如何验证程序是否存在,以返回错误并退出,或继续执行脚本?

看起来应该很容易,但这让我很为难。


当前回答

checkexists() {
    while [ -n "$1" ]; do
        [ -n "$(which "$1")" ] || echo "$1": command not found
        shift
    done
}

其他回答

which命令可能有用。男子谁

如果找到可执行文件,则返回0;如果找不到或不可执行,则返回1:

NAME

       which - locate a command

SYNOPSIS

       which [-a] filename ...

DESCRIPTION

       which returns the pathnames of the files which would
       be executed in the current environment, had its
       arguments been given as commands in a strictly
       POSIX-conformant shell. It does this by searching
       the PATH for executable files matching the names
       of the arguments.

OPTIONS

       -a     print all matching pathnames of each argument

EXIT STATUS

       0      if all specified commands are 
              found and executable

       1      if one or more specified commands is nonexistent
              or not executable

       2      if an invalid option is specified

这样做的好处是,它可以确定可执行文件在运行环境中是否可用-这节省了一些问题。。。

哈希变量有一个陷阱:例如,可以在命令行中键入

one_folder/process

以执行进程。为此,one_folder的父文件夹必须位于$PATH中。但当您尝试散列此命令时,它总是会成功:

hash one_folder/process; echo $? # will always output '0'

如果您检查程序是否存在,您可能会稍后运行它。为什么不先尝试运行它?

if foo --version >/dev/null 2>&1; then
    echo Found
else
    echo Not found
fi

这是一个更值得信赖的检查程序运行,而不仅仅是查看PATH目录和文件权限。

此外,您可以从程序中获得一些有用的结果,例如其版本。

当然,缺点是有些程序启动起来会很重,有些程序没有--version选项可以立即(并成功)退出。

扩展@lhunath和@GregV的答案,下面是那些希望将该检查轻松放入if语句的人的代码:

exists()
{
  command -v "$1" >/dev/null 2>&1
}

以下是使用方法:

if exists bash; then
  echo 'Bash exists!'
else
  echo 'Your system does not have Bash'
fi

仅zsh,但对于zsh脚本非常有用(例如,在编写完成脚本时):

zsh/parameter模块可以访问内部命令哈希表等。来自man zshmodules:

THE ZSH/PARAMETER MODULE
       The zsh/parameter module gives access to some of the internal hash  ta‐
       bles used by the shell by defining some special parameters.


[...]

       commands
              This  array gives access to the command hash table. The keys are
              the names of external commands, the values are the pathnames  of
              the  files  that would be executed when the command would be in‐
              voked. Setting a key in this array defines a new entry  in  this
              table  in the same way as with the hash builtin. Unsetting a key
              as in `unset "commands[foo]"' removes the entry  for  the  given
              key from the command hash table.

尽管它是一个可加载的模块,但只要zsh不与--simulate一起使用,它似乎是默认加载的。

例子:

martin@martin ~ % echo $commands[zsh]
/usr/bin/zsh

要快速检查某个命令是否可用,只需检查哈希中是否存在密钥:

if (( ${+commands[zsh]} ))
then
  echo "zsh is available"
fi

请注意,散列将包含$PATH文件夹中的任何文件,无论它们是否可执行。为了绝对确定,您必须对此进行统计:

if (( ${+commands[zsh]} )) && [[ -x $commands[zsh] ]]
then
  echo "zsh is available"
fi