首先，在。net Core 1.0中 使用Microsoft.AspNetCore.Http.Features添加;到控制器 然后里面的相关方法:

var ip = HttpContext.Features.Get<IHttpConnectionFeature>()?.RemoteIpAddress?.ToString();

我读了其他几个答案，因为它使用了小写的httpContext，导致VS使用Microsoft.AspNetCore添加。Http，而不是适当的使用，或与HttpContext(编译器也是误导)。

您可以使用IHttpConnectionFeature来获取此信息。

var remoteIpAddress = httpContext.GetFeature<IHttpConnectionFeature>()?.RemoteIpAddress;

var remoteIpAddress = HttpContext.Features.Get<IHttpConnectionFeature>()?.RemoteIpAddress;

我发现，你们中的一些人发现你们得到的IP地址是:::1或0.0.0.1

这是一个问题，因为你试图从你自己的机器获取IP，而c#试图返回IPv6的混乱。

所以，我实现了来自@Johna (https://stackoverflow.com/a/41335701/812720)和@David (https://stackoverflow.com/a/8597351/812720)的答案，感谢他们!

下面是解决方案:

add Microsoft.AspNetCore.HttpOverrides Package in your References (Dependencies/Packages) add this line in Startup.cs public void Configure(IApplicationBuilder app, IHostingEnvironment env) { // your current code // start code to add // to get ip address app.UseForwardedHeaders(new ForwardedHeadersOptions { ForwardedHeaders = ForwardedHeaders.XForwardedFor | ForwardedHeaders.XForwardedProto }); // end code to add } to get IPAddress, use this code in any of your Controller.cs IPAddress remoteIpAddress = Request.HttpContext.Connection.RemoteIpAddress; string result = ""; if (remoteIpAddress != null) { // If we got an IPV6 address, then we need to ask the network for the IPV4 address // This usually only happens when the browser is on the same machine as the server. if (remoteIpAddress.AddressFamily == System.Net.Sockets.AddressFamily.InterNetworkV6) { remoteIpAddress = System.Net.Dns.GetHostEntry(remoteIpAddress).AddressList .First(x => x.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork); } result = remoteIpAddress.ToString(); }

现在你可以从remoteIpAddress或result获取IPv4地址

API已经更新。不知道它什么时候改变了，但根据达米安·爱德华兹在12月底的说法，你现在可以这样做:

var remoteIpAddress = request.HttpContext.Connection.RemoteIpAddress;

也可以从外部服务获取IP。

public string GetIP()
{
    HttpClient client = new HttpClient();
    var result = client.GetStringAsync("https://jsonip.com/").Result;
    var ip = JsonSerializer.Deserialize<RemoteIPDto>(result.ToString()).IP;
    return ip;
}

RemoteIPDto类在哪里

public class RemoteIPDto
{
    [JsonPropertyName("ip")]
    public string IP { get; set; }
    [JsonPropertyName("geo-ip")]
    public string GeoIp { get; set; }
    [JsonPropertyName("API Help")]
    public string ApiHelp { get; set; }
}