如何验证程序是否存在,以返回错误并退出,或继续执行脚本?

看起来应该很容易,但这让我很为难。


当前回答

仅zsh,但对于zsh脚本非常有用(例如,在编写完成脚本时):

zsh/parameter模块可以访问内部命令哈希表等。来自man zshmodules:

THE ZSH/PARAMETER MODULE
       The zsh/parameter module gives access to some of the internal hash  ta‐
       bles used by the shell by defining some special parameters.


[...]

       commands
              This  array gives access to the command hash table. The keys are
              the names of external commands, the values are the pathnames  of
              the  files  that would be executed when the command would be in‐
              voked. Setting a key in this array defines a new entry  in  this
              table  in the same way as with the hash builtin. Unsetting a key
              as in `unset "commands[foo]"' removes the entry  for  the  given
              key from the command hash table.

尽管它是一个可加载的模块,但只要zsh不与--simulate一起使用,它似乎是默认加载的。

例子:

martin@martin ~ % echo $commands[zsh]
/usr/bin/zsh

要快速检查某个命令是否可用,只需检查哈希中是否存在密钥:

if (( ${+commands[zsh]} ))
then
  echo "zsh is available"
fi

请注意,散列将包含$PATH文件夹中的任何文件,无论它们是否可执行。为了绝对确定,您必须对此进行统计:

if (( ${+commands[zsh]} )) && [[ -x $commands[zsh] ]]
then
  echo "zsh is available"
fi

其他回答

它可能更简单,只是:

#!/usr/bin/env bash                                                                
set -x                                                                             

# if local program 'foo' returns 1 (doesn't exist) then...                                                                               
if ! type -P foo; then                                                             
    echo 'crap, no foo'                                                            
else                                                                               
    echo 'sweet, we have foo!'                                                    
fi                                                                                 

将foo更改为vi以激发其他条件。

checkexists() {
    while [ -n "$1" ]; do
        [ -n "$(which "$1")" ] || echo "$1": command not found
        shift
    done
}
GIT=/usr/bin/git                     # STORE THE RELATIVE PATH
# GIT=$(which git)                   # USE THIS COMMAND TO SEARCH FOR THE RELATIVE PATH

if [[ ! -e $GIT ]]; then             # CHECK IF THE FILE EXISTS
    echo "PROGRAM DOES NOT EXIST."
    exit 1                           # EXIT THE PROGRAM IF IT DOES NOT
fi

# DO SOMETHING ...

exit 0                               # EXIT THE PROGRAM IF IT DOES
#!/bin/bash
a=${apt-cache show program}
if [[ $a == 0 ]]
then
echo "the program doesn't exist"
else
echo "the program exists"
fi

#程序不是字面意思,您可以将其更改为要检查的程序名称

这里有很多选择,但我很惊讶没有快速的一句话。这是我在脚本开始时使用的方法:

[[ "$(command -v mvn)" ]] || { echo "mvn is not installed" 1>&2 ; exit 1; }
[[ "$(command -v java)" ]] || { echo "java is not installed" 1>&2 ; exit 1; }

这是基于此处选择的答案和另一个来源。