是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
当前回答
ES6解决方案用于JavaScript对象的查询字符串编码
const params = {
a: 1,
b: 'query stringify',
c: null,
d: undefined,
f: '',
g: { foo: 1, bar: 2 },
h: ['Winterfell', 'Westeros', 'Braavos'],
i: { first: { second: { third: 3 }}}
}
static toQueryString(params = {}, prefix) {
const query = Object.keys(params).map((k) => {
let key = k;
const value = params[key];
if (!value && (value === null || value === undefined || isNaN(value))) {
value = '';
}
switch (params.constructor) {
case Array:
key = `${prefix}[]`;
break;
case Object:
key = (prefix ? `${prefix}[${key}]` : key);
break;
}
if (typeof value === 'object') {
return this.toQueryString(value, key); // for nested objects
}
return `${key}=${encodeURIComponent(value)}`;
});
return query.join('&');
}
toQueryString (params)
"a=1&b=query%20stringify&c=&d=&f=&g[foo]=1&g[bar]=2&h[]=Winterfell&h[]=Westeros&h[]=Braavos&i[first][second][third]=3"
其他回答
只需使用以下方法:
encodeURIComponent(JSON.stringify(obj))
// elastic search example let story ={ "query": { "bool": { "must": [ { "term": { "revision.published": 0, } }, { "term": { "credits.properties.by.properties.name": "Michael Guild" } }, { "nested": { "path": "taxonomy.sections", "query": { "bool": { "must": [ { "term": { "taxonomy.sections._id": "/science" } }, { "term": { "taxonomy.sections._website": "staging" } } ] } } } } ] } } } const whateva = encodeURIComponent(JSON.stringify(story)) console.log(whateva)
这是一个开箱即用的。net后端解决方案。我已经采取了这个线程的主要答案,并更新它以适应我们的。net需求。
function objectToQuerystring(params) {
var result = '';
function convertJsonToQueryString(data, progress, name) {
name = name || '';
progress = progress || '';
if (typeof data === 'object') {
Object.keys(data).forEach(function (key) {
var value = data[key];
if (name == '') {
convertJsonToQueryString(value, progress, key);
} else {
if (isNaN(parseInt(key))) {
convertJsonToQueryString(value, progress, name + '.' + key);
} else {
convertJsonToQueryString(value, progress, name + '[' + key+ ']');
}
}
})
} else {
result = result ? result.concat('&') : result.concat('?');
result = result.concat(`${name}=${data}`);
}
}
convertJsonToQueryString(params);
return result;
}
另一种方法(没有递归对象):
getQueryString = function(obj)
{
result = "";
for(param in obj)
result += ( encodeURIComponent(param) + '=' + encodeURIComponent(obj[param]) + '&' );
if(result) //it's not empty string when at least one key/value pair was added. In such case we need to remove the last '&' char
result = result.substr(0, result.length - 1); //If length is zero or negative, substr returns an empty string [ref. http://msdn.microsoft.com/en-us/library/0esxc5wy(v=VS.85).aspx]
return result;
}
alert( getQueryString({foo: "hi there", bar: 123, quux: 2 }) );
使用Node.js v6.6.3
const querystring = require('querystring')
const obj = {
foo: 'bar',
baz: 'tor'
}
let result = querystring.stringify(obj)
// foo=bar&baz=tor
参考:查询字符串
好吧,似乎每个人都把他的俏皮话写在这里,所以我的是:
const encoded = Object.entries(obj).map(([k, v]) => `${k}=${encodeURIComponent(v)}`).join("&");