在Java中,arrays .equals()允许轻松地比较两个基本数组的内容(重载可用于所有基本类型)。
c#中有这样的东西吗?在c#中是否存在比较两个数组内容的“神奇”方法?
在Java中,arrays .equals()允许轻松地比较两个基本数组的内容(重载可用于所有基本类型)。
c#中有这样的东西吗?在c#中是否存在比较两个数组内容的“神奇”方法?
当前回答
对于。net 4.0及更高版本,您可以通过使用structuralcompare类型比较数组或元组中的元素:
object[] a1 = { "string", 123, true };
object[] a2 = { "string", 123, true };
Console.WriteLine (a1 == a2); // False (because arrays is reference types)
Console.WriteLine (a1.Equals (a2)); // False (because arrays is reference types)
IStructuralEquatable se1 = a1;
//Next returns True
Console.WriteLine (se1.Equals (a2, StructuralComparisons.StructuralEqualityComparer));
其他回答
我在视觉工作室做了这个,效果非常好;用简短的此代码逐个索引地比较数组。
private void compareButton_Click(object sender, EventArgs e)
{
int[] answer = { 1, 3, 4, 6, 8, 9, 5, 4, 0, 6 };
int[] exam = { 1, 2, 3, 6, 8, 9, 5, 4, 0, 7 };
int correctAnswers = 0;
int wrongAnswers = 0;
for (int index = 0; index < answer.Length; index++)
{
if (answer[index] == exam[index])
{
correctAnswers += 1;
}
else
{
wrongAnswers += 1;
}
}
outputLabel.Text = ("The matching numbers are " + correctAnswers +
"\n" + "The non matching numbers are " + wrongAnswers);
}
输出将是;匹配的数字是7 不匹配的数字是3
你可以使用Enumerable。相交:
int[] array1 = new int[] { 1, 2, 3, 4,5 },
array2 = new int[] {7,8};
if (array1.Intersect(array2).Any())
Console.WriteLine("matched");
else
Console.WriteLine("not matched");
你可以使用Enumerable.SequenceEqual。这适用于任何IEnumerable<T>,而不仅仅是数组。
Elementwise比较?是什么
public void Linq78a()
{
int[] numbers1 = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };
int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };
bool bb = numbers.Zip(numbers1, (a, b) => (a == b)).Any(p => !p);
if (!bb) Console.WriteLine("Lists are equal (bb)");
else Console.WriteLine("Lists are not equal (bb)");
}
将(a==b)条件替换为您想在a和b中进行比较的任何内容。
(这结合了来自MSDN开发者Linq的两个例子)
如果你想优雅地处理空输入,并忽略项目的顺序,尝试以下解决方案:
static class Extensions
{
public static bool ItemsEqual<TSource>(this TSource[] array1, TSource[] array2)
{
if (array1 == null && array2 == null)
return true;
if (array1 == null || array2 == null)
return false;
if (array1.Count() != array2.Count())
return false;
return !array1.Except(array2).Any() && !array2.Except(array1).Any();
}
}
测试代码如下所示:
public static void Main()
{
int[] a1 = new int[] { 1, 2, 3 };
int[] a2 = new int[] { 3, 2, 1 };
int[] a3 = new int[] { 1, 3 };
Console.WriteLine(a1.ItemsEqual(a2)); // Output: True.
Console.WriteLine(a2.ItemsEqual(a3)); // Output: False.
Console.WriteLine(a3.ItemsEqual(a2)); // Output: False.
int[] a4 = new int[] { 1, 1 };
int[] a5 = new int[] { 1, 2 };
Console.WriteLine(a4.ItemsEqual(a5)); // Output: False
Console.WriteLine(a5.ItemsEqual(a4)); // Output: False
int[] a6 = null;
int[] a7 = null;
int[] a8 = new int[0];
Console.WriteLine(a6.ItemsEqual(a7)); // Output: True. No Exception.
Console.WriteLine(a8.ItemsEqual(a6)); // Output: False. No Exception.
Console.WriteLine(a7.ItemsEqual(a8)); // Output: False. No Exception.
}