在讨论了一些最重要的答案之后，我编写了另一个实现，它也可以处理一些边缘情况

function serialize(params, prefix) {                
    return Object.entries(params).reduce((acc, [key, value]) => {
        // remove whitespace from both sides of the key before encoding
        key = encodeURIComponent(key.trim());

        if (params.constructor === Array ) {
          key = `${prefix}[]`;
        } else if (params.constructor === Object) {
          key = (prefix ? `${prefix}[${key}]` : key);
        }

        /**
         *  - undefined and NaN values will be skipped automatically
         *  - value will be empty string for functions and null
         *  - nested arrays will be flattened
         */
        if (value === null || typeof value === 'function') {
            acc.push(`${key}=`);
        } else if (typeof value === 'object') {
            acc = acc.concat(serialize(value, key));
        } else if(['number', 'boolean', 'string'].includes(typeof value) && value === value) { // self-check to avoid NaN
            acc.push(`${key}=${encodeURIComponent(value)}`);
        }

        return acc;
    }, []);
}

function objectToQueryString(queryParameters) {
    return queryParameters ? serialize(queryParameters).join('&'): '';
}

let x = objectToQueryString({
    foo: 'hello world',
    bar: {
      blah: 123,
      list: [1, 2, 3],
        'nested array': [[4,5],[6,7]] // will be flattened
    },
    page: 1,
    limit: undefined, // field will be ignored
    check: false,
    max: NaN, // field will be ignored
    prop: null,
    ' key value': 'with spaces' // space in key will be trimmed out
});
  
console.log(x); // foo=hello%20world&bar[blah]=123&bar[list][]=1&bar[list][]=2&bar[list][]=3&bar[nested%20array][][]=4&bar[nested%20array][][]=5&bar[nested%20array][][]=6&bar[nested%20array][][]=7&page=1&check=false&prop=&key%20value=with%20spaces

还有一个很受欢迎的图书馆，qs。您可以通过以下方式添加:

yarn add qs

然后像这样使用它:

import qs from 'qs'

const array = { a: { b: 'c' } }
const stringified = qs.stringify(array, { encode: false })

console.log(stringified) //-- outputs a[b]=c

我有一个更简单的解决方案，它不使用任何第三方库，并且已经易于在任何具有“Object”的浏览器中使用。键”(也就是所有现代浏览器+ edge + ie):

In ES5

function(a){
    if( typeof(a) !== 'object' ) 
        return '';
    return `?${Object.keys(a).map(k=>`${k}=${a[k]}`).join('&')}`;
}

在胡

function(a){
    if( typeof(a) !== 'object' ) 
        return '';
    return '?' + Object.keys(a).map(function(k){ return k + '=' + a[k] }).join('&');
}

另一种方法(没有递归对象):

   getQueryString = function(obj)
   {
      result = "";

      for(param in obj)
         result += ( encodeURIComponent(param) + '=' + encodeURIComponent(obj[param]) + '&' );

      if(result) //it's not empty string when at least one key/value pair was added. In such case we need to remove the last '&' char
         result = result.substr(0, result.length - 1); //If length is zero or negative, substr returns an empty string [ref. http://msdn.microsoft.com/en-us/library/0esxc5wy(v=VS.85).aspx]

      return result;
   }

alert( getQueryString({foo: "hi there", bar: 123, quux: 2 }) );

ES6解决方案用于JavaScript对象的查询字符串编码

const params = {
  a: 1,
  b: 'query stringify',
  c: null,
  d: undefined,
  f: '',
  g: { foo: 1, bar: 2 },
  h: ['Winterfell', 'Westeros', 'Braavos'],
  i: { first: { second: { third: 3 }}}
}

static toQueryString(params = {}, prefix) {
  const query = Object.keys(params).map((k) => {
    let key = k;
    const value = params[key];

    if (!value && (value === null || value === undefined || isNaN(value))) {
      value = '';
    }

    switch (params.constructor) {
      case Array:
        key = `${prefix}[]`;
        break;
      case Object:
        key = (prefix ? `${prefix}[${key}]` : key);
        break;
    }

    if (typeof value === 'object') {
      return this.toQueryString(value, key); // for nested objects
    }

    return `${key}=${encodeURIComponent(value)}`;
  });

  return query.join('&');
}

toQueryString (params)

"a=1&b=query%20stringify&c=&d=&f=&g[foo]=1&g[bar]=2&h[]=Winterfell&h[]=Westeros&h[]=Braavos&i[first][second][third]=3"

const querystring=  {};

querystring.stringify = function (obj, sep = '&', eq = '=') {
  const escape = encodeURIComponent;
  const qs = [];
  let key = null;

  for (key in obj) if (obj.hasOwnProperty(key)) {
    qs.push(escape(key) + eq + escape(String(obj[key])));
  }
  return qs.join(sep);
};

例子:

const a  = querystring.stringify({a: 'all of them', b: true});
console.log(a);  // Output: a=all%20of%20them&b=true