如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案，但其他方法是受欢迎的
当前回答
查找SQL reference (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)中所有表的行数的最快方法
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC
其他回答
SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
Sum(B.rows)AS RecordCount
FROM sys.objects A INNER JOIN sys.partitions B
ON A.object_id = B.object_id WHERE A.type = 'U'
GROUP BY A.schema_id,A.NAME ;
QUERY_PHOTO
QUERY_RESULT_PHOTO
首先想到的是使用sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
但是它没有列出表名，所以可以扩展到
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
这里的问题是，如果数据库有超过100个表，你会得到以下错误消息:
查询已超过最大值 可以的结果集的数目 显示在结果网格中。只有 前100个结果集是 显示在网格中。
所以我最终使用表变量来存储结果
declare @stats table (n sysname, c int)
insert into @stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from @stats
order by c desc
我在http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021上找到了一个帮助我的片段:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;
接受的答案在Azure SQL上不适合我，这里有一个，它非常快，完全符合我的要求:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc
SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;
