让我们把你的优秀和最喜欢的扩展方法列一个列表。

要求是必须发布完整的代码,以及如何使用它的示例和解释。

基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。

请将您的回答标记为接受,以便将代码放入Codeplex项目。

请张贴完整的源代码,而不是一个链接。

Codeplex上新闻:

24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/

11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。

11.11.2008仍有发展空间。;-)现在就加入!

11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen

11.11.2008 FormatWith现在是实现和单元测试。

09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。

我们需要更多的开发人员。: -)

09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。


当前回答

这是一个位图扩展,可以将位图转换为灰度;

public static Bitmap GrayScale(this Bitmap bitmap)
{
    Bitmap newBitmap = new Bitmap(bitmap.Width, bitmap.Height);
    Graphics g = Graphics.FromImage(newBitmap);

    //the grayscale ColorMatrix
    ColorMatrix colorMatrix = new ColorMatrix(new float[][] {
            new float[] {.3f, .3f, .3f, 0, 0},
            new float[] {.59f, .59f, .59f, 0, 0},
            new float[] {.11f, .11f, .11f, 0, 0},
            new float[] {0, 0, 0, 1, 0},
            new float[] {0, 0, 0, 0, 1}
    });

    ImageAttributes attributes = new ImageAttributes();
    attributes.SetColorMatrix(colorMatrix);
    g.DrawImage(bitmap, new Rectangle(0, 0, bitmap.Width, bitmap.Height), 0, 0, bitmap.Width, bitmap.Height, GraphicsUnit.Pixel, attributes);
    g.Dispose();
    return newBitmap;
}

示例用法:

Bitmap grayscaled = bitmap.GrayScale()

其他回答

// Checks for an empty collection, and sends the value set in the default constructor for the desired field
public static TResult MinGuarded<T, TResult>(this IEnumerable<T> items, Func<T, TResult> expression) where T : new() {
    if(items.IsEmpty()) {
        return (new List<T> { new T() }).Min(expression);
    }
    return items.Min(expression);
}

// Checks for an empty collection, and sends the value set in the default constructor for the desired field
public static TResult MaxGuarded<T, TResult>(this IEnumerable<T> items, Func<T, TResult> expression) where T : new() {
    if(items.IsEmpty()) {
        return (new List<T> { new T() }).Max(expression);
    }
    return items.Max(expression);
}

我不确定是否有更好的方法来做到这一点,但这个扩展是非常有用的,每当我想要控制我的对象中的字段的默认值。 例如,如果我想控制DateTime的值,并希望根据我的业务逻辑进行设置,那么我可以在默认构造函数中这样做。否则,它将显示为DateTime.MinDate。

扩展方法:

public static void AddRange<T, S>(this ICollection<T> list, params S[] values)
    where S : T
{
    foreach (S value in values)
        list.Add(value);
}

该方法适用于所有类型,并允许您将一系列项作为参数添加到列表中。

例子:

var list = new List<Int32>();
list.AddRange(5, 4, 8, 4, 2);

我还没有看到任何关于这个问题的答案…

public static string[] Split(this string value, string regexPattern)
{
    return value.Split(regexPattern, RegexOptions.None);
}

public static string[] Split(this string value, string regexPattern, 
    RegexOptions options)
{
    return Regex.Split(value, regexPattern, options);
}

用法:

var obj = "test1,test2,test3";
string[] arrays = obj.Split(",");

类似于上面的字符串As和Is,但对所有对象都是全局的。

这很简单,但我经常使用这些方法来缓解拳击中的parens爆炸。

public static class ExtensionMethods_Object
{
    [DebuggerStepThrough()]
    public static bool Is<T>(this object item) where T : class
    {
        return item is T;
    }

    [DebuggerStepThrough()]
    public static bool IsNot<T>(this object item) where T : class
    {
        return !(item.Is<T>());
    }

    [DebuggerStepThrough()]
    public static T As<T>(this object item) where T : class
    {
        return item as T;
    }
}

我很高兴这段代码能在codeplex上使用,事实上它已经在使用了。

// This file contains extension methods for generic List<> class to operate on sorted lists.
// Duplicate values are OK.
// O(ln(n)) is still much faster then the O(n) of LINQ's searches/filters.
static partial class SortedList
{
    // Return the index of the first element with the key greater then provided.
    // If there's no such element within the provided range, it returns iAfterLast.
    public static int sortedFirstGreaterIndex<tElt, tKey>( this IList<tElt> list, Func<tElt, tKey, int> comparer, tKey key, int iFirst, int iAfterLast )
    {
        if( iFirst < 0 || iAfterLast < 0 || iFirst > list.Count || iAfterLast > list.Count )
            throw new IndexOutOfRangeException();
        if( iFirst > iAfterLast )
            throw new ArgumentException();
        if( iFirst == iAfterLast )
            return iAfterLast;

        int low = iFirst, high = iAfterLast;
        // The code below is inspired by the following article:
        // http://en.wikipedia.org/wiki/Binary_search#Single_comparison_per_iteration
        while( low < high )
        {
            int mid = ( high + low ) / 2;
            // 'mid' might be 'iFirst' in case 'iFirst+1 == iAfterLast'.
            // 'mid' will never be 'iAfterLast'.
            if( comparer( list[ mid ], key ) <= 0 ) // "<=" since we gonna find the first "greater" element
                low = mid + 1;
            else
                high = mid;
        }
        return low;
    }

    // Return the index of the first element with the key greater then the provided key.
    // If there's no such element, returns list.Count.
    public static int sortedFirstGreaterIndex<tElt, tKey>( this IList<tElt> list, Func<tElt, tKey, int> comparer, tKey key )
    {
        return list.sortedFirstGreaterIndex( comparer, key, 0, list.Count );
    }

    // Add an element to the sorted array.
    // This could be an expensive operation if frequently adding elements that sort firstly.
    // This is cheap operation when adding elements that sort near the tail of the list.
    public static int sortedAdd<tElt>( this List<tElt> list, Func<tElt, tElt, int> comparer, tElt elt )
    {
        if( list.Count == 0 || comparer( list[ list.Count - 1 ], elt ) <= 0 )
        {
            // either the list is empty, or the item is greater then all elements already in the collection.
            list.Add( elt );
            return list.Count - 1;
        }
        int ind = list.sortedFirstGreaterIndex( comparer, elt );
        list.Insert( ind, elt );
        return ind;
    }

    // Find first exactly equal element, return -1 if not found.
    public static int sortedFindFirstIndex<tElt, tKey>( this List<tElt> list, Func<tElt, tKey, int> comparer, tKey elt )
    {
        int low = 0, high = list.Count - 1;

        while( low < high )
        {
            int mid = ( high + low ) / 2;
            if( comparer( list[ mid ], elt ) < 0 )
                low = mid + 1;
            else
                high = mid; // this includes the case when we've found an element exactly matching the key
        }
        if( high >= 0 && 0 == comparer( list[ high ], elt ) )
            return high;
        return -1;
    }

    // Return the IEnumerable that returns array elements in the reverse order.
    public static IEnumerable<tElt> sortedReverse<tElt>( this List<tElt> list )
    {
        for( int i=list.Count - 1; i >= 0; i-- )
            yield return list[ i ];
    }
}