也可以从外部服务获取IP。

public string GetIP()
{
    HttpClient client = new HttpClient();
    var result = client.GetStringAsync("https://jsonip.com/").Result;
    var ip = JsonSerializer.Deserialize<RemoteIPDto>(result.ToString()).IP;
    return ip;
}

RemoteIPDto类在哪里

public class RemoteIPDto
{
    [JsonPropertyName("ip")]
    public string IP { get; set; }
    [JsonPropertyName("geo-ip")]
    public string GeoIp { get; set; }
    [JsonPropertyName("API Help")]
    public string ApiHelp { get; set; }
}

在。net 5中，我使用它通过AWS fargate上的容器来检索客户端IP。

public static class HttpContextExtensions
{
    //https://gist.github.com/jjxtra/3b240b31a1ed3ad783a7dcdb6df12c36

    public static IPAddress GetRemoteIPAddress(this HttpContext context, bool allowForwarded = true)
    {
        if (allowForwarded)
        {
            string header = (context.Request.Headers["CF-Connecting-IP"].FirstOrDefault() ?? context.Request.Headers["X-Forwarded-For"].FirstOrDefault());
            if (IPAddress.TryParse(header, out IPAddress ip))
            {
                return ip;
            }
        }
        return context.Connection.RemoteIpAddress;
    }
}

你这样称呼它:

var ipFromExtensionMethod = HttpContext.GetRemoteIPAddress().ToString();

源

可以添加一些回退逻辑来处理负载均衡器的存在。

此外，通过检查，即使没有负载均衡器，X-Forwarded-For报头也会被设置(可能是因为额外的Kestrel层?):

public string GetRequestIP(bool tryUseXForwardHeader = true)
{
    string ip = null;

    // todo support new "Forwarded" header (2014) https://en.wikipedia.org/wiki/X-Forwarded-For

    // X-Forwarded-For (csv list):  Using the First entry in the list seems to work
    // for 99% of cases however it has been suggested that a better (although tedious)
    // approach might be to read each IP from right to left and use the first public IP.
    // http://stackoverflow.com/a/43554000/538763
    //
    if (tryUseXForwardHeader)
        ip = GetHeaderValueAs<string>("X-Forwarded-For").SplitCsv().FirstOrDefault();

    // RemoteIpAddress is always null in DNX RC1 Update1 (bug).
    if (ip.IsNullOrWhitespace() && _httpContextAccessor.HttpContext?.Connection?.RemoteIpAddress != null)
        ip = _httpContextAccessor.HttpContext.Connection.RemoteIpAddress.ToString();

    if (ip.IsNullOrWhitespace())
        ip = GetHeaderValueAs<string>("REMOTE_ADDR");

    // _httpContextAccessor.HttpContext?.Request?.Host this is the local host.

    if (ip.IsNullOrWhitespace())
        throw new Exception("Unable to determine caller's IP.");

    return ip;
}

public T GetHeaderValueAs<T>(string headerName)
{
    StringValues values;

    if (_httpContextAccessor.HttpContext?.Request?.Headers?.TryGetValue(headerName, out values) ?? false)
    {
        string rawValues = values.ToString();   // writes out as Csv when there are multiple.

        if (!rawValues.IsNullOrWhitespace())
            return (T)Convert.ChangeType(values.ToString(), typeof(T));
    }
    return default(T);
}

public static List<string> SplitCsv(this string csvList, bool nullOrWhitespaceInputReturnsNull = false)
{
    if (string.IsNullOrWhiteSpace(csvList))
        return nullOrWhitespaceInputReturnsNull ? null : new List<string>();

    return csvList
        .TrimEnd(',')
        .Split(',')
        .AsEnumerable<string>()
        .Select(s => s.Trim())
        .ToList();
}

public static bool IsNullOrWhitespace(this string s)
{
    return String.IsNullOrWhiteSpace(s);
}

假设_httpContextAccessor通过DI提供。

首先，在。net Core 1.0中 使用Microsoft.AspNetCore.Http.Features添加;到控制器 然后里面的相关方法:

var ip = HttpContext.Features.Get<IHttpConnectionFeature>()?.RemoteIpAddress?.ToString();

我读了其他几个答案，因为它使用了小写的httpContext，导致VS使用Microsoft.AspNetCore添加。Http，而不是适当的使用，或与HttpContext(编译器也是误导)。

第一次添加

Microsoft.AspNetCore.Http
services.AddSingleton<IHttpContextAccessor, HttpContextAccessor>();

在Startup.cs中的ConfigureServices中 然后在控制器中添加以下代码

   private IHttpContextAccessor _accessor;
    
  public LoginController(IHttpContextAccessor accessor)
            {
              _accessor = accessor;
            }

  public IEnumerable<string> Get()
        {
         var ip = _accessor.HttpContext?.Connection?.RemoteIpAddress?.ToString();
         return new string[] { ip, "value" };
        }

希望这对你有用

我发现，你们中的一些人发现你们得到的IP地址是:::1或0.0.0.1

这是一个问题，因为你试图从你自己的机器获取IP，而c#试图返回IPv6的混乱。

所以，我实现了来自@Johna (https://stackoverflow.com/a/41335701/812720)和@David (https://stackoverflow.com/a/8597351/812720)的答案，感谢他们!

下面是解决方案:

add Microsoft.AspNetCore.HttpOverrides Package in your References (Dependencies/Packages) add this line in Startup.cs public void Configure(IApplicationBuilder app, IHostingEnvironment env) { // your current code // start code to add // to get ip address app.UseForwardedHeaders(new ForwardedHeadersOptions { ForwardedHeaders = ForwardedHeaders.XForwardedFor | ForwardedHeaders.XForwardedProto }); // end code to add } to get IPAddress, use this code in any of your Controller.cs IPAddress remoteIpAddress = Request.HttpContext.Connection.RemoteIpAddress; string result = ""; if (remoteIpAddress != null) { // If we got an IPV6 address, then we need to ask the network for the IPV4 address // This usually only happens when the browser is on the same machine as the server. if (remoteIpAddress.AddressFamily == System.Net.Sockets.AddressFamily.InterNetworkV6) { remoteIpAddress = System.Net.Dns.GetHostEntry(remoteIpAddress).AddressList .First(x => x.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork); } result = remoteIpAddress.ToString(); }

现在你可以从remoteIpAddress或result获取IPv4地址