数据类似乎是Java中老式pojo的替代品。这些类允许继承是可以预料的,但我看不出扩展数据类的方便方法。我需要的是这样的东西:
open data class Resource (var id: Long = 0, var location: String = "")
data class Book (var isbn: String) : Resource()
上面的代码失败是因为component1()方法的冲突。只在一个类中留下数据注释也不能完成这项工作。
也许还有另一种扩展数据类的习惯用法?
UPD:我可能只注释子子类,但数据注释只处理构造函数中声明的属性。也就是说,我必须声明所有的父属性是开放的,并重写它们,这是丑陋的:
open class Resource (open var id: Long = 0, open var location: String = "")
data class Book (
override var id: Long = 0,
override var location: String = "",
var isbn: String
) : Resource()
可以从非数据类继承数据类。
基类
open class BaseEntity (
@ColumnInfo(name = "name") var name: String? = null,
@ColumnInfo(name = "description") var description: String? = null,
// ...
)
子类
@Entity(tableName = "items", indices = [Index(value = ["item_id"])])
data class CustomEntity(
@PrimaryKey
@ColumnInfo(name = "id") var id: Long? = null,
@ColumnInfo(name = "item_id") var itemId: Long = 0,
@ColumnInfo(name = "item_color") var color: Int? = null
) : BaseEntity()
它工作。
可以从非数据类继承数据类。
基类
open class BaseEntity (
@ColumnInfo(name = "name") var name: String? = null,
@ColumnInfo(name = "description") var description: String? = null,
// ...
)
子类
@Entity(tableName = "items", indices = [Index(value = ["item_id"])])
data class CustomEntity(
@PrimaryKey
@ColumnInfo(name = "id") var id: Long? = null,
@ColumnInfo(name = "item_id") var itemId: Long = 0,
@ColumnInfo(name = "item_color") var color: Int? = null
) : BaseEntity()
它工作。