我想从设备中检索并显示SMS消息?


当前回答

使用内容解析器(" Content://sms/inbox")来读取收件箱中的sms。

// public static final String INBOX = "content://sms/inbox";
// public static final String SENT = "content://sms/sent";
// public static final String DRAFT = "content://sms/draft";
Cursor cursor = getContentResolver().query(Uri.parse("content://sms/inbox"), null, null, null, null);

if (cursor.moveToFirst()) { // must check the result to prevent exception
    do {
       String msgData = "";
       for(int idx=0;idx<cursor.getColumnCount();idx++)
       {
           msgData += " " + cursor.getColumnName(idx) + ":" + cursor.getString(idx);
       }
       // use msgData
    } while (cursor.moveToNext());
} else {
   // empty box, no SMS
}

请添加READ_SMS权限。

其他回答

从API 19开始,你可以使用Telephony类;因为硬核值不会在每个设备中检索消息,因为内容提供程序Uri会因设备和制造商而变化。

public void getAllSms(Context context) {

    ContentResolver cr = context.getContentResolver();
    Cursor c = cr.query(Telephony.Sms.CONTENT_URI, null, null, null, null);
    int totalSMS = 0;
    if (c != null) {
        totalSMS = c.getCount();
        if (c.moveToFirst()) {
            for (int j = 0; j < totalSMS; j++) {
                String smsDate = c.getString(c.getColumnIndexOrThrow(Telephony.Sms.DATE));
                String number = c.getString(c.getColumnIndexOrThrow(Telephony.Sms.ADDRESS));
                String body = c.getString(c.getColumnIndexOrThrow(Telephony.Sms.BODY));
                Date dateFormat= new Date(Long.valueOf(smsDate));
                String type;
                switch (Integer.parseInt(c.getString(c.getColumnIndexOrThrow(Telephony.Sms.TYPE)))) {
                    case Telephony.Sms.MESSAGE_TYPE_INBOX:
                        type = "inbox";
                        break;
                    case Telephony.Sms.MESSAGE_TYPE_SENT:
                        type = "sent";
                        break;
                    case Telephony.Sms.MESSAGE_TYPE_OUTBOX:
                        type = "outbox";
                        break;
                    default:
                        break;
                }


                c.moveToNext();
            }
        }

        c.close();

    } else {
        Toast.makeText(this, "No message to show!", Toast.LENGTH_SHORT).show();
    }
}

Hier是一个很棒的视频教程!!!!效果非常好!!

这是一个组合从谷歌表列表与数字和一个Android应用程序。(非常容易遵循教程也没有编码员!!

点击链接进入教程:

https://www.youtube.com/watch?v=PReU4ITp37I&list=PLuB9drjjGa0QvFzWq_bwO8bOTRaWpdP_d&index=2

下面是谷歌应用程序脚本的代码:

const SHEET_URL = "https://docs.google.com/spreadsheets/d/16_fp7lQsnaMLaDYMVsE5YxsohQBANllEVcZeMP5ZpiU/edit#gid=0";
const SHEET_NAME = "SMS";

const doGet = () => {
  const sheet = SpreadsheetApp.openByUrl(SHEET_URL).getSheetByName(SHEET_NAME);
  const [header, ...data] = sheet.getDataRange().getDisplayValues();
  

  const PHONE = header.indexOf("Phone");
  const TEXT = header.indexOf("Text");
  const STATUS = header.indexOf("Status");

  const output = [];

 data.forEach((row, index) => {
  if (row[STATUS] === "") {
    output.push([index+1, row[PHONE], row[TEXT]]);
  }
});

const json = JSON.stringify(output);

return ContentService.createTextOutput(json).setMimeType(ContentService.MimeType.TEXT);
}

const doPost = (e) => {
  const sheet = SpreadsheetApp.openByUrl(SHEET_URL).getSheetByName(SHEET_NAME);
  const [header] = sheet.getRange("A1:1").getValues();
  const STATUS = header.indexOf("Status");
  var rowId = Number(e.parameter.row);
  sheet.getRange(rowId + 1, STATUS +1).setValue("SMS Sent");
  return ContentService.createTextOutput("").setMimeType(ContentService.MimeType.TEXT);
}

然后你只需要跟随视频的第二部分他在MIT APP Inventer中构建Android应用程序。我做了一个截图来看看这个项目

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
        final String myPackageName = getPackageName();
        if (!Telephony.Sms.getDefaultSmsPackage(this).equals(myPackageName)) {

            Intent intent = new Intent(Telephony.Sms.Intents.ACTION_CHANGE_DEFAULT);
            intent.putExtra(Telephony.Sms.Intents.EXTRA_PACKAGE_NAME, myPackageName);
            startActivityForResult(intent, 1);
        }else {
            List<Sms> lst = getAllSms();
        }
    }else {
        List<Sms> lst = getAllSms();
    }

将app设置为默认短信app

    @Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 1) {
    if (resultCode == RESULT_OK) {

        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
            final String myPackageName = getPackageName();
            if (Telephony.Sms.getDefaultSmsPackage(mActivity).equals(myPackageName)) {

                List<Sms> lst = getAllSms();
            }
        }
    }
}
}

获取短信的功能

public List<Sms> getAllSms() {
    List<Sms> lstSms = new ArrayList<Sms>();
    Sms objSms = new Sms();
    Uri message = Uri.parse("content://sms/");
    ContentResolver cr = mActivity.getContentResolver();

    Cursor c = cr.query(message, null, null, null, null);
    mActivity.startManagingCursor(c);
    int totalSMS = c.getCount();

    if (c.moveToFirst()) {
        for (int i = 0; i < totalSMS; i++) {

            objSms = new Sms();
            objSms.setId(c.getString(c.getColumnIndexOrThrow("_id")));
            objSms.setAddress(c.getString(c
                    .getColumnIndexOrThrow("address")));
            objSms.setMsg(c.getString(c.getColumnIndexOrThrow("body")));
            objSms.setReadState(c.getString(c.getColumnIndex("read")));
            objSms.setTime(c.getString(c.getColumnIndexOrThrow("date")));
            if (c.getString(c.getColumnIndexOrThrow("type")).contains("1")) {
                objSms.setFolderName("inbox");
            } else {
                objSms.setFolderName("sent");
            }

            lstSms.add(objSms);
            c.moveToNext();
        }
    }
    // else {
    // throw new RuntimeException("You have no SMS");
    // }
    c.close();

    return lstSms;
}

短信类如下:

public class Sms{
private String _id;
private String _address;
private String _msg;
private String _readState; //"0" for have not read sms and "1" for have read sms
private String _time;
private String _folderName;

public String getId(){
return _id;
}
public String getAddress(){
return _address;
}
public String getMsg(){
return _msg;
}
public String getReadState(){
return _readState;
}
public String getTime(){
return _time;
}
public String getFolderName(){
return _folderName;
}


public void setId(String id){
_id = id;
}
public void setAddress(String address){
_address = address;
}
public void setMsg(String msg){
_msg = msg;
}
public void setReadState(String readState){
_readState = readState;
}
public void setTime(String time){
_time = time;
}
public void setFolderName(String folderName){
_folderName = folderName;
}

}

不要忘记在AndroidManifest.xml中定义权限

<uses-permission android:name="android.permission.READ_SMS" />

目前已有多种答案,但我认为所有答案都忽略了这个问题的一个重要部分。 在从内部数据库或其表中读取数据之前,我们必须了解数据是如何存储在其中的,只有这样我们才能找到上述问题的解决方案:

如何在Android系统下以编程方式从设备上读取短信?

在android中,短信表是这样的

现在您可以从数据库中选择您想要的任何内容。在我们的例子中,我们只需要

身份,地址和正文

阅读短信时:

1.请求许可

int REQUEST_PHONE_CALL = 1;

   if (ContextCompat.checkSelfPermission(MainActivity.this, Manifest.permission.READ_SMS) != PackageManager.PERMISSION_GRANTED) {
            ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_SMS}, REQUEST_PHONE_CALL);
        }

or

 <uses-permission android:name="android.permission.READ_SMS" />

2.现在你的代码是这样的

// Create Inbox box URI
Uri inboxURI = Uri.parse("content://sms/inbox");

// List required columns
String[] reqCols = new String[]{"_id", "address", "body"};

// Get Content Resolver object, which will deal with Content Provider
ContentResolver cr = getContentResolver();

// Fetch Inbox SMS Message from Built-in Content Provider
Cursor c = cr.query(inboxURI, reqCols, null, null, null);

// Attached Cursor with adapter and display in listview
adapter = new SimpleCursorAdapter(this, R.layout.a1_row, c,
        new String[]{"body", "address"}, new int[]{
        R.id.A1_txt_Msg, R.id.A1_txt_Number});
lst.setAdapter(adapter);

我希望这对你有所帮助。 谢谢。

String WHERE_CONDITION = unreadOnly ? SMS_READ_COLUMN + " = 0" : null;

改变了:

String WHERE_CONDITION = unreadOnly ? SMS_READ_COLUMN + " = 0 " : SMS_READ_COLUMN + " = 1 ";