是否有一种方法可以在延迟后用一个基本参数调用块,就像使用performSelector:withObject:afterDelay:但是使用int/double/float这样的参数?


当前回答

这里是我的2美分= 5个方法;)

我喜欢封装这些细节,让AppCode告诉我如何完成我的句子。

void dispatch_after_delay(float delayInSeconds, dispatch_queue_t queue, dispatch_block_t block) {
    dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
    dispatch_after(popTime, queue, block);
}

void dispatch_after_delay_on_main_queue(float delayInSeconds, dispatch_block_t block) {
    dispatch_queue_t queue = dispatch_get_main_queue();
    dispatch_after_delay(delayInSeconds, queue, block);
}

void dispatch_async_on_high_priority_queue(dispatch_block_t block) {
    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_HIGH, 0), block);
}

void dispatch_async_on_background_queue(dispatch_block_t block) {
    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_BACKGROUND, 0), block);
}

void dispatch_async_on_main_queue(dispatch_block_t block) {
    dispatch_async(dispatch_get_main_queue(), block);
}

其他回答

也许比通过GCD更简单,在某个班级(例如。"Util"),或对象上的类别:

+ (void)runBlock:(void (^)())block
{
    block();
}
+ (void)runAfterDelay:(CGFloat)delay block:(void (^)())block 
{
    void (^block_)() = [[block copy] autorelease];
    [self performSelector:@selector(runBlock:) withObject:block_ afterDelay:delay];
}

所以要使用:

[Util runAfterDelay:2 block:^{
    NSLog(@"two seconds later!");
}];

下面是Swift 3在延迟后排队工作的方法。

DispatchQueue.main.asyncAfter(
  DispatchTime.now() + DispatchTimeInterval.seconds(2)) {
    // do work
}

您可以使用dispatch_after稍后调用一个块。在Xcode中,开始输入dispatch_after并按Enter键自动完成如下内容:

下面是一个使用两个浮点数作为“参数”的示例。你不需要依赖任何类型的宏,代码的意图是非常清楚的:

斯威夫特3,斯威夫特4

let time1 = 8.23
let time2 = 3.42

// Delay 2 seconds
DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) {
    print("Sum of times: \(time1 + time2)")
}

斯威夫特2

let time1 = 8.23
let time2 = 3.42

// Delay 2 seconds
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, Int64(2.0 * Double(NSEC_PER_SEC))), dispatch_get_main_queue()) { () -> Void in
        println("Sum of times: \(time1 + time2)")
}

Objective - C

CGFloat time1 = 3.49;
CGFloat time2 = 8.13;

// Delay 2 seconds
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(2.0 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
    CGFloat newTime = time1 + time2;
    NSLog(@"New time: %f", newTime);
});

对于Swift,我已经创建了一个全局函数,没什么特别的,使用dispatch_after方法。我更喜欢这个,因为它易于阅读和使用:

func performBlock(block:() -> Void, afterDelay delay:NSTimeInterval){
    dispatch_after(dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC))), dispatch_get_main_queue(), block)
}

你可以这样使用:

performBlock({ () -> Void in
    // Perform actions
}, afterDelay: 0.3)

我相信作者不是在问如何等待一个分数时间(延迟),而是如何传递一个标量作为参数的选择器(withObject:)和现代objective C中最快的方法是:

[obj performSelector:...  withObject:@(0.123123123) afterDelay:10]

你的选择器必须改变它的参数为NSNumber,并使用floatValue或doubleValue这样的选择器检索值