如果你想优雅地处理空输入，并忽略项目的顺序，尝试以下解决方案:

static class Extensions
{
    public static bool ItemsEqual<TSource>(this TSource[] array1, TSource[] array2)
    {
        if (array1 == null && array2 == null)
            return true;
        if (array1 == null || array2 == null)
            return false;
        if (array1.Count() != array2.Count())
            return false;
        return !array1.Except(array2).Any() && !array2.Except(array1).Any();
    }
}

测试代码如下所示:

public static void Main()
{
    int[] a1 = new int[] { 1, 2, 3 };
    int[] a2 = new int[] { 3, 2, 1 };
    int[] a3 = new int[] { 1, 3 };
    Console.WriteLine(a1.ItemsEqual(a2)); // Output: True.
    Console.WriteLine(a2.ItemsEqual(a3)); // Output: False.
    Console.WriteLine(a3.ItemsEqual(a2)); // Output: False.
   
    int[] a4 = new int[] { 1, 1 };
    int[] a5 = new int[] { 1, 2 };
    Console.WriteLine(a4.ItemsEqual(a5)); // Output: False 
    Console.WriteLine(a5.ItemsEqual(a4)); // Output: False 
    
    int[] a6 = null;
    int[] a7 = null;
    int[] a8 = new int[0];

    Console.WriteLine(a6.ItemsEqual(a7)); // Output: True. No Exception.
    Console.WriteLine(a8.ItemsEqual(a6)); // Output: False. No Exception.
    Console.WriteLine(a7.ItemsEqual(a8)); // Output: False. No Exception.
}

对于。net 4.0及更高版本，您可以通过使用structuralcompare类型比较数组或元组中的元素:

object[] a1 = { "string", 123, true };
object[] a2 = { "string", 123, true };

Console.WriteLine (a1 == a2);        // False (because arrays is reference types)
Console.WriteLine (a1.Equals (a2));  // False (because arrays is reference types)

IStructuralEquatable se1 = a1;
//Next returns True
Console.WriteLine (se1.Equals (a2, StructuralComparisons.StructuralEqualityComparer)); 

Elementwise比较?是什么

public void Linq78a()
{
 int[] numbers1 = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };
 int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };
 bool bb = numbers.Zip(numbers1, (a, b) => (a == b)).Any(p => !p);
 if (!bb) Console.WriteLine("Lists are equal (bb)");
   else Console.WriteLine("Lists are not equal (bb)");
}

将(a==b)条件替换为您想在a和b中进行比较的任何内容。

(这结合了来自MSDN开发者Linq的两个例子)

对于某些应用可能更好:

string.Join(",", arr1) == string.Join(",", arr2)

如果您不想比较顺序，但确实想比较每一项的计数，包括处理空值，那么我为此编写了一个扩展方法。

例如，它给出了以下结果:

new int?[]{  }.IgnoreOrderComparison(new int?{ });                            // true
new int?[]{ 1 }.IgnoreOrderComparison(new int?{ });                           // false
new int?[]{ }.IgnoreOrderComparison(new int?{ 1 });                           // false
new int?[]{ 1 }.IgnoreOrderComparison(new int?{ 1 });                         // true
new int?[]{ 1, 2 }.IgnoreOrderComparison(new int?{ 2, 1 });                   // true
new int?[]{ 1, 2, null }.IgnoreOrderComparison(new int?{ 2, 1 });             // false
new int?[]{ 1, 2, null }.IgnoreOrderComparison(new int?{ null, 2, 1 });       // true
new int?[]{ 1, 2, null, null }.IgnoreOrderComparison(new int?{ null, 2, 1 }); // false
new int?[]{ 2 }.IgnoreOrderComparison(new int?{ 2, 2 });                      // false
new int?[]{ 2, 2 }.IgnoreOrderComparison(new int?{ 2, 2 });                   // true

代码如下:

public static class ArrayComparisonExtensions
{
    public static bool IgnoreOrderComparison<TSource>(this IEnumerable<TSource> first, IEnumerable<TSource> second) =>
        IgnoreOrderComparison(first, second, EqualityComparer<TSource>.Default);

    public static bool IgnoreOrderComparison<TSource>(this IEnumerable<TSource> first, IEnumerable<TSource> second, IEqualityComparer<TSource> comparer)
    {
        var a = ToDictionary(first, out var firstNullCount);
        var b = ToDictionary(second, out var secondNullCount);

        if (a.Count != b.Count)
            return false;

        if (firstNullCount != secondNullCount)
            return false;

        foreach (var item in a)
        {
            if (b.TryGetValue(item.Key, out var count) && item.Value == count)
                continue;
            return false;
        }


        return true;

        Dictionary<TSource, int> ToDictionary(IEnumerable<TSource> items, out int nullCount)
        {
            nullCount = 0;
            var result = new Dictionary<TSource, int>(comparer);
            foreach (var item in items)
            {
                if (item is null)
                    nullCount++;
                else if (result.TryGetValue(item, out var count))
                    result[item] = count + 1;
                else
                    result[item] = 1;
            }

            return result;
        }
    }
}

它只枚举每个枚举对象一次，但它确实为每个枚举对象创建了一个字典，并迭代这些字典一次。我对如何改善这一点很感兴趣。

也可以使用array1.ToList()。All(x => array2.Contains(x))如果您需要比较顺序不相同的数组