我一直在安卓SDK平台上工作，现在还不清楚如何保存应用程序的状态。因此，考虑到“你好，Android”示例的这个小的重新设计：
package com.android.hello;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;
public class HelloAndroid extends Activity {
private TextView mTextView = null;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mTextView = new TextView(this);
if (savedInstanceState == null) {
mTextView.setText("Welcome to HelloAndroid!");
} else {
mTextView.setText("Welcome back.");
}
setContentView(mTextView);
}
}
我认为这对于最简单的情况来说已经足够了，但无论我如何离开应用程序，它总是以第一条消息来响应。
我确信解决方案就像重写onPause之类的东西一样简单，但我已经在文档中翻了大约30分钟，没有发现任何明显的东西。
使用Android ViewModel和SavedStateHandle持久化可序列化数据
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
ActivityMainBinding binding = ActivityMainBinding.inflate(getLayoutInflater());
binding.setViewModel(new ViewModelProvider(this).get(ViewModel.class));
binding.setLifecycleOwner(this);
setContentView(binding.getRoot());
}
public static class ViewModel extends AndroidViewModel {
//This field SURVIVE the background process reclaim/killing & the configuration change
public final SavedStateHandle savedStateHandle;
//This field NOT SURVIVE the background process reclaim/killing but SURVIVE the configuration change
public final MutableLiveData<String> inputText2 = new MutableLiveData<>();
public ViewModel(@NonNull Application application, SavedStateHandle savedStateHandle) {
super(application);
this.savedStateHandle = savedStateHandle;
}
}
}
在布局文件中
<?xml version="1.0" encoding="utf-8"?>
<layout xmlns:android="http://schemas.android.com/apk/res/android">
<data>
<variable
name="viewModel"
type="com.xxx.viewmodelsavedstatetest.MainActivity.ViewModel" />
</data>
<LinearLayout xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
tools:context=".MainActivity">
<EditText
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:autofillHints=""
android:hint="This field SURVIVE the background process reclaim/killing & the configuration change"
android:text='@={(String)viewModel.savedStateHandle.getLiveData("activity_main/inputText", "")}' />
<SeekBar
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:max="100"
android:progress='@={(Integer)viewModel.savedStateHandle.getLiveData("activity_main/progress", 50)}' />
<EditText
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="This field SURVIVE the background process reclaim/killing & the configuration change"
android:text='@={(String)viewModel.savedStateHandle.getLiveData("activity_main/inputText", "")}' />
<SeekBar
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:max="100"
android:progress='@={(Integer)viewModel.savedStateHandle.getLiveData("activity_main/progress", 50)}' />
<EditText
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="This field NOT SURVIVE the background process reclaim/killing but SURVIVE the configuration change"
android:text='@={viewModel.inputText2}' />
</LinearLayout>
</layout>
测试：
1. start the test activity
2. press home key to go home
3. adb shell kill <the test activity process>
4. open recent app list and restart the test activity
我想我找到了答案。让我简单地说一下我做了什么：
假设我有两个活动，即活动1和活动2，我正在从活动1导航到活动2（我在活动2中做了一些工作），然后通过单击活动1中的按钮再次返回活动1。现在在这个阶段，我想回到活动2，我想看到我的活动2处于上次离开活动2时的相同状态。
对于上述场景，我所做的是在清单中进行了如下更改：
<activity android:name=".activity2"
android:alwaysRetainTaskState="true"
android:launchMode="singleInstance">
</activity>
在活动1的按钮点击事件中，我这样做了：
Intent intent = new Intent();
intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT);
intent.setClassName(this,"com.mainscreen.activity2");
startActivity(intent);
在活动2的按钮点击事件中，我这样做了：
Intent intent=new Intent();
intent.setClassName(this,"com.mainscreen.activity1");
startActivity(intent);
现在将要发生的是，我们在activity2中所做的任何更改都不会丢失，并且我们可以以与之前相同的状态查看activity2。
我相信这就是答案，这对我来说很好。如果我错了，请纠正我。
现在，在视图模型中使用两种方法是有意义的。如果要将第一个保存为保存的实例：您可以像这样在视图模型中添加状态参数https://developer.android.com/topic/libraries/architecture/viewmodel-savedstate#java
或者您可以在视图模型中保存变量或对象，在这种情况下，视图模型将保存生命周期，直到活动被破坏。
public class HelloAndroidViewModel extends ViewModel {
public Booelan firstInit = false;
public HelloAndroidViewModel() {
firstInit = false;
}
...
}
public class HelloAndroid extends Activity {
private TextView mTextView = null;
HelloAndroidViewModel viewModel = ViewModelProviders.of(this).get(HelloAndroidViewModel.class);
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mTextView = new TextView(this);
//Because even if the state is deleted, the data in the viewmodel will be kept because the activity does not destroy
if(!viewModel.firstInit){
viewModel.firstInit = true
mTextView.setText("Welcome to HelloAndroid!");
}else{
mTextView.setText("Welcome back.");
}
setContentView(mTextView);
}
}
虽然公认的答案是正确的，但有一种更快、更容易的方法可以使用名为Icepick的库在Android上保存“活动”状态。Icepick是一个注释处理器，它负责为您保存和恢复状态时使用的所有样板代码。
对Icepick:
class MainActivity extends Activity {
@State String username; // These will be automatically saved and restored
@State String password;
@State int age;
@Override public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Icepick.restoreInstanceState(this, savedInstanceState);
}
@Override public void onSaveInstanceState(Bundle outState) {
super.onSaveInstanceState(outState);
Icepick.saveInstanceState(this, outState);
}
}
与执行以下操作相同：
class MainActivity extends Activity {
String username;
String password;
int age;
@Override
public void onSaveInstanceState(Bundle savedInstanceState) {
super.onSaveInstanceState(savedInstanceState);
savedInstanceState.putString("MyString", username);
savedInstanceState.putString("MyPassword", password);
savedInstanceState.putInt("MyAge", age);
/* remember you would need to actually initialize these variables before putting it in the
Bundle */
}
@Override
public void onRestoreInstanceState(Bundle savedInstanceState) {
super.onRestoreInstanceState(savedInstanceState);
username = savedInstanceState.getString("MyString");
password = savedInstanceState.getString("MyPassword");
age = savedInstanceState.getInt("MyAge");
}
}
Icepick可以处理任何使用Bundle保存其状态的对象。
