是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
当前回答
ES6解决方案用于JavaScript对象的查询字符串编码
const params = {
a: 1,
b: 'query stringify',
c: null,
d: undefined,
f: '',
g: { foo: 1, bar: 2 },
h: ['Winterfell', 'Westeros', 'Braavos'],
i: { first: { second: { third: 3 }}}
}
static toQueryString(params = {}, prefix) {
const query = Object.keys(params).map((k) => {
let key = k;
const value = params[key];
if (!value && (value === null || value === undefined || isNaN(value))) {
value = '';
}
switch (params.constructor) {
case Array:
key = `${prefix}[]`;
break;
case Object:
key = (prefix ? `${prefix}[${key}]` : key);
break;
}
if (typeof value === 'object') {
return this.toQueryString(value, key); // for nested objects
}
return `${key}=${encodeURIComponent(value)}`;
});
return query.join('&');
}
toQueryString (params)
"a=1&b=query%20stringify&c=&d=&f=&g[foo]=1&g[bar]=2&h[]=Winterfell&h[]=Westeros&h[]=Braavos&i[first][second][third]=3"
其他回答
下面是Object.entries的简洁递归版本。它处理任意嵌套的数组,但不处理嵌套的对象。它还会删除空元素:
const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''
const to_qs = (obj) => {
return [].concat(...Object.entries(obj)
.map(([k,v]) => Array.isArray(v)
? v.map(arr => to_qs({[k]:arr}))
: format(k,v)))
.filter(x => x)
.join('&');
}
例如:
let json = {
a: [1, 2, 3],
b: [], // omit b
c: 1,
d: "test&encoding", // uriencode
e: [[4,5],[6,7]], // flatten this
f: null, // omit nulls
g: 0
};
let qs = to_qs(json)
=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"
PHP符号的TypeScript版本(没有URL转义版本)
/**
* Converts an object into a Cookie-like string.
* @param toSerialize object or array to be serialized
* @param prefix used in deep objects to describe the final query parameter
* @returns ampersand separated key=value pairs
*
* Example:
* ```js
* serialize({hello:[{world: "nice"}]}); // outputs "hello[0][world]=nice"
* ```
* ---
* Adapted to TS from a StackOverflow answer https://stackoverflow.com/a/1714899/4537906
*/
const serialize = (toSerialize: unknown = {}, prefix?: string) => {
const keyValuePairs = [];
Object.keys(toSerialize).forEach((attribute) => {
if (Object.prototype.hasOwnProperty.call(toSerialize, attribute)) {
const key = prefix ? `${prefix}[${attribute}]` : attribute;
const value = toSerialize[attribute];
const toBePushed =
value !== null && typeof value === "object"
? serialize(value, key)
: `${key}=${value}`;
keyValuePairs.push(toBePushed);
}
});
return keyValuePairs.join("&");
};
还有一个很受欢迎的图书馆,qs。您可以通过以下方式添加:
yarn add qs
然后像这样使用它:
import qs from 'qs'
const array = { a: { b: 'c' } }
const stringified = qs.stringify(array, { encode: false })
console.log(stringified) //-- outputs a[b]=c
我为此写了一个包:object-query-string:)
它支持嵌套对象、数组、自定义编码函数等。它是轻量级的,不支持jquery。
// TypeScript
import { queryString } from 'object-query-string';
// Node.js
const { queryString } = require("object-query-string");
const query = queryString({
filter: {
brands: ["Audi"],
models: ["A4", "A6", "A8"],
accidentFree: true
},
sort: 'mileage'
});
返回
filter[brands][]=Audi&filter[models][]=A4&filter[models][]=A6&filter[models][]=A8&filter[accidentFree]=true&sort=milage
好吧,似乎每个人都把他的俏皮话写在这里,所以我的是:
const encoded = Object.entries(obj).map(([k, v]) => `${k}=${encodeURIComponent(v)}`).join("&");