有没有办法用JavaScript生成指定范围内的随机数?
例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。
有没有办法用JavaScript生成指定范围内的随机数?
例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。
当前回答
如果您想覆盖负数和正数,并确保其安全,请使用以下方法:
JS解决方案:
function generateRangom(low, up) {
const u = Math.max(low, up);
const l = Math.min(low, up);
const diff = u - l;
const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r; //add the random number that was selected within distance between low and up to the lower limit.
}
Java解决方案:
public static int generateRandom(int low, int up) {
int l = Math.min(low, up);
int u = Math.max(low, up);
int diff = u - l;
int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r;//add the random number that was selected within distance between low and up to the lower limit.
}
其他回答
jsfiddle:https://jsfiddle.net/cyGwf/477/
随机整数:要获得最小值和最大值之间的随机整数,请使用以下代码
function getRandomInteger(min, max) {
min = Math.ceil(min);
max = Math.floor(max);
return Math.floor(Math.random() * (max - min)) + min;
}
随机浮点数:要获得最小值和最大值之间的随机浮点数,请使用以下代码
function getRandomFloat(min, max) {
return Math.random() * (max - min) + min;
}
参考:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/random
我写了一个更灵活的函数,它可以给你随机数,而不仅仅是整数。
function rand(min,max,interval)
{
if (typeof(interval)==='undefined') interval = 1;
var r = Math.floor(Math.random()*(max-min+interval)/interval);
return r*interval+min;
}
var a = rand(0,10); //can be 0, 1, 2 (...) 9, 10
var b = rand(4,6,0.1); //can be 4.0, 4.1, 4.2 (...) 5.9, 6.0
固定版本。
对于大数字。
var min_num = 900;
var max_num = 1000;
while(true){
let num_random = Math.random()* max_num;
console.log('input : '+num_random);
if(num_random >= min_num){
console.log(Math.floor(num_random));
break;
} else {
console.log(':::'+Math.floor(num_random));
}
}
如果您想覆盖负数和正数,并确保其安全,请使用以下方法:
JS解决方案:
function generateRangom(low, up) {
const u = Math.max(low, up);
const l = Math.min(low, up);
const diff = u - l;
const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r; //add the random number that was selected within distance between low and up to the lower limit.
}
Java解决方案:
public static int generateRandom(int low, int up) {
int l = Math.min(low, up);
int u = Math.max(low, up);
int diff = u - l;
int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r;//add the random number that was selected within distance between low and up to the lower limit.
}
TL;博士
function generateRandomInteger(min, max) {
return Math.floor(min + Math.random()*(max - min + 1))
}
要获得随机数generateRandomInteger(-20,20);
下面的解释
整数-不是分数的数字;整数
我们需要得到一个随机数,比如最小值和最大值之间的X。十、 min和max都是整数
即最小<=X<=最大
如果我们从方程中减去min,这相当于
0<=(X-最小)<=(最大-最小)
现在,让我们将其与随机数r相乘这是
0<=(X-分钟)*r<=(最大-分钟)*r
现在,让我们把min加回到等式中
最小<=最小+(X-最小)*r<=最小值+(最大-最小)*r
对于任何给定的X,只有当r的范围为[0,1]时,上述方程才满足。对于r的任何其他值,上述方程都不满足。
在此处了解范围[x,y]或(x,y)的更多信息
我们的下一步是找到一个函数,该函数总是产生范围为[0,1]的值
现在,r的范围,即[0,1]与Javascript中的Math.random()函数非常相似。不是吗?
函数的作用是:返回浮点伪随机范围[0,1)内的数字;即从0(含0)到但不包括1(不含)
使用Math.Random()的随机函数0<=r<1
注意,在Math.random()中,左边界是包含的,右边界是排他的。这意味着min+(max-min)*r的取值范围为[min,max)
为了包括我们的右边界,即[min,max],我们将右边界增加1,并将结果下限。
function generateRandomInteger(min, max) {
return Math.floor(min + Math.random()*(max - min + 1))
}
要获得随机数
generateRandomInteger(-20,20);