jQuery有一个函数jQuery.param()。如果你已经在使用它，你可以使用这个:

例子:

var params = { width:1680, height:1050 };
var str = jQuery.param( params );

STR现在包含宽度=1680&高度=1050。

 let data = {
    id:1,
    name:'Newuser'
    };
const getqueryParam = data => {
  let datasize = Object.keys(data).length;
  let initial = '?';

  Object.keys(data).map(function (key, index) {
    initial = initial.concat(`${key}=${data[key]}`);
    index != datasize - 1 && (initial = initial.concat('&'));
  });
  console.log(initial, 'MyqueryString');
  return initial;
};

console.log(getqueryParam(data))//You can get the query string here

If you have baseUrl means to get full query use 

baseUrl concat (getqueryParam(数据)。

还有一个很受欢迎的图书馆，qs。您可以通过以下方式添加:

yarn add qs

然后像这样使用它:

import qs from 'qs'

const array = { a: { b: 'c' } }
const stringified = qs.stringify(array, { encode: false })

console.log(stringified) //-- outputs a[b]=c

ES6解决方案用于JavaScript对象的查询字符串编码

const params = {
  a: 1,
  b: 'query stringify',
  c: null,
  d: undefined,
  f: '',
  g: { foo: 1, bar: 2 },
  h: ['Winterfell', 'Westeros', 'Braavos'],
  i: { first: { second: { third: 3 }}}
}

static toQueryString(params = {}, prefix) {
  const query = Object.keys(params).map((k) => {
    let key = k;
    const value = params[key];

    if (!value && (value === null || value === undefined || isNaN(value))) {
      value = '';
    }

    switch (params.constructor) {
      case Array:
        key = `${prefix}[]`;
        break;
      case Object:
        key = (prefix ? `${prefix}[${key}]` : key);
        break;
    }

    if (typeof value === 'object') {
      return this.toQueryString(value, key); // for nested objects
    }

    return `${key}=${encodeURIComponent(value)}`;
  });

  return query.join('&');
}

toQueryString (params)

"a=1&b=query%20stringify&c=&d=&f=&g[foo]=1&g[bar]=2&h[]=Winterfell&h[]=Westeros&h[]=Braavos&i[first][second][third]=3"

只需使用以下方法:

encodeURIComponent(JSON.stringify(obj))

// elastic search example let story ={ "query": { "bool": { "must": [ { "term": { "revision.published": 0, } }, { "term": { "credits.properties.by.properties.name": "Michael Guild" } }, { "nested": { "path": "taxonomy.sections", "query": { "bool": { "must": [ { "term": { "taxonomy.sections._id": "/science" } }, { "term": { "taxonomy.sections._website": "staging" } } ] } } } } ] } } } const whateva = encodeURIComponent(JSON.stringify(story)) console.log(whateva)

Use:

const objectToQueryParams = (o = {}) =>
  Object.entries(o)
    .map((p) => `${encodeURIComponent(p[0])}=${encodeURIComponent(p[1])}`)
    .join("&");

参考以下要点了解更多信息: https://gist.github.com/bhaireshm