HyperTalk:

很久很久以前就死了 没有简单的赋值(你不能说a:= 3，你必须说把3放进a 没有嵌套函数 没有真正的数据结构，只有字符串。要创建“列表”，您可以使用itemDelimiter分隔项并手动转义它们。你也可以得到行和单词比如txt的第5行第2个单词

说句题外话，我认为HyperTalk最酷的独特功能之一是特殊的it变量:

ask "How many years old are you?"
answer "You are " & it*12 & " months old."

我自己最讨厌c++的5个地方:

自动生成构造函数、析构函数和赋值操作符。伙计，每当我在课上没有声明什么东西时，这意味着我不需要它，而不是我忘记了。你们这些编辑们，听到了吗?!

[4]模板语法。哦，我真的需要输入所有这些“<”和“>”，每当我决定从类主体提取定义?

[3]字符串。天啊，我受够了“const char*”，我必须处理NULL情况，我必须浪费O(N)来获得它的长度，我必须为concat操作分配缓冲区。

[2] Macroprocessing。每当我不明白，什么是我的编译器，我开始寻找宏。

[1]操作符重载。我看到代码“A + B * C”，在我看到A、B和C的实际类型之前，我说不出这个代码是关于什么的。

Haskell

Sometimes the type system feels backwards. What if I don't want the compiler to infer types for my variables? What if I want the opposite, where it does constraint checking on said variables? For example, instead of inferring the type of the elements of a list, it instead makes sure that they all belong to a particular typeclass. This is a subtle but huge difference that makes it difficult for me to program UIs. It can be done, but it takes more effort than it does in some other languages. Haskell rocks for the non-UI parts, but the UI I leave to an untyped language. Allowing the construction of infinite values leads to some really frustrating errors sometimes. NoMonomorphismRestriction. Bytestring handling bites me in the ass sometimes and you don't know it until your program crashes because you mixed them up improperly. Something is wrong here, when we are losing type information that should have prevented this. Typeclasses should be automatically derived for trivial cases, like witness types, but there's a strong potential for abuse there.

我讨厌内梅尔的五个方面:

局部函数不能让步 编译lambda的能力有时取决于它是否内联 元组的值/引用类型语义不一致 数组下标和类型参数之间偶尔会出现歧义 缺乏普遍采用

Java

已检查的异常 类型擦除 缺少操作符重载(例如BigInteger/BigDecimal) 缺少regexp/date/duration /复杂文字 对不可变性的支持很差

Python,:

No switch keyword. And NO, dictionary is not a replacement for it. Not even a bunch of elif statements. Inconsistent line break handling. Why can I do: test = (1, 2, 3) And not: from itertools import cycle, islice, izip Why can't I do: if stuff \ and foo \ or bar: return "Formated string with %(arg)s" % \ {'arg': "bloody slash"} without using slashes? There is not one obvious and only one way to do it. Python fails on its motto just like Java failed on "Write once run anywhere". # what somebody from an another language would do if not test.has_key('foo'): test['foo'] = 0 n = test['foo'] = test['foo'] + 1 vs # what an agnostic beginer would do try: test['foo'] += 1 except KeyError: test['foo'] = 1 n = test['foo'] vs # what you end up after looking for dictionary default value in the python doc test.setdefault('foo', 0) n = test['foo'] = test['foo'] + 1 vs # what I would do n = test['foo'] = test.get('foo', 0) + 1 And the worst is that they don't do exactly the same thing. There are subtle differences. Choice between spaces and tabs. There should be no choice. Pick on, set it in stone and stop fighting. Why can you do that: test = {} test['foo'] = 0 but not: test = [] test[] = 0

附注:" ".join(l)是优秀的人。不要抱怨它，这并不明显，但考虑到迭代器模式，这是正确的方法。