dispatch_after函数在给定时间后将块对象分派到分派队列。使用下面的代码在2.0秒后执行一些UI相关的任务。

            let delay = 2.0
            let delayInNanoSeconds = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
            let mainQueue = dispatch_get_main_queue()

            dispatch_after(delayInNanoSeconds, mainQueue, {

                print("Some UI related task after delay")
            })

在swift 3.0中:

            let dispatchTime: DispatchTime = DispatchTime.now() + Double(Int64(2.0 * Double(NSEC_PER_SEC))) / Double(NSEC_PER_SEC)
            DispatchQueue.main.asyncAfter(deadline: dispatchTime, execute: {

          })

根据Jaime Cham的回答，我创建了一个NSObject+Blocks类别，如下所示。我觉得这些方法更好地匹配现有的performSelector: NSObject方法

NSObject + Blocks.h

#import <Foundation/Foundation.h>

@interface NSObject (Blocks)

- (void)performBlock:(void (^)())block afterDelay:(NSTimeInterval)delay;

@end

NSObject + Blocks.m

#import "NSObject+Blocks.h"

@implementation NSObject (Blocks)

- (void)performBlock:(void (^)())block
{
    block();
}

- (void)performBlock:(void (^)())block afterDelay:(NSTimeInterval)delay
{
    void (^block_)() = [block copy]; // autorelease this if you're not using ARC
    [self performSelector:@selector(performBlock:) withObject:block_ afterDelay:delay];
}

@end

并像这样使用:

[anyObject performBlock:^{
    [anotherObject doYourThings:stuff];
} afterDelay:0.15];

以下是在Swift中延迟后触发阻塞的方法:

runThisAfterDelay(seconds: 2) { () -> () in
    print("Prints this 2 seconds later in main queue")
}

/// EZSwiftExtensions
func runThisAfterDelay(seconds seconds: Double, after: () -> ()) {
    let time = dispatch_time(DISPATCH_TIME_NOW, Int64(seconds * Double(NSEC_PER_SEC)))
    dispatch_after(time, dispatch_get_main_queue(), after)
}

它包括作为一个标准函数在我的回购。

dispatch_after函数在给定时间后将块对象分派到分派队列。使用下面的代码在2.0秒后执行一些UI相关的任务。

            let delay = 2.0
            let delayInNanoSeconds = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
            let mainQueue = dispatch_get_main_queue()

            dispatch_after(delayInNanoSeconds, mainQueue, {

                print("Some UI related task after delay")
            })

在swift 3.0中:

            let dispatchTime: DispatchTime = DispatchTime.now() + Double(Int64(2.0 * Double(NSEC_PER_SEC))) / Double(NSEC_PER_SEC)
            DispatchQueue.main.asyncAfter(deadline: dispatchTime, execute: {

          })

按Cmd + Shift + L显示Xcode内置代码片段库:

寻找分派之后，然后，只需拖放到您的代码。

下面是Swift 3在延迟后排队工作的方法。

DispatchQueue.main.asyncAfter(
  DispatchTime.now() + DispatchTimeInterval.seconds(2)) {
    // do work
}