremental build times bearable, etc. It was great in the eighties, but now? There are so many hurdles to packing up a piece of code so it can be reused that even moms dog gets bored listening to me.
Hard to parse
This makes external tools especially hard to write, and get right. And today, we C++ guys are lacking mostly in the tool chain. I love my C# reflection and delegates but I can live without them. Without great refactoring, I can't.
Threading is too hard
Language doesn't even recognize it (by now), and the freedoms of the compiler - while great - are to painful.
Static and on-demand initialization
Technically, I cheat here: this is another puzzle piece in the "wrap up code for reuse": It's a nightmare to get something initialized only when it is needed. The best solution to all other redist problems is throwing everything into headers, this problem says "neeener - you cannot".
诚然，其中许多内容超出了严格的语言范围，但在我看来，整个工具链都需要进行判断和发展。
Python,:
No switch keyword. And NO, dictionary is not a replacement for it. Not even a bunch of elif statements.
Inconsistent line break handling. Why can I do:
test = (1,
2,
3)
And not:
from itertools import cycle,
islice,
izip
Why can't I do:
if stuff \
and foo \
or bar:
return "Formated string with %(arg)s" % \
{'arg': "bloody slash"}
without using slashes?
There is not one obvious and only one way to do it. Python fails on its motto just like Java failed on "Write once run anywhere".
# what somebody from an another language would do
if not test.has_key('foo'):
test['foo'] = 0
n = test['foo'] = test['foo'] + 1
vs
# what an agnostic beginer would do
try:
test['foo'] += 1
except KeyError:
test['foo'] = 1
n = test['foo']
vs
# what you end up after looking for dictionary default value in the python doc
test.setdefault('foo', 0)
n = test['foo'] = test['foo'] + 1
vs
# what I would do
n = test['foo'] = test.get('foo', 0) + 1
And the worst is that they don't do exactly the same thing. There are subtle differences.
Choice between spaces and tabs. There should be no choice. Pick on, set it in stone and stop fighting.
Why can you do that:
test = {}
test['foo'] = 0
but not:
test = []
test[] = 0
附注:" ".join(l)是优秀的人。不要抱怨它，这并不明显，但考虑到迭代器模式，这是正确的方法。
