一些用于使用列表的扩展:

/// <summary>
/// Wrap an object in a list
/// </summary>
public static IList<T> WrapInList<T>(this T item)
{
    List<T> result = new List<T>();
    result.Add(item);
    return result;
}

使用如:

myList = someObject.InList();

使IEnumerable包含来自一个或多个源的项，以使IEnumerable更像列表。对于高性能代码来说，这可能不是一个好主意，但对于测试来说很有用:

public static IEnumerable<T> Append<T>(this IEnumerable<T> enumerable, T newItem)
{
    foreach (T item in enumerable)
    {
        yield return item;
    }

    yield return newItem;
}

public static IEnumerable<T> Append<T>(this IEnumerable<T> enumerable, params T[] newItems)
{
    foreach (T item in enumerable)
    {
        yield return item;
    }

    foreach (T newItem in newItems)
    {
        yield return newItem;
    }
}

如使用。

someEnumeration = someEnumeration.Append(newItem);

还有其他可能的变化——例如。

someEnumeration = someEnumeration.Append(otherEnumeration);

如果你正在克隆项目，你可能还想克隆它们的列表:

public static IList<T> Clone<T>(this IEnumerable<T> source) where T: ICloneable
{
    List<T> result = new List<T>();

    foreach (T item in source)
    {
        result.Add((T)item.Clone());
    }

    return result;
}

当我使用ObservableCollection<T>时，我通常使用AddRange方法扩展它。这里的其他答案给出了这个的实现。

如果您愿意，可以将此代码放入Codeplex项目中。

无论如何，把它放在codeplex项目中。

将对象序列化/反序列化为XML:

/// <summary>Serializes an object of type T in to an xml string</summary>
/// <typeparam name="T">Any class type</typeparam>
/// <param name="obj">Object to serialize</param>
/// <returns>A string that represents Xml, empty otherwise</returns>
public static string XmlSerialize<T>(this T obj) where T : class, new()
{
    if (obj == null) throw new ArgumentNullException("obj");

    var serializer = new XmlSerializer(typeof(T));
    using (var writer = new StringWriter())
    {
        serializer.Serialize(writer, obj);
        return writer.ToString();
    }
}

/// <summary>Deserializes an xml string in to an object of Type T</summary>
/// <typeparam name="T">Any class type</typeparam>
/// <param name="xml">Xml as string to deserialize from</param>
/// <returns>A new object of type T is successful, null if failed</returns>
public static T XmlDeserialize<T>(this string xml) where T : class, new()
{
    if (xml == null) throw new ArgumentNullException("xml");

    var serializer = new XmlSerializer(typeof(T));
    using (var reader = new StringReader(xml))
    {
        try { return (T)serializer.Deserialize(reader); }
        catch { return null; } // Could not be deserialized to this type.
    }
}

我在我的web项目中使用这些，主要是MVC。我为ViewData和TempData写了一些这样的代码

/// <summary>
/// Checks the Request.QueryString for the specified value and returns it, if none 
/// is found then the default value is returned instead
/// </summary>
public static T QueryValue<T>(this HtmlHelper helper, string param, T defaultValue) {
    object value = HttpContext.Current.Request.QueryString[param] as object;
    if (value == null) { return defaultValue; }
    try {
        return (T)Convert.ChangeType(value, typeof(T));
    } catch (Exception) {
        return defaultValue;
    }
}

这样我就可以写……

<% if (Html.QueryValue("login", false)) { %>
    <div>Welcome Back!</div>

<% } else { %>
    <%-- Render the control or something --%>

<% } %>

日期时间扩展

例子:

DateTime firstDayOfMonth = DateTime.Now.First();
DateTime lastdayOfMonth = DateTime.Now.Last();
DateTime lastFridayInMonth = DateTime.Now.Last(DayOfWeek.Friday);
DateTime nextFriday = DateTime.Now.Next(DayOfWeek.Friday);
DateTime lunchTime = DateTime.Now.SetTime(11, 30);
DateTime noonOnFriday = DateTime.Now.Next(DayOfWeek.Friday).Noon();
DateTime secondMondayOfMonth = DateTime.Now.First(DayOfWeek.Monday).Next(DayOfWeek.Monday).Midnight();

这些有用吗?

public static bool CoinToss(this Random rng)
{
    return rng.Next(2) == 0;
}

public static T OneOf<T>(this Random rng, params T[] things)
{
    return things[rng.Next(things.Length)];
}

Random rand;
bool luckyDay = rand.CoinToss();
string babyName = rand.OneOf("John", "George", "Radio XBR74 ROCKS!");

将double类型转换为使用指定区域性格式化的字符串:

public static class ExtensionMethods 
{
  public static string ToCurrency(this double value, string cultureName)
  {
    CultureInfo currentCulture = new CultureInfo(cultureName);
    return (string.Format(currentCulture, "{0:C}", value));
  }
}

例子:

double test = 154.20;
string testString = test.ToCurrency("en-US"); // $154.20