允许一行代码小数点

    private void txtQty_KeyPress(object sender, KeyPressEventArgs e)
    {
        e.Handled =  e.KeyChar != '.' && !char.IsDigit(e.KeyChar) && !char.IsControl(e.KeyChar);
    }

整数和浮点数都需要被接受，包括负数。

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    // Text
    string text = ((Control) sender).Text;

    // Is Negative Number?
    if (e.KeyChar == '-' && text.Length == 0)
    {
        e.Handled = false;
        return;
    }

    // Is Float Number?
    if (e.KeyChar == '.' && text.Length > 0 && !text.Contains("."))
    {
        e.Handled = false;
        return;
    }

    // Is Digit?
    e.Handled = (!char.IsDigit(e.KeyChar) && !char.IsControl(e.KeyChar));
}

我喜欢简洁的代码

    private void xmm_textbox_KeyPress(object sender, KeyPressEventArgs e) {
        double x;
        e.Handled = !double.TryParse(((TextBox)sender).Text, out x);
    }

我已经为各种验证创建了一个可重用的文本框扩展类，并考虑共享它。

您所需要做的就是引发一个TextChange事件，然后调用Validate方法。它是这样的:

private void tbxAmount_TextChanged(object sender, EventArgs e)
{ 
    tbxAmount.Validate(TextValidator.ValidationType.Amount);
}

下面是扩展类:

public static class TextValidator
{
    public enum ValidationType
    {
        Amount,
        Integer
    }

    /// <summary>
    /// Validate a textbox on text change.
    /// </summary>
    /// <param name="tbx"></param>
    /// <param name="validationType"></param>
    public static void Validate(this TextBox tbx, ValidationType validationType)
    {
        PerformValidation(tbx, validationType);
        tbx.Select(tbx.Text.Length, 0);
    }


    private static void PerformValidation(this TextBox tbx, ValidationType validationType)
    {
        char[] enteredString = tbx.Text.ToCharArray();
        switch (validationType)
        {
            case ValidationType.Amount:
                tbx.Text = AmountValidation(enteredString);
                break;

            case ValidationType.Integer:
                tbx.Text = IntegerValidation(enteredString);
                break;

            default:
                break;
        }

        tbx.SelectionStart = tbx.Text.Length;
    }



    private static string AmountValidation(char[] enteredString)
    {
        string actualString = string.Empty;
        int count = 0;
        foreach (char c in enteredString.AsEnumerable())
        {
            if (count >= 1 && c == '.')
            { actualString.Replace(c, ' '); actualString.Trim(); }
            else
            {
                if (Char.IsDigit(c))
                {
                    actualString = actualString + c;
                }

                if (c == '.')
                {
                    actualString = actualString + c; count++;
                }

                else
                {
                    actualString.Replace(c, ' ');
                    actualString.Trim();
                }
            }
        }
        return actualString;
    }


    private static string IntegerValidation(char[] enteredString)
    {
        string actualString = string.Empty;
        foreach (char c in enteredString.AsEnumerable())
        {
            if (Char.IsDigit(c))
            {
                actualString = actualString + c;
            }
            else
            {
                actualString.Replace(c, ' ');
                actualString.Trim();
            }
        }
        return actualString;
    }
}

你可以在这里找到完整的代码

我也在寻找最好的方法来检查文本框中只有数字和键盘的问题是，它不支持通过右键单击或剪贴板复制粘贴，所以提出了这个代码，验证光标离开文本字段时，它也检查空字段。(newguy改编版)

private void txtFirstValue_MouseLeave(object sender, EventArgs e)
{
    int num;
    bool isNum = int.TryParse(txtFirstValue.Text.Trim(), out num);

    if (!isNum && txtFirstValue.Text != String.Empty)
    {
        MessageBox.Show("The First Value You Entered Is Not a Number, Please Try Again", "Invalid Value Detected", MessageBoxButtons.OK, MessageBoxIcon.Error);
        txtFirstValue.Clear();
    }
}

不要忘记用户可以在文本框中粘贴无效文本。

如果你想限制它，遵循下面的代码:

private void ultraTextEditor1_TextChanged(object sender, EventArgs e)
{
    string append="";
    foreach (char c in ultraTextEditor1.Text)
    {
        if ((!Char.IsNumber(c)) && (c != Convert.ToChar(Keys.Back)))
        {

        }
        else
        {
            append += c;
        }
    }

    ultraTextEditor1.Text = append;
}