是否有一种方法可以获得MySQL数据库中所有表的行计数,而无需在每个表上运行SELECT count() ?


当前回答

大多数其他答案建议使用INFORMATION_SCHEMA。但是在MySQL 8中它已经不存在了。行数已移动到INFORMATION_SCHEMA.INNODB_TABLESTATS。

你可以用以下方法查询:

SELECT *
FROM information_schema.INNODB_TABLESTATS
WHERE NAME LIKE "YOUR_DB_NAME/%"
ORDER BY NUM_ROWS DESC

请注意,这仍然是一个近似值,像以前一样,不是一个确切的数字。

其他回答

你可以用表格把一些东西组合在一起。我从来没有这样做过,但它看起来有一个列用于TABLE_ROWS和一个列用于TABLE NAME。

要获取每个表的行,你可以使用这样的查询:

SELECT table_name, table_rows
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = '**YOUR SCHEMA**';

像许多其他人一样,我很难用InnoDB在INFORMATION_SCHEMA表上获得准确的值,并且能够通过count()进行查询将无限受益,并且希望在一次查询中完成它。

首先,确保启用大规模group_concats:

SET SESSION group_concat_max_len = 1000000;

然后运行此查询以获得将为数据库运行的结果查询。

SELECT CONCAT('SELECT ', GROUP_CONCAT(table1.count SEPARATOR ',\n')) FROM (
    SELECT concat('(SELECT count(id) AS \'',table_name,' Count\' ','FROM ',table_name,') AS ',table_name,'_Count') AS 'count'
    FROM information_schema.tables 
    WHERE table_schema = '**YOUR_DATABASE_HERE**'
) AS table1

这将生成诸如…

SELECT (SELECT count(id) AS 'table1 Count' FROM table1) AS table1_Count,
   (SELECT count(id) AS 'table2 Count' FROM table2) AS table2_Count,
   (SELECT count(id) AS 'table3 Count' FROM table3) AS table3_Count;

这反过来又产生了以下结果:

*************************** 1. row ***************************
table1_Count: 1
table2_Count: 1
table3_Count: 0
SELECT SUM(TABLE_ROWS) 
     FROM INFORMATION_SCHEMA.TABLES 
     WHERE TABLE_SCHEMA = '{your_db}';

从文档中注意到:对于InnoDB表,行数只是用于SQL优化的粗略估计。您需要使用COUNT(*)来获得精确的计数(成本更高)。

基于上面@Nathan的回答,但不需要“删除最终的联合”,并带有对输出进行排序的选项,我使用以下SQL。它生成另一个SQL语句,然后运行:

select CONCAT( 'select * from (\n', group_concat( single_select SEPARATOR ' UNION\n'), '\n ) Q order by Q.exact_row_count desc') as sql_query
from (
    SELECT CONCAT(
        'SELECT "', 
        table_name, 
        '" AS table_name, COUNT(1) AS exact_row_count
        FROM `', 
        table_schema,
        '`.`',
        table_name, 
        '`'
    ) as single_select
    FROM INFORMATION_SCHEMA.TABLES 
    WHERE table_schema = 'YOUR_SCHEMA_NAME'
      and table_type = 'BASE TABLE'
) Q 

您确实需要一个足够大的group_concat_max_len服务器变量的值,但是从MariaDb 10.2.4开始,它应该默认为1M。

这个存储过程列出表,统计记录,并在最后生成记录的总数。

添加此过程后运行:

CALL `COUNT_ALL_RECORDS_BY_TABLE` ();

-

过程:

DELIMITER $$

CREATE DEFINER=`root`@`127.0.0.1` PROCEDURE `COUNT_ALL_RECORDS_BY_TABLE`()
BEGIN
DECLARE done INT DEFAULT 0;
DECLARE TNAME CHAR(255);

DECLARE table_names CURSOR for 
    SELECT table_name FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = DATABASE();

DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;

OPEN table_names;   

DROP TABLE IF EXISTS TCOUNTS;
CREATE TEMPORARY TABLE TCOUNTS 
  (
    TABLE_NAME CHAR(255),
    RECORD_COUNT INT
  ) ENGINE = MEMORY; 


WHILE done = 0 DO

  FETCH NEXT FROM table_names INTO TNAME;

   IF done = 0 THEN
    SET @SQL_TXT = CONCAT("INSERT INTO TCOUNTS(SELECT '" , TNAME  , "' AS TABLE_NAME, COUNT(*) AS RECORD_COUNT FROM ", TNAME, ")");

    PREPARE stmt_name FROM @SQL_TXT;
    EXECUTE stmt_name;
    DEALLOCATE PREPARE stmt_name;  
  END IF;

END WHILE;

CLOSE table_names;

SELECT * FROM TCOUNTS;

SELECT SUM(RECORD_COUNT) AS TOTAL_DATABASE_RECORD_CT FROM TCOUNTS;

END