是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?

没有jQuery,没有其他框架-只有纯JavaScript:)


当前回答

这是对已接受的解的补充。这适用于对象和对象数组:

parseJsonAsQueryString = function (obj, prefix, objName) {
    var str = [];
    for (var p in obj) {
        if (obj.hasOwnProperty(p)) {
            var v = obj[p];
            if (typeof v == "object") {
                var k = (objName ? objName + '.' : '') + (prefix ? prefix + "[" + p + "]" : p);
                str.push(parseJsonAsQueryString(v, k));
            } else {
                var k = (objName ? objName + '.' : '') + (prefix ? prefix + '.' + p : p);
                str.push(encodeURIComponent(k) + "=" + encodeURIComponent(v));
                //str.push(k + "=" + v);
            }
        }
    }
    return str.join("&");
}

我还添加了objName,如果你使用对象参数,像在ASP。NET MVC动作方法。

其他回答

const serialize = obj => Object.keys(obj).reduce((a, b) =>
    a.push(encodeURIComponent(b) + "=" + encodeURIComponent(obj[b])) && a,
    []).join("&");

电话:

console.log(serialize({a:1,b:2}));
// output: 'a=1&b=2

'

我对JSON stringfier进行了比较,结果如下:

JSON:    {"_id":"5973782bdb9a930533b05cb2","isActive":true,"balance":"$1,446.35","age":32,"name":"Logan Keller","email":"logankeller@artiq.com","phone":"+1 (952) 533-2258","friends":[{"id":0,"name":"Colon Salazar"},{"id":1,"name":"French Mcneil"},{"id":2,"name":"Carol Martin"}],"favoriteFruit":"banana"}
Rison:   (_id:'5973782bdb9a930533b05cb2',age:32,balance:'$1,446.35',email:'logankeller@artiq.com',favoriteFruit:banana,friends:!((id:0,name:'Colon Salazar'),(id:1,name:'French Mcneil'),(id:2,name:'Carol Martin')),isActive:!t,name:'Logan Keller',phone:'+1 (952) 533-2258')
O-Rison: _id:'5973782bdb9a930533b05cb2',age:32,balance:'$1,446.35',email:'logankeller@artiq.com',favoriteFruit:banana,friends:!((id:0,name:'Colon Salazar'),(id:1,name:'French Mcneil'),(id:2,name:'Carol Martin')),isActive:!t,name:'Logan Keller',phone:'+1 (952) 533-2258'
JSURL:   ~(_id~'5973782bdb9a930533b05cb2~isActive~true~balance~'!1*2c446.35~age~32~name~'Logan*20Keller~email~'logankeller*40artiq.com~phone~'*2b1*20*28952*29*20533-2258~friends~(~(id~0~name~'Colon*20Salazar)~(id~1~name~'French*20Mcneil)~(id~2~name~'Carol*20Martin))~favoriteFruit~'banana)
QS:      _id=5973782bdb9a930533b05cb2&isActive=true&balance=$1,446.35&age=32&name=Logan Keller&email=logankeller@artiq.com&phone=+1 (952) 533-2258&friends[0][id]=0&friends[0][name]=Colon Salazar&friends[1][id]=1&friends[1][name]=French Mcneil&friends[2][id]=2&friends[2][name]=Carol Martin&favoriteFruit=banana
URLON:   $_id=5973782bdb9a930533b05cb2&isActive:true&balance=$1,446.35&age:32&name=Logan%20Keller&email=logankeller@artiq.com&phone=+1%20(952)%20533-2258&friends@$id:0&name=Colon%20Salazar;&$id:1&name=French%20Mcneil;&$id:2&name=Carol%20Martin;;&favoriteFruit=banana
QS-JSON: isActive=true&balance=%241%2C446.35&age=32&name=Logan+Keller&email=logankeller%40artiq.com&phone=%2B1+(952)+533-2258&friends(0).id=0&friends(0).name=Colon+Salazar&friends(1).id=1&friends(1).name=French+Mcneil&friends(2).id=2&friends(2).name=Carol+Martin&favoriteFruit=banana

其中最短的是URL对象表示法。

如果有很多嵌套对象,前面的答案就不起作用了。

相反,你可以从jquery-param/jquery-param.js中选择函数参数。这对我来说非常有效!

    var param = function (a) {
    var s = [], rbracket = /\[\]$/,
        isArray = function (obj) {
            return Object.prototype.toString.call(obj) === '[object Array]';
        }, add = function (k, v) {
            v = typeof v === 'function' ? v() : v === null ? '' : v === undefined ? '' : v;
            s[s.length] = encodeURIComponent(k) + '=' + encodeURIComponent(v);
        }, buildParams = function (prefix, obj) {
            var i, len, key;

            if (prefix) {
                if (isArray(obj)) {
                    for (i = 0, len = obj.length; i < len; i++) {
                        if (rbracket.test(prefix)) {
                            add(prefix, obj[i]);
                        } else {
                            buildParams(prefix + '[' + (typeof obj[i] === 'object' ? i : '') + ']', obj[i]);
                        }
                    }
                } else if (obj && String(obj) === '[object Object]') {
                    for (key in obj) {
                        buildParams(prefix + '[' + key + ']', obj[key]);
                    }
                } else {
                    add(prefix, obj);
                }
            } else if (isArray(obj)) {
                for (i = 0, len = obj.length; i < len; i++) {
                    add(obj[i].name, obj[i].value);
                }
            } else {
                for (key in obj) {
                    buildParams(key, obj[key]);
                }
            }
            return s;
        };

    return buildParams('', a).join('&').replace(/%20/g, '+');
};
 let data = {
    id:1,
    name:'Newuser'
    };
const getqueryParam = data => {
  let datasize = Object.keys(data).length;
  let initial = '?';

  Object.keys(data).map(function (key, index) {
    initial = initial.concat(`${key}=${data[key]}`);
    index != datasize - 1 && (initial = initial.concat('&'));
  });
  console.log(initial, 'MyqueryString');
  return initial;
};

console.log(getqueryParam(data))//You can get the query string here

If you have baseUrl means to get full query use 

baseUrl concat (getqueryParam(数据)。

这里有一个简单的答案,在转换过程中同时处理字符串和数组。

jsonToQueryString: function (data) {
        return Object.keys(data).map((key) => {
            if (Array.isArray(data[key])) {
                return (`${encodeURIComponent(key)}=${data[key].map((item) => encodeURIComponent(item)).join('%2C')}`);
            }
            return(`${encodeURIComponent(key)}=${encodeURIComponent(data[key])}`);
        }).join('&');
    }