我一直在安卓SDK平台上工作,现在还不清楚如何保存应用程序的状态。因此,考虑到“你好,Android”示例的这个小的重新设计:

package com.android.hello;

import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;

public class HelloAndroid extends Activity {

  private TextView mTextView = null;

  /** Called when the activity is first created. */
  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    mTextView = new TextView(this);

    if (savedInstanceState == null) {
       mTextView.setText("Welcome to HelloAndroid!");
    } else {
       mTextView.setText("Welcome back.");
    }

    setContentView(mTextView);
  }
}

我认为这对于最简单的情况来说已经足够了,但无论我如何离开应用程序,它总是以第一条消息来响应。

我确信解决方案就像重写onPause之类的东西一样简单,但我已经在文档中翻了大约30分钟,没有发现任何明显的东西。


当前回答

要获取存储在onCreate()中的活动状态数据,首先必须通过重写SaveInstanceState(Bundle savedInstanceState)方法将数据保存在savedInstanceStatus中。

当调用activity destroy SaveInstanceState(Bundle savedInstanceState)方法并保存要保存的数据时。当活动重新启动时,在onCreate()中也会得到同样的结果。(savedInstanceState不会为空,因为在活动被破坏之前,您已经在其中保存了一些数据)

其他回答

要获取存储在onCreate()中的活动状态数据,首先必须通过重写SaveInstanceState(Bundle savedInstanceState)方法将数据保存在savedInstanceStatus中。

当调用activity destroy SaveInstanceState(Bundle savedInstanceState)方法并保存要保存的数据时。当活动重新启动时,在onCreate()中也会得到同样的结果。(savedInstanceState不会为空,因为在活动被破坏之前,您已经在其中保存了一些数据)

使用Android ViewModel和SavedStateHandle持久化可序列化数据

public class MainActivity extends AppCompatActivity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        ActivityMainBinding binding = ActivityMainBinding.inflate(getLayoutInflater());
        binding.setViewModel(new ViewModelProvider(this).get(ViewModel.class));
        binding.setLifecycleOwner(this);
        setContentView(binding.getRoot());
    }

    public static class ViewModel extends AndroidViewModel {

        //This field SURVIVE the background process reclaim/killing & the configuration change
        public final SavedStateHandle savedStateHandle;

        //This field NOT SURVIVE the background process reclaim/killing but SURVIVE the configuration change
        public final MutableLiveData<String> inputText2 = new MutableLiveData<>();


        public ViewModel(@NonNull Application application, SavedStateHandle savedStateHandle) {
            super(application);
            this.savedStateHandle = savedStateHandle;
        }
    }
}

在布局文件中

<?xml version="1.0" encoding="utf-8"?>
<layout xmlns:android="http://schemas.android.com/apk/res/android">

    <data>

        <variable
            name="viewModel"
            type="com.xxx.viewmodelsavedstatetest.MainActivity.ViewModel" />
    </data>

    <LinearLayout xmlns:tools="http://schemas.android.com/tools"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:orientation="vertical"
        tools:context=".MainActivity">


        <EditText
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:autofillHints=""
            android:hint="This field SURVIVE the background process reclaim/killing &amp; the configuration change"
            android:text='@={(String)viewModel.savedStateHandle.getLiveData("activity_main/inputText", "")}' />

        <SeekBar
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:max="100"
            android:progress='@={(Integer)viewModel.savedStateHandle.getLiveData("activity_main/progress", 50)}' />

        <EditText
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="This field SURVIVE the background process reclaim/killing &amp; the configuration change"
            android:text='@={(String)viewModel.savedStateHandle.getLiveData("activity_main/inputText", "")}' />

        <SeekBar
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:max="100"
            android:progress='@={(Integer)viewModel.savedStateHandle.getLiveData("activity_main/progress", 50)}' />

        <EditText
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="This field NOT SURVIVE the background process reclaim/killing but SURVIVE the configuration change"
            android:text='@={viewModel.inputText2}' />

    </LinearLayout>
</layout>

测试:

1. start the test activity
2. press home key to go home
3. adb shell kill <the test activity process>
4. open recent app list and restart the test activity

我想我找到了答案。让我简单地说一下我做了什么:

假设我有两个活动,即活动1和活动2,我正在从活动1导航到活动2(我在活动2中做了一些工作),然后通过单击活动1中的按钮再次返回活动1。现在在这个阶段,我想回到活动2,我想看到我的活动2处于上次离开活动2时的相同状态。

对于上述场景,我所做的是在清单中进行了如下更改:

<activity android:name=".activity2"
          android:alwaysRetainTaskState="true"      
          android:launchMode="singleInstance">
</activity>

在活动1的按钮点击事件中,我这样做了:

Intent intent = new Intent();
intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT);
intent.setClassName(this,"com.mainscreen.activity2");
startActivity(intent);

在活动2的按钮点击事件中,我这样做了:

Intent intent=new Intent();
intent.setClassName(this,"com.mainscreen.activity1");
startActivity(intent);

现在将要发生的是,我们在activity2中所做的任何更改都不会丢失,并且我们可以以与之前相同的状态查看activity2。

我相信这就是答案,这对我来说很好。如果我错了,请纠正我。

现在,在视图模型中使用两种方法是有意义的。如果要将第一个保存为保存的实例:您可以像这样在视图模型中添加状态参数https://developer.android.com/topic/libraries/architecture/viewmodel-savedstate#java

或者您可以在视图模型中保存变量或对象,在这种情况下,视图模型将保存生命周期,直到活动被破坏。

public class HelloAndroidViewModel extends ViewModel {
   public Booelan firstInit = false;

    public HelloAndroidViewModel() {
        firstInit = false;
    }
    ...
}

public class HelloAndroid extends Activity {

  private TextView mTextView = null;
  HelloAndroidViewModel viewModel = ViewModelProviders.of(this).get(HelloAndroidViewModel.class);
  /** Called when the activity is first created. */
  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    mTextView = new TextView(this);

    //Because even if the state is deleted, the data in the viewmodel will be kept because the activity does not destroy
    if(!viewModel.firstInit){
        viewModel.firstInit = true
        mTextView.setText("Welcome to HelloAndroid!");
    }else{
       mTextView.setText("Welcome back.");
    }

    setContentView(mTextView);
  }
}

虽然公认的答案是正确的,但有一种更快、更容易的方法可以使用名为Icepick的库在Android上保存“活动”状态。Icepick是一个注释处理器,它负责为您保存和恢复状态时使用的所有样板代码。

对Icepick:

class MainActivity extends Activity {
  @State String username; // These will be automatically saved and restored
  @State String password;
  @State int age;

  @Override public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    Icepick.restoreInstanceState(this, savedInstanceState);
  }

  @Override public void onSaveInstanceState(Bundle outState) {
    super.onSaveInstanceState(outState);
    Icepick.saveInstanceState(this, outState);
  }
}

与执行以下操作相同:

class MainActivity extends Activity {
  String username;
  String password;
  int age;

  @Override
  public void onSaveInstanceState(Bundle savedInstanceState) {
    super.onSaveInstanceState(savedInstanceState);
    savedInstanceState.putString("MyString", username);
    savedInstanceState.putString("MyPassword", password);
    savedInstanceState.putInt("MyAge", age); 
    /* remember you would need to actually initialize these variables before putting it in the
    Bundle */
  }

  @Override
  public void onRestoreInstanceState(Bundle savedInstanceState) {
    super.onRestoreInstanceState(savedInstanceState);
    username = savedInstanceState.getString("MyString");
    password = savedInstanceState.getString("MyPassword");
    age = savedInstanceState.getInt("MyAge");
  }
}

Icepick可以处理任何使用Bundle保存其状态的对象。